Two step equations
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first use the sin sum and difference formulas to re-write sin(x+pi/4) and sin(x-pi/4)
sin(A+B) = sin(A)cos(B) + cos(A)sin(B) sin(x+pi/4) = sin(x)cos(pi/4) + cos(x)sin(pi/4) try to apply the same kind of reasoning for sin(x-pi/4)
sin(x-pi/4) = sin(x)cos(pi/4) - cos(x)sin(pi/4)
awesome now putting this together we get sin(x)cos(pi/4) + cos(x)sin(pi/4) + sin(x)cos(pi/4) - cos(x)sin(pi/4) = 1 see anything you can simplify/cancel out?
+ cos(x)sin(pi/4)
sin(x)cos(pi/4) + sin(x)cos(pi/4) = 1
whoops made a mistake, should have been a minus sign sin(x)cos(pi/4) + cos(x)sin(pi/4) - [ sin(x)cos(pi/4) - cos(x)sin(pi/4) ] = 1 therefore 2cos(x)sin(pi/4) = 1 ^ try solving this for x
sqrt 2
first find what sin(pi/4) equals using the unit circle then solve for cos(x) then figure out what the value of x must be
sqrt 2 cos x =1
good, so cos(x) = 1/sqrt(2) = sqrt(2)/2 what values of x does this correspond to?
1/sqrt2
if cos(x) = sqrt(2)/2 what must x equal?
pi/4 and 7pi/4
awesome so x = pi/4 and 7pi/4 are your solutions
for B) sin(2x) = 2cos(x)sin(x) try to apply this to sin(x)cos(x) = sqrt(3)/2 to re-write the expression in terms of sin only
do i use the chart you provided
hint: try solving sin(2x) = 2cos(x)sin(x) for cos(x)sin(x) then re-write the original equation in terms of sin only
\[\sin(2x)=2\sin^2(x)\cos^2(x)\]
i think :/
if 2cos(x)sin(x) = sin(2x) then what does cos(x)sin(x) equal?
hint: divide both sides by 2.
cos(x)sin(x) = sin(x)
ugh had a brain fart
you cannot divide the 2x inside of the sin expression 2cos(x)sin(x) = sin(2x) dividing both sides by 2 gives us cos(x)sin(x) = (1/2)sin(2x) now go back to the original expression and substitute this inside to re-write the original expression in terms of sin only
sin(x)cos(x) = sqrt(3)/4 sin(x)cos(x) = (1/2)sin(2x) therefore: (1/2)sin(2x) = sqrt(3)/4 solve for x
multiply both sides of the equation by 2 to get sin(2x) = sqrt(3)/2 look on the unit circle where sinx = sqrt(3)/2 and then divide those solution(s) by 2 because it's sin(2x) not sinx
pi /6 and pi/3
good
for C) try factoring tan^2(x) - 3tan(x) + 2 = 0 if you are having trouble, try letting a = tan(x) and re-write the equation in terms of a
(tanx -2)(tanx-1) is what it should factor to, set that equal to 0 and solve for the appropriate tan values
x=1.11
x=pi/4
good but also x = 5pi/4 (that's where sin and cos both equal -sqrt(2)/2)
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