+5i?
a: +5i would be the conjugate not the modulus/argument modulus is the length (or the r value) argument is the angle so as usual r = sqrt(x^2 + y^2) and angle = arctan(y/x) for a) we only have a y-value (-5) so we have to do a quick sketch to find the angle:
I believe that's treating i as an independent variable not the imaginary value i|dw:1527647759022:dw|
parabola
hm? it's not asking for a shape it's asking for a modulus and argument
im not sure actually :/
-5i (in other words, 0 - 5i) means that x = 0 and y = -5 calculate r = sqrt(x^2 + y^2) and find the angle: |dw:1527650067194:dw|
notice how the angle is made of three 90 degree angles 3*90 gives the argument r = sqrt(0^2 + (-5)^2) gives the modulus
5
so argument = 3*90 = 270 Modulus= r = sqrt(0^2 + (-5)^2) = 5
good
anyway for b) the number in front (sqrt(10)) is the modulus, and the angle of cos and sin is the argument
Wait the number in front of sqrt 10?
sqrt(10) is the modulus
oh okay so modulus= sqrt 10 argument = arccos (sqrt 10) = 1.18 arcsin (sqrt 10) = 1.57
like that
if you look at the original equation the argument is just the angle that is contained within the cos and sin expressions since its cos(5pi/7) and sin(5pi/7) the argument is just 5pi/7
oh right because we are finding both cos and sin and 5pi/7 is given
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