Marco can run 3 miles per hour faster than Polo. Marco ran 12 miles in the same time it took Polo to run 8 miles.
I need to fill in a table for Marco and Polo's Distance, Rate, and Time. Then determine their speed.
@Hero
\(\begin{array}{|c|c|c|c|} \hline &\text{Distance}&\text{Rate}&\text{Time}\\ \hline \text{Marco}&&&\\ \hline \text{Polo}&&&\\ \hline \text{Total}&&& \hline \end{array}\)
thats what it looks like on my paper
umm, so Marco is 12 and Polo is 8
Total is 20
So did they run the same time or different time?
it says for the different distances they ran the same time
Correct, they ran the same time so we'll let \(t\) represent the time for both runners: \(\begin{array}{|c|c|c|c|} \hline &\text{Distance}&\text{Rate}&\text{Time}\\ \hline \text{Marco}&12&&t\\ \hline \text{Polo}&8&&t\\ \hline \text{Total}&&& \hline \end{array}\)
Okay, so now all we have to do is figure out the rates for both. Who ran faster than whom?
Marco
uh, 3miles per hour faster than Polo
Good, so whatever Polo's speed is, Marco ran 3 miles per hour faster than that:
So if we let \(r\) represent Polo's speed, how can we show that Marco ran three miles per hour faster than that? \(\begin{array}{|c|c|c|c|} \hline &\text{Distance}&\text{Rate}&\text{Time}\\ \hline \text{Marco}&12&&t\\ \hline \text{Polo}&8&r&t\\ \hline \text{Total}&&& \hline \end{array}\)
r + 3?
Correct: \(\color{#0cbb34}{\text{Originally Posted by}}\) @Hero So if we let \(r\) represent Polo's speed, how can we show that Marco ran three miles per hour faster than that? \(\begin{array}{|c|c|c|c|} \hline &\text{Distance}&\text{Rate}&\text{Time}\\ \hline \text{Marco}&12&r+3&t\\ \hline \text{Polo}&8&r&t\\ \hline \text{Total}&&& \hline \end{array}\) \(\color{#0cbb34}{\text{End of Quote}}\)
So how can we set up an equation to find \(r\)?
r = 8/t ?
We need to start off by setting two things that we know are equal, equal to each other.
And what would that be @Taco ?
the other rate?
What two things that we discussed earlier are same for both Marco and Polo?
oh time
I think I get it
Correct, they both ran the same length of time together so we set \(t = t\). Do you think you can set up the next step from here?
let me try
Post your steps here
You can use either the drawing board or the equation buttons located just below the text box.
12/(r +3) = 8/r 12r = 8(r +3) 12r = 8r +3 4r = 3 r = 3/4 is that right
12r = 8(r +3) Can you try re-doing this step by distributing the 8 using the distributive property? \(a(b + c) = ab + ac\)
oh
12r = 8(r +3) 12r = 8r + 24 4r = 24 r = 6
So what does the 6 represent in this case?
Polo runs 6mph ?
and Marco runs 9mph?
Correct.
oh wow
thank you I didnt understand this
Let's check by making sure the times are the same for both.
t = 8/6 = 4/3 t = 12/9 = 4/3
Very good. So they both ran about 1 + 1/3 hours. 6 miles or 9 miles in 1 + 1/3 hours. Seems a reasonable time for running mileages.
Can you help me with more?
Create a new post for the next question.
i don't see the text box
Because you have to close this question first.
oh
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