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Mathematics 16 Online
zarkam21:

+5i?

zarkam21:

1 attachment
Vocaloid:

a: +5i would be the conjugate not the modulus/argument modulus is the length (or the r value) argument is the angle so as usual r = sqrt(x^2 + y^2) and angle = arctan(y/x) for a) we only have a y-value (-5) so we have to do a quick sketch to find the angle:

zarkam21:

1 attachment
Vocaloid:

I believe that's treating i as an independent variable not the imaginary value i|dw:1527647759022:dw|

zarkam21:

parabola

Vocaloid:

hm? it's not asking for a shape it's asking for a modulus and argument

zarkam21:

im not sure actually :/

Vocaloid:

-5i (in other words, 0 - 5i) means that x = 0 and y = -5 calculate r = sqrt(x^2 + y^2) and find the angle: |dw:1527650067194:dw|

Vocaloid:

notice how the angle is made of three 90 degree angles 3*90 gives the argument r = sqrt(0^2 + (-5)^2) gives the modulus

zarkam21:

5

zarkam21:

so argument = 3*90 = 270 Modulus= r = sqrt(0^2 + (-5)^2) = 5

Vocaloid:

good

Vocaloid:

anyway for b) the number in front (sqrt(10)) is the modulus, and the angle of cos and sin is the argument

zarkam21:

Wait the number in front of sqrt 10?

Vocaloid:

sqrt(10) is the modulus

zarkam21:

oh okay so modulus= sqrt 10 argument = arccos (sqrt 10) = 1.18 arcsin (sqrt 10) = 1.57

zarkam21:

like that

Vocaloid:

if you look at the original equation the argument is just the angle that is contained within the cos and sin expressions since its cos(5pi/7) and sin(5pi/7) the argument is just 5pi/7

zarkam21:

oh right because we are finding both cos and sin and 5pi/7 is given

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