Question

Math quest(For fun)

Answer 1

http://prntscr.com/jzjd7u

Answer 2

A box contains gold coins.

If the coins are equally divided among six friends, four coins are left over.
If the coins are equally divided among five friends, three coins are left over.

If the box holds the smallest number of coins that meets these two conditions, how many coins are left when equally divided among seven friends?

Answer 3

0

Answer 4

Cool
Would u mind sharing your working?

Answer 5

my opinion

six friends ,four coins are left over
five friends,three coins are left over
seven friends,five coins are left over - using algorithm law

Answer 6

Not really :)

It's the sort of thing you can do by counting using yer fingers.

Answer 7

here is one way:

\(n\equiv 4(\hspace{-.3cm}\mod 6)\)
so \(n=4+6t \)

\(n\equiv 3(\hspace{-.3cm}\mod 5)\)
\(4+6t=3(\hspace{-.3cm}\mod 5)\)

\(6t=-1(\hspace{-.3cm}\mod 5)\)

since \(6 \hspace{-.3cm}\mod 5 =1\) we have

\(t=-1(\hspace{-.3cm}\mod 5)\)

which is the same as
\(t=4(\hspace{-.3cm}\mod 5)\)

so use t=4 since it is the smallest positive value

\(n=4+6t =4+6(4)=4+24=28\)

since \(7|28\) we have

\(n\equiv 0(\hspace{-.3cm}\mod 7)\)

Answer 8

jhonny9,answer is 0
but good try tho ^

lol,sillybilly123 ;P

Nice one,Zarkon
Thanks 4 sharing ur solution. ^

Answer 9

TU, MARC, for seeing funny side 👌

was how it was intended

Answer 10

Haha,np,sillybilly123 ;)