Question

What is each expression in simplest form? State any restrictions.

Answer 1

\[\frac{ 2x }{ 4x^2-2x }\]

Answer 2

Afternoon @EndersWorld. Hope you're doing well. How far have you gotten with solving this problem so far? What step are you currently stuck on?

Answer 3

I haven't started yet, just got home, been a stressful weekend, dad was put under arrest.

Answer 4

I know I have to factor \[4x^2-2x\]

Answer 5

Okay great. You know that much so what expression would you say is common to both terms?

Answer 6

2x

Answer 7

Which leaves \[2x-1\]?

Answer 8

That is correct. Factoring out \(2x\) from the expression in the denominator leaves \(2x - 1\) but you should write out your steps so that I know you are writing the complete correct answer correctly.

Answer 9

There is a certain correct form in which you must express each step in order to get full credit. Go ahead and post your steps here.

Answer 10

Im stuck

Answer 11

\[\frac{ 2x }{ 2x(2x-1) }\]

Answer 12

Okay great. Outstanding work. Now do you see anything that cancels top and bottom. You can always cancel factors of one at this point. It's better form as practice to re-write the factors of one as a separate fraction first before canceling.

Answer 13

\[\frac{ 2x }{ 2x } \cancel\]

Answer 14

I think that maybe you were trying to do this:
\(\dfrac{\cancel{2x}}{\cancel{2x}} \cdot\ \dfrac{1}{2x - 1}\)

Answer 15

ye

Answer 16

Here's the correct code for that:
`\(\dfrac{\cancel{2x}}{\cancel{2x}} \cdot\ \dfrac{1}{2x - 1}\)`

Answer 17

thx

Answer 18

You're welcome.

Answer 19

Is that it?

Answer 20

Well, you now have to express the very final step. Which is the resultant expression after cancellation. Once you've posted that, then we should be finished.

Answer 21

Im confused

Answer 22

Why?

Answer 23

What happens after you cancel factors of one?

Answer 24

Left with just \[2x\]?

Answer 25

Is that really true? What did you cancel and what was left after cancellation. Look again at the fraction you last posted.

Answer 26

the one from the top and the one from 2x-1

Answer 27

All you have to do is just express the fraction that remains after cancellation and then you will be done.

Answer 28

Im confused..

Answer 29

Starting here, if we remove the canceled fraction, what remains?

\(\dfrac{\cancel{2x}}{\cancel{2x}} \cdot\ \dfrac{1}{2x - 1}\)

Answer 30

2x?

Answer 31

Let's do it this way:

When we remove cancelled fraction\(\dfrac{\cancel{2x}}{\cancel{2x}}\), then the fraction\(\text{__________}\) remains.

Answer 32

Fill in the blank.

Answer 33

\[\frac{ 1 }{ 1 }\]

Answer 34

What about the other fraction?

Answer 35

Does that remain or do we get rid of it?

Answer 36

Remain

Answer 37

Let's go with what you wrote. When we cancel \(\dfrac{\cancel{2x}}{\cancel{2x}}\), we are left with
\(\dfrac{1}{1} \cdot\ \dfrac{1}{2x - 1}\) can we simplify this further? If yes, what can it be simplified to?