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Mathematics 15 Online
princeevee:

i need some answers checked

princeevee:

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princeevee:

@Mercury

Mercury:

good

princeevee:

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Mercury:

for a prism generally the volume = base*height so calculate the area of the triangle then multiply by the height

Mercury:

area of a triangle = (1/2)bh = (1/2)(8)(20) then just multiply the height so volume = (1/2)(8)(20)(20) => plug these in to get the solution

Mercury:

my family and I are gonna watch a movie I'll try to be on later tonight

princeevee:

okay

Mercury:

any new questions?

princeevee:

yeah

princeevee:

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Mercury:

hm not quite notice how you have a right triangle on the right side one of the legs is 100 and the other leg is 550/2 calculate the hypotenuse w/ pythagorean theorem

Mercury:

*just had to correct a typo

princeevee:

A?

Mercury:

good

princeevee:

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Mercury:

hm not quite if you treat it as a right triangle, the smaller leg is 9/2 and the hypotenuse is 11.8 solve for the other leg x

princeevee:

10.9?

Mercury:

good

princeevee:

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Mercury:

good

princeevee:

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Mercury:

good

princeevee:

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Mercury:

good

princeevee:

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Mercury:

good

princeevee:

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Mercury:

good

princeevee:

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Mercury:

hm not quite you have a right triangle with the short leg 32/2, other leg 12 calculate the hypotenuse

princeevee:

20?

Mercury:

good so 20 = your sol'n

princeevee:

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Mercury:

hm not quite you have a right triangle with legs 12/2 (since it's in the middle of the 12 ft beam) and hypotenuse 12, calculate the other leg

princeevee:

17?

Mercury:

(12/2)^2 + x^2 = 12^2

princeevee:

5

Mercury:

remember order of operations 6^2 + x^2 = 12^2 simplifying the exponents 36 + x^2 = 144 solve for x

princeevee:

108

Mercury:

remember the formula gives you the value of x^2 not x so you have to take the square root at the end.

princeevee:

10.4

Mercury:

good so 10.4 = your sol'n

princeevee:

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princeevee:

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Mercury:

hm not quite "four of the fourty gondolas" so (4/40) * 360 degrees = ?

princeevee:

36

Mercury:

good so 36 = your sol'n

princeevee:

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Mercury:

not quite he ran 152 degrees so the fraction is (152/360) multiply that fraction by the circumference 2pi*r

Mercury:

(152/360) * 2 * 3.14 * 1.2 = ?

Mercury:

still there? you just need to chuck (152/360) * 2 * 3.14 * 1.2 = ? into a calculator

princeevee:

sorry, had to do a bit of chores

princeevee:

3.18

princeevee:

@Mercury

Mercury:

good (rounds up to 3.2)

princeevee:

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Mercury:

not quite notice how SKF includes the 56 angle + half the circle so 180 + 56

princeevee:

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Mercury:

good

princeevee:

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Mercury:

good

princeevee:

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Mercury:

good

princeevee:

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Mercury:

"five teams of four" so 20 students out of 24 (20/24) * 360 = ?

princeevee:

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Mercury:

good

princeevee:

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Mercury:

notice how RQS includes everything except the 30 degree angle

Mercury:

"everything except the 30 degree angle" so take the whole circle 360 and subtract 30 degrees.

princeevee:

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Mercury:

good

princeevee:

i'm gonna head off for the night, you will be here tomorrow, right?

Mercury:

I'm doing volunteer work all day but maybe in the evening

princeevee:

i might be able to do some more, if that's okay

princeevee:

@Mercury

Mercury:

sure

princeevee:

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Mercury:

notice how angle ADC is the inscribed arc of <B so it's double <B

princeevee:

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Mercury:

each side of the octagon is 45 the number of sides between TQV is 5 so 5 * 45

princeevee:

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Mercury:

good

princeevee:

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Mercury:

close but not quite, the angle is half the arc not double

princeevee:

60?

Mercury:

the angle is half the arc the arc is 60 so the angle is 30

princeevee:

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Mercury:

yikes what's the question it's not showing up for me

princeevee:

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Mercury:

good

princeevee:

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Mercury:

if you notice <JHI includes everything except the arc JI so it's 360 - 124

princeevee:

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Mercury:

both angles Q and R intersect the same arc PS so 5x = 28.5 solve for x

princeevee:

2.3?

Mercury:

check your calculations again if 5x = 28.5 simply divide both sides by 5 to get x

princeevee:

5.7

Mercury:

good so 5.7 = your sol'n

princeevee:

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Mercury:

statement 1 is true (remember that an angle on the edge of a circle is 1/2 its arc)

Mercury:

try checking the other statements

princeevee:

C?

Mercury:

statement 3 is true for the same reason statement 1 is (angle on the edge of circle is 1/2 its arc) notice how statement 4 is talking about arcs on opposite sides of the circle so the 1/2 rule does not apply making statement 4 the incorrect statement and thus the solution

princeevee:

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Mercury:

good

princeevee:

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Mercury:

good

princeevee:

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Mercury:

hm. still working on it.

Mercury:

ok got it 140K is correct

princeevee:

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Mercury:

good

princeevee:

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Mercury:

|dw:1530777860150:dw| concentric means they have to have the same center which is not the case in your problem between "nonintersecting" and "tangent" which one do you think is the better descriptor? keep in mind the red dots where the circles touch

princeevee:

tangent

Mercury:

good so tangent = your sol'n

princeevee:

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Mercury:

huh generally the tangent does not include the radius except for the tangent point so generally speaking i would say no |dw:1530778461837:dw|

princeevee:

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Mercury:

good

princeevee:

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Mercury:

good

princeevee:

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Mercury:

good

princeevee:

alright, i think it's time for both of us to sleep

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