If BC = 7 and CD = 24, find AC.
Is there a diagram associated w/ this question?
|dw:1529330039415:dw|
Here are the lengths that are given |dw:1529330501074:dw|
I think we will need to make two eqns using pythagoras theorem
All the right triangles involved are similar triangles. We can use this and proportions to get to the answer.
Oh yeah,another way to solve it. *Thumbs up*
My brain is malfunctioning >.< can u show me how u do that proportion? @Angle
Yeah, sorry, my drawing tool wasn't working properly |dw:1529331158397:dw| |dw:1529331257769:dw|
so we can set up the proportional fractions: \(\large \frac{x}{24} = \frac{7}{x}\) *note there are other ways to represent this proportion
\(AD^2=AC^2+24^2\) \(AD^2=31^2-AB^2\) \(31^2-AB^2=AC^2+24^2\) \(AB^2=AC^2+7^2\) \(31^2-(AC^2+7^2)=AC^2+24^2\) \(31^2-24^2=AC^2+7^2+AC^2\) \(2AC^2=31^2-24^2-7^2\) \(2AC^2=336\) \(AC^2=168\) \(AC=\sqrt{168}\)
Cool,we got the same answer :D Thanks for showing me that working
yup ^_^ plus, I think the square root can be simplified a little more but it's great to have more than one way to solve something :)
Haha,true ;) But I think your working for this question is much better bcoz it is simple,lol :D
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