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Mathematics 16 Online
satellite73:

\[y'+3x^2y=x^2\]

satellite73:

\[y'+\color{red}{3x^2}y=x^2\] we start by finding \(\mu\) in two steps

satellite73:

take the function of x in from of the y and integrate it wrt x

satellite73:

\[\int 3x^2dx\] is step 1

Vrefela:

So x^3

satellite73:

right

satellite73:

next step, raise \(e\) to that power, that is your \(\mu\)

Vrefela:

e^(x^3))

satellite73:

that is \(\mu\) now multiply both sides by your \(\mu\) and you will have, on the left, the derivative of \(\mu u\)

satellite73:

i mean the derivative of \(\mu y\)

Vrefela:

e^(x^3))*y' + e^(2x^3)) = e^(x^3))*(x^2)

satellite73:

yes, and integrating on the left gives \[e^{3x}y\] so your only real job is to integrate on the right

Vrefela:

So u-sub?

satellite73:

yes mental u sub

Vrefela:

(1/3)e^(x^3)

Vrefela:

I don't think thats right

satellite73:

i do

satellite73:

plus c, which is kind of important

Vrefela:

Shouldn't the x come out front?

satellite73:

god help me

satellite73:

you were right, leave it be

Vrefela:

Ok

satellite73:

\[e^{3x}y=\frac{1}{3}e^{3x}+c\] the c is real important

Vrefela:

Okie

satellite73:

gives \[e=\frac{1}{3}\] but with it you get \[y=\frac{1}{3}+ce^{-3x}\]

satellite73:

that didnt come out right at all

Vrefela:

Nope

satellite73:

i meant if you forget the c and solve for y you get \[y=\frac{1}{3}\]

satellite73:

but the correct answer is \[y=\frac{1}{3}+ce^{-3x}\]

Vrefela:

Right

satellite73:

why this miracle works is explained on page 55 i have time for one more if you like, just so you get the hang of it

Vrefela:

I appreciate it but I'm so tired. Tomorrow?

satellite73:

ok you try some though method is probably not clear yet but we did all the steps to find mu

Vrefela:

I will do 2.3 tomorrow.

Vrefela:

I should come annoy you Saturday or something

satellite73:

ok that is this section, do a ton i am not free saturday birthday party for a 3 year old

satellite73:

is your job monday through friday?

Vrefela:

I will do my entire assigned homework problems. And well maybe a weekend soon. My exam is on the 27th of June so I have to annoy you sometime about it. (if you're free of course)

Vrefela:

And yes it is. I come back to philly on the weekends

satellite73:

ok we will see we can do some tomorrow night if you like, send me a text

satellite73:

g'night

Vrefela:

Absolutely

Vrefela:

Thank you! Goodnight!

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