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Chemistry 11 Online
JMT:

Fill in the coefficients that will balance the following reaction: (a0)C3H8 + (a1)O2 → (a2)CO2 + (a3)H2O

KyroKazimake:

Hey do you still need help?

Mercury:

old question but will attempt so this can be closed generally you want to start with the longest/most complex compound, in this case we could use C3H8 as our starting point we have 3 carbons on the left side and only one on the right, so we can multiply the CO2 on the right to get __C3H8 + __O2 → 3CO2 + __H2O now we have 8 hydrogens on the left side and only 2 on the right side, so can multiply the right hydrogen by 4 to get 4H2O __C3H8 + __O2 → 3CO2 + 4H2O balancing the oxygens from there should be straightforward, count up the oxygens on the right side and write the appropriate coefficient on the O2 that gives the right # of oxygens on the left side too

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