i need some help
@Vocaloid
yikes, I'm not quite sure about this one coordinate plane? I can't really find much on the internet
what about this?
alright, this is kind of hard to explain because it requires you to use a bit of imagination/visualization but there need to be four long sides, and two small square "caps" that can fold on either side of the shape with that being said what might be the best choice?
top right one?
good
good
hm, not quite first find the missing angle, using the fact that all angles in a triangle sum up to 180 then use law of sines to find the missing side
81?
good, then use law of sines to find the missing side
9.4?
got close to that
8/sin(81) = x/sin(44) x = ?
-12.70
make sure you're using degrees not radians
8.009?
8/sin(81) = x/sin(44) cross multiply to get 8sin(44) = x*sin(81) solve for x make sure your calc is in degrees mode
5.6
good so 5.6 = your sol'n
good
check your calculations again |dw:1530151648418:dw| use law of cosines. let the missing side x be C
ok
let's look at your diagram c = the missing side x the angle is 128 degrees a and b are the other two sides 420 and 330 therefore x^2 = (420)^2 + (330)^2 + 2(330)(420)cos(128) solve for x.
338.5
x^2 = (420)^2 + (330)^2 + 2(330)(420)cos(128) therefore you just need to plug (420)^2 + (330)^2 + 2(330)(420)cos(128) into a calculator then take the square root of the result make sure your calculator is in degrees mode
750
start with this 2(330)(420)cos(128) what do you get?
45181.0
let's break it down step by step cos(128) = ?
-0.42
what sort of calculator are you using?
a scientific calculator
the one that comes pre-installed in windows 8.
is it actually -0.69
yup, it should be around -.69 for calculators like this you need to clear the calculator, press 128, then press the cos button (it's backwards from how a real one usually works)
562500
*should be a minus sign in between the 330^2 and the 2(330)(420)cos(128)
but anyway, remember your order of operations remember order of operations 1. calculate (420)^2 2. calculate (330)^2 3. calculate 2(330)(420)cos(128) then add the first 2 quantities, then subtract the last quantity
8100
1. calculate (420)^2 = 176400 2. calculate (330)^2 = 108900 3. calculate 2(330)(420)cos(128) = -170661.361 now calculate (420)^2 + (330)^2 - 2(330)(420)cos(128)
477370.722
(420)^2 + (330)^2 - 2(330)(420)cos(128) = 176400 + 108900 - (-170661.361) = ?
455961
good now take the square root
675
jfc..
good so 675 = your sol'n
not quite, check your calculations again use law of cosines where c^2 = a^2 + b^2 - 2*a*b*cos(C) c is the missing side; a and b are the given sides; C is the angle solve for c
130585
c^2 = a^2 + b^2 - 2*a*b*cos(C) plugging in the values we get c^2 = 252^2 + 229^2 - 2(229)(252)*cos(94) evaluate what 252^2 + 229^2 - 2(229)(252)*cos(94) and take the square root
can't sove it, lemme try it manually
4053
252^2 = 63504 229^2 = 52441 2(229)(252)*cos(94) = -8051.01 plugging these into the formula gives us 63504 + 52441 - (-8051.01) = ?
123996.01
good then take the square root to get your sol'n
not quite using law of sines 72/sin(46) = 90/sin(x) solve for x
1.11
that's in radians, convert that to degrees
2.02?
to convert from radians to degrees, multiply by (180/pi) 1.11 * (180/pi) = ?
63.5
good so 64 = your sol'n
good
you don't know any angles so you can't use law of sines
good
not quite remember sin(angle)/side across from the angle
so the top right one then?
good
good
good
good
good
good
hm. not quite. angle = arctan(y/x) so you need to calculate the angle of the plane before the wind (160,-120) and the angle after the wind is applied (160 + 40, -120 + 40)
120
and 40
let's take it one step at a time angle = arctan(y/x) for the first plane (160,-120), what is arctan(y/x) = ?
1.107
arctan(-120/160) = ? make sure you are using arctan not tan
-0.64
good but let's use degrees instead -0.64 in degrees is -36.87 degrees now apply the same logic to find the angle of (160 + 40, -120 + 40)
1,56246319
let's try that again (160 + 40, -120 + 40) = (200,-80) arctan(-80/200) in degrees = ?
-0.0066410891
arctan(-80/200 = -21.8 degrees therefore the difference = -36.87 - (-21.8) = -15.07 so there's a 15 degree difference = your sol'n
good
hm not quite if you draw a right triangle between the lake and pool you get a right triangle w/ legs 5 and 1 so what would be the hypotenuse if the legs are 5 and 1?
7?
wait, 5
hypotenuse = sqrt(leg^2 + leg^2)
5.09
the answers in radical form so sqrt(5^1 +1^1) = sqrt(26) = your sol'n
speed is a scalar so it's always positive so 28.3 not -28.3
the x-coordinate comes first make sure to also consider the direction, too
for example, from A to B it goes 1 unit to the left so we have -1 as the x-coordinate then we go 4 units up as the y-coordinate giving us (-1,4) as the sol'n
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