Question

i need more answers checked

Answer 1

@Vocaloid

Answer 2

hm. not quite. GEH is one half of <FEH right?

and <FEH and <GFE are supplementary, right?

using this information try solving for <GFE

Answer 3

31.5

Answer 4

if GEH is one half of FEH, that means FEH is 2 * GEH = 2 * 63 = 126

as stated before:

FEH and GFE are supplementary

therefore GFE + 126 = 180

Answer 5

solve for GFE

Answer 6

54

Answer 7

right?

Answer 8

hm lemme just double check something first

Answer 9

apparently this method only works if the sides are congruent which is not explicitly stated

still figuring out how to solve it w/o this assumption

Answer 10

oh..

Answer 11

@hero @Nnesha having a bit of a brain fart, how do I solve this w/ the information given?

Answer 12

@MARC may I have a second opinion on this? my first thought was to assume the diagonals bisect the angles but then I realized the side lengths aren't given so that wouldn't automatically be valid

Answer 13

...

Answer 14

I think that shape should be rhombus
If it is a parallelogram,I don't think we can solve it,unless there are extra info X'D
Mercury,ur working looks good so far

Answer 15

alright just making sure cuz this problem was messing with me

in that case, the solution is 54 as stated before

Answer 16

I didn't really want to assume the shape was a rhombus 'cause that's a common math trap to make misleading diagrams ;_;

Answer 17

hm. not quite.

it's a rectangle so opposite sides are equal

therefore x^2 + 12 = 10x - 13

solve for x. as a hint, move all the terms to one side by performing the appropriate operations, then factor

Answer 18

5,5?

Answer 19

good

x = 5

(don't write 5,5, since x has a single value)

Answer 20

Theorem 8: A quadrilateral is a rhombus if and only if the diagonals are perpendicular bisectors of each other.
Theorem 9: A quadrilateral is a rhombus if and only if the diagonals bisect all the vertex angles.
For the previous question ;p

Answer 21

good, y = 6

Answer 22

any ideas?

as a hint: squares ~have~ to have four 90 degree angles

Answer 23

good

Answer 24

good (sorry had to brush my teeth)

Answer 25

good

Answer 26

good

Answer 27

good

Answer 28

good

Answer 29

good

Answer 30

good

Answer 31

hm. not quite.
remember that the midsegment is the average of the bases

so add up the bases 5 and 3.2, then divide by 2

Answer 32

4.1

Answer 33

good so 4.1 = your sol'n

Answer 34

hm, not quite

notice how the upper left part of the kite is a right triangle with hypotenuse = 5 and leg = 3

using the pythagorean theorem what's the length of the missing leg?

Answer 35

34?

Answer 36

5? @Mercury

Answer 37

leg^2 + leg^2 = hypotenuse^2

one leg = 3
hypotenuse = 5

solve for the missing leg

Answer 38

34

Answer 39

3^2 + leg^2 = 5^2

solve for leg

Answer 40

remember your order of operations. simplify the exponents first.

Answer 41

good

Answer 42

good

Answer 43

good

Answer 44

imagine rotating your problem 90 degrees so it looks more like this

the parallel sides are AB and CD making BC and AD the legs

so the original statement is true

Answer 45

good

Answer 46

remember you need to square the legs too

hypotenuse = sqrt(4^2 + 9^2) = ?

leave in radical form w/o simplifying to a decimal

Answer 47

D?

Answer 48

what is 4^2 + 9^2?

Answer 49

97

Answer 50

good so taking the sqrt of that gives us sqrt(97) = your sol'n

Answer 51

D is actually a true statement (one pair congruent + parallel = parallelogram)

let's look at A again



if adjacent sides are congruent we have a kite not a parallelogram

so A is the best choice here

Answer 52

hm. not quite. slope = rise/run

notice how it's rising 3 units and running 2 units

Answer 53

so 3/2?

Answer 54

good

Answer 55

it's slightly off from a true parallelogram so false

Answer 56

good

Answer 57

close but not quite

the pythagorean theorem is leg^2 + leg^2 not leg^2 - leg^2

so the last choice should be it

Answer 58

good (sorry that took a while, was trying to figure out some software thing)

Answer 59

check again

the formula states that there should be subtraction inside the parentheses, and addition between them

Answer 60

good