Ask your own question, for FREE!
Tutorials 8 Online
Moon:

MCAT Tutorial: Introduction to Electrochemistry

Moon:

MgujSMP.png

Moon:

\({\bf{Basic~Terminology:}}\) - electrochemical cell: chemical reaction in solution(s) that are linked with electrodes in electrolytes - galvanic cell: generates current - electrolytic cell: uses current - anode: the positive electrode, where oxidation takes place - cathode: the negative electrode, where reduction takes place - oxidation: chemical loses electrons [the charge goes up] - reduction: chemical gains electrons [the charge is reduced] Cell Notation: oxidation on the left, reduction on the right so for the rxns Zn(s) --> Zn(2+) + 2e- (losing electrons, thus oxidation) Cu(2+) + 2e- --> Cu(s) (gaining electrons, thus reduction) we can re-write this as Zn(s) | Zn^(2+) || Cu^(2+) | Cu(s) ions go in the middle, separated by the double bar to represent the salt bridge

Moon:

\({\bf{Formulas~to~Know:}}\) W= -nFE F = faraday's constant E = cell potential/voltage n = # of moles electrons applying this to Gibb's free energy we get ΔG = -nFE where ΔG > 0 indicates nonspontaneity and negative electric potential ΔG < 0 indicates spontenaity and positive electric potential Ecell = Ecathode - Eanode cell potential/voltage typically you will be given the reduction potentials, to obtain the oxidation potential simply multiply by (-1) **** important note: when adding reactions it is important to balance the # of electrons by multiplying the equations by an integer value BUT you do NOT multiply the electric potentials by that value Nernst Equation: Ecell = E° - RT/nF * [lnQ] E° is the standard potential, Ecell is the potential at the conditions being studied, R is the ideal gas constant (usu. 8.314 J/molK) if we are working with joules, T is temp. in Kelvin, n is # of moles, F is faraday's as usual, Q is the reaction quotient

Moon:

|dw:1526222115936:dw| basic structure of an electrochemical cell, notice the salt bridge to allow ions to flow, preventing charge from accumulating on one cell and stopping the flow of electrons

Moon:

Anyway, that's the end of my tutorial, I hope it was a helpful resource. Source material is the 2nd Edition Barron's Prep book for the new MCAT

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!