Question

Stumped

Answer 1

Oh, i suck at math, sorry!

Answer 2

But which one do you think it is?

Answer 3

What is this lesson called?

Answer 4

Angle measures and segment lengths.

Answer 5

I still don’t know how to help without giving the answer lmao

Answer 6

Well, how did you determine the answer?

Answer 7

Explain your steps. idek what to do :(

Answer 8

Do you at least know where to start?

Answer 9

Ah, I see

Answer 10

Nope our teacher was supposed to go over the lesson today but ended up not being able to and we still have to do the practice today :/ So I really don't get any of this. I have been able to figure out a few but none of them were anything like this

Answer 11

This is basically two secants and a tangent

Answer 12

Do you know the formula for that?

Answer 13

A secant and a tangent line?

Answer 14

um \[y-y1=f1(x1)(x-x1)\] is the only formula we were given/shown

Answer 15

Familiar?

Answer 16

a bit yeah

Answer 17

Which formula do you think we'll be using?

Answer 18

Tangent and secant?

Answer 19

Yes. Do you see why it would work for this problem?

Answer 20

Yeah.

Answer 21

So t in the formulas I gave you is x in this case, which is what we are solving for.

Answer 22

They give us the measurements for each secant, so we can effectively solve for it using either one.

Answer 23

\[x^2 = 4(4 + 16) \]
\[x^2 = 4(20) = 80 \]
\[x = \sqrt 80 = 8.9\]
\[x^2 = 8(8 + 2)\]
\[x^2 = 8(10) = 80\]
\[x = \sqrt 80 = 8.9\]

Answer 24

@lexxii does that make sense?

Answer 25

Yes thank you!

Answer 26

No problem, glad I could help.