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\[\frac{ 1 }{ 1 - \cos \theta } + \frac{ 1 }{1 + \cos \theta}\]
needs steps for this one @nuts
just got it
\[\frac{ 1 }{ (1-\cos \theta )(1+\cos \theta)} + \frac{ 1 }{ (1+\cos \theta)(1-\cos \theta) } = \frac{ 2 }{ 1-\cos^2 \theta } = \frac{ 2 }{ \sin^2 \theta }\] .-.
@snowflake0531 wrote:
\[\frac{ 1 }{ (1-\cos \theta )(1+\cos \theta)} + \frac{ 1 }{ (1+\cos \theta)(1-\cos \theta) } = \frac{ 2 }{ 1-\cos^2 \theta } = \frac{ 2 }{ \sin^2 \theta }\] .-.
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oh oops ._. 😔
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