What amount of heat is exchanged when 16.02 grams of substance Y goes from a gas at 62 degrees Celsius to a liquid at 62 degrees Celsius? Boiling point of substance Y = 62 degrees C; ΔHvaporization = 9.22 J/mol; ΔHfusion = 2.77 J/mol. MWsubstance y = 14.77 g/mol.

−1.47 x 102 J

−10.0 J

3.00 x 100 J

1.00 x 102 J

Question

What amount of heat is exchanged when 16.02 grams of substance Y goes from a gas at 62 degrees Celsius to a liquid at 62 degrees Celsius? Boiling point of substance Y = 62 degrees C; ΔHvaporization = 9.22 J/mol; ΔHfusion = 2.77 J/mol. MWsubstance y = 14.77 g/mol.

−1.47 x 102 J

−10.0 J

3.00 x 100 J

1.00 x 102 J

Mercury · Answer

the temperature is not changing, just the phase

since we are going from gas to liquid we use the molar heat of vaporization ΔHvaporization = 9.22 J/mol

simply convert 16.02 g to moles using the MW, then multiply by the molar heat of vaporization to get your solution