The function g(n) = n2 − 20n + 95 represents a parabola. Part A: Rewrite the function in vertex form by completing the square. Show your work. (6 points) Part B: Determine the vertex and indicate whether it is a maximum or a minimum on the graph. How do you know? (2 points) Part C: Determine the axis of symmetry for g(n).
@Shadow
Did part A with dude yesterday but now need part B and C
I have to study for a quiz so I won’t be able to help you. Try tagging dude. I know there are easy websites that can help you find the vertex and axis of symmetry. I used them years ago. Also, a minimum just means the vertex is on the bottom, with the lines going up. Maximum means the vertex is the highest point, with the parabola going down.
g(n)= n^2-20n+95 Step 1: n^2 - 20n + 100 Step 2: (b over 2) ^2 So (-20 over 2) ^2=-10^2=100 Step 3: (n^2-20n=100)=95-100 Step 4: (n-10) (n-10)- 5 Step 5: (n-10)^2 - 5 Answer G(n)=(n-10)^2-5
@dude
Do you know what the vertex is?
yes
What is it?
hold on im pulling it up
(10,-5)
Mhm, and have you determined whether this is a minimum or a maximum?
I think its maximum because it goes from negative to positive
What do you mean from negative to positive
hold on imma show u what i have
^^if u look it goes down to up so that would make it maximum because it goes up to the positives
Maximum is when the vertex is the highest point. Does that seem to be the case?
Nu so it would be minimum because the vertex has negatives and it is not at its highest points
Think of it this way: Maximum: Parabola opens down Minimum: Parabola opens up
Ohhhh so Its minimum because the vertext is not at its highest points and becuase the parabola opens up
Yes
*because
And it since it's the lowest point.
how do we know? i know because if the vertex is in the negatives it means its at its lowest points so that would make the parabola open
A vertex can be in the negative and still be a maximum. |dw:1526590701385:dw|
That's why you focus on these two qualifications: Opens up/Opens down Highest point/lowest point It's positioning of the vertex in terms of pos/neg doesn't matter.
so how would you explain how you know if a vertex could still be in negatives but still maximum
Because it's the highest point in the graph and the parabola opens down.
I know because its the lowest point in the graph and the parabola opens up
@dude can yew helps yeet
@dude e.e
Part C im on den one last question
In order to find axis of symmetry you have to use the this equation: \(\large -\frac{b}{2a}\) Remember: This equation is written as \(g(n)=ax^2+bx+c\)
i know so it would be (n-10) over -5?
cause the equation we finished yesterday is G(n)=(n-10)^2-5
Ah we're using the original equation for this one \(n^2 − 20n + 95\) As its written in standard form \(ax^2+bx+c\)
im confused now so we dont use our revised equation we use the original
We use the original
Its easier to solve for the vertex at least in my opinion
i have the vertex i need the axis symmetry
^^look up i already told shadow the vertex for part B
OHHHHHHHHH
Scratch what I just said, just look at the h value Hint: \(g(n)=a(x-h)+k\)
Umm ok.....
\(g(n)=(n-10)^2-5\) What is the h value?
10?
Right so x=10 is the axis of symmetry This may help https://www.desmos.com/calculator/s7k0gr4pee
what? u just what IM SOOO CONFUSED how did it go from 10 being h to 10 being x
The rule for axis of symmetry: \(x=h\) \(g(n)=(x-h)+k\) The value of x for the line of symmetry is equal to the value of h on the vertex form for an equation
so Part C: The Axis equals 10.
The axis of symmetry is when x=10, yes
Ok are you ready to finish da last question
give me a few mins, ill be right there. Post it though
ok
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