Anotha one DDDDJJJJjjjjjj KHAAALID Another graphing question
@GraphitePencil
He came ;o
Lemme try dis first
Okay, but ... there is a much easier way than you're probably about to try.
Not gonna say. But erase it.
Okay now what
o.O
Whoops, actually, you didn't have that point correct either.
Fudge
All just ask you two questions: What is y when x is 0? Then what is x when y is -5?
Math lovers and experts hate me. My math teacher literally said I am terrible at math yet I have an A- somehow
When x is 0, y is 1/3?
No lol wait
When x is 0, y is -5 and when y is 0, x is 1/3
Eh? e.e
Actually, when x is 0 y is -5. So that gives (0,-5). We'll go with that. But then, what is y when x = 3?
y is 1?
\(y = \dfrac{x}{3} - 5\) We can re-write the equation this way. What is y when x = 3?
Done? Done :D
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Hero \(y = \dfrac{x}{3} - 5\) We can re-write the equation this way. What is y when x = 3? \(\color{#0cbb34}{\text{End of Quote}}\)
1
One to the right, 3 up?
No, don't do it that way. Insert 3 in place of x, then calculate on the right hand side.
It's not too late. Just do it on paper. Literally re-write the equation as I have written it above except in place of x, write 3. Then calculate the right hand side.
You should get something such as y = a number
Um y=3?
How did you get y = 3. Show me your steps.
I guessed cause you keep saying y is a number and you keep saying 3 e.e
You're not even doing what I asked you to do.
Bruh
How hard is it to write this: \(y = \dfrac{3}{3} - 5\)
Oh y is 1
I SAID THAT
And then realize that \(\dfrac{3}{3} = 1\) And then finish calculating: \(y = 1 - 5\) What's 1 - 5?
Don’t I have it pointed too? e.e
4
-4 actually y = -4
This is how I would think about it The equation is written as \(y=mx+b\) m is the slope which is \(\frac{1}{3}\) Slope can also be seen as \(\frac{rise}{run}\) rise is how many points you go up and run is how much you go to the right So we would go 1 up and 3 to the left \(\bf b\) is the y intercept or when x is 0 (Which is the point you have) Basically from that point you are just going up 1 box and right 3 boxes
Akdkosjsjajsksksja
So the other point is \((3, -4)\)
Math is so confusing :-:
It's much simpler to plug and play. So your points are \((0,-5)\) and \((3, -4)\)
Got it
Then after you plot those two points, draw a line through it NOT a line segment
Past it???
You drew a line segment rather than a line.
Okay through it c:
|dw:1526682083593:dw| Another way to look at it maybe it can help
I have dat Jay
Yep, @dude, that's great until you get something like \(y = \dfrac{100}{3}x + 20\)
Wuh
What are you going to do then? Go up 100?
Yes but I think she has to get used to the concept first before attempting to do something she doesn't understand |dw:1526682290366:dw|
There is no 100, it goes up to 6, Hero •-•
OH MY GOD THAT IS SO SATISFYING
I'm just saying, plugging in numbers isn't so difficult as I just showed.
Hero is right, I don't disagree but I think Allison is a visual learner
It works for any equation. The rise over run method has limited usage. It's better to work with universal methods. Methods that can work in any linear equation.
I am visual hehe. Kid brain.
There are many visual learners, being one doesn't mean you're a kid e.e
Anyway e.e Thank you Avocado c: Thank you JJ c:
Rip e.e
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