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Mathematics 4 Online

Shadow:

Simplife

8 years ago

Shadow:

\[\frac{ 1 }{ 1 - \cos \theta } + \frac{ 1 }{1 + \cos \theta}\]

8 years ago

Shadow:

needs steps for this one @nuts

8 years ago

Shadow:

just got it

8 years ago

snowflake0531:

\[\frac{ 1 }{ (1-\cos \theta )(1+\cos \theta)} + \frac{ 1 }{ (1+\cos \theta)(1-\cos \theta) } = \frac{ 2 }{ 1-\cos^2 \theta } = \frac{ 2 }{ \sin^2 \theta }\] .-.

5 years ago

AZ:

@snowflake0531 wrote:

\[\frac{ 1 }{ (1-\cos \theta )(1+\cos \theta)} + \frac{ 1 }{ (1+\cos \theta)(1-\cos \theta) } = \frac{ 2 }{ 1-\cos^2 \theta } = \frac{ 2 }{ \sin^2 \theta }\] .-.

No no \[\frac{ 1+\cos \theta }{ (1-\cos \theta )(1+\cos \theta)} + \frac{ 1-\cos \theta }{ (1+\cos \theta)(1-\cos \theta) } = \frac{ 2 }{ 1-\cos^2 \theta } = \frac{ 2 }{ \sin^2 \theta }\]

5 years ago

snowflake0531:

oh oops ._. 😔

5 years ago

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