Question

i need some answers checked

Answer 1

@Vocaloid

Answer 2

wait, i got this one.

Answer 3

it was midsegment.

Answer 4

yeah I was gonna say, a perpendicular bisector does not necessarily have to cross the midpoints of a triangle

Answer 5

hm, not quite

use the midsegment theorem



so SW is twice the length of TV

Answer 6

so D?

Answer 7

yup well done

Answer 8

wait you said true not false

so you're right ;;

Answer 9

hm, not quite, the incenter would require the angles, not the sides, to be bisected

Answer 10

good

Answer 11

good

Answer 12

so this one should be true

Answer 13

hm, not quite, BF would be the altitude

to be a median you need to connect

1) the midpoint of a side
with
2) the opposite vertex

Answer 14

so B

Answer 15

excellent

Answer 16

hm, not quite, VU has one hash mark and TU has two hash marks so they are probably not equal to each other

try looking for a pair of corresponding angles made by two parallel lines cut by a transversal

Answer 17

going to grab a bite to eat but will be back soon

Answer 18

so any progress yet?

Answer 19

TV is the midsegment right? so SW and TV must be parallel according to the midsegment definition, these two pairs of angles must be equal

Answer 20

sorry if that's hard to see

with that being said what might the sol'n be?

Answer 21

still there?