Mathematics
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princeevee:
i need some answers checked
7 years ago
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princeevee:
7 years ago
princeevee:
@Mercury
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
Mercury:
for a prism generally the volume = base*height
so calculate the area of the triangle then multiply by the height
7 years ago
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Mercury:
area of a triangle = (1/2)bh = (1/2)(8)(20)
then just multiply the height
so volume = (1/2)(8)(20)(20) => plug these in to get the solution
7 years ago
Mercury:
my family and I are gonna watch a movie
I'll try to be on later tonight
7 years ago
princeevee:
okay
7 years ago
Mercury:
any new questions?
7 years ago
princeevee:
yeah
7 years ago
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princeevee:
7 years ago
Mercury:
hm not quite
notice how you have a right triangle on the right side
one of the legs is 100 and the other leg is 550/2
calculate the hypotenuse w/ pythagorean theorem
7 years ago
Mercury:
*just had to correct a typo
7 years ago
princeevee:
A?
7 years ago
Mercury:
good
7 years ago
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princeevee:
7 years ago
Mercury:
hm not quite
if you treat it as a right triangle, the smaller leg is 9/2 and the hypotenuse is 11.8
solve for the other leg x
7 years ago
princeevee:
10.9?
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
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Mercury:
good
7 years ago
princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
Mercury:
good
7 years ago
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princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
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Mercury:
hm not quite
you have a right triangle with the short leg 32/2, other leg 12
calculate the hypotenuse
7 years ago
princeevee:
20?
7 years ago
Mercury:
good so 20 = your sol'n
7 years ago
princeevee:
7 years ago
Mercury:
hm not quite
you have a right triangle with legs 12/2 (since it's in the middle of the 12 ft beam) and hypotenuse 12, calculate the other leg
7 years ago
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princeevee:
17?
7 years ago
Mercury:
(12/2)^2 + x^2 = 12^2
7 years ago
princeevee:
5
7 years ago
Mercury:
remember order of operations
6^2 + x^2 = 12^2
simplifying the exponents
36 + x^2 = 144
solve for x
7 years ago
princeevee:
108
7 years ago
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Mercury:
remember the formula gives you the value of x^2 not x so you have to take the square root at the end.
7 years ago
princeevee:
10.4
7 years ago
Mercury:
good so 10.4 = your sol'n
7 years ago
princeevee:
7 years ago
princeevee:
7 years ago
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Mercury:
hm not quite
"four of the fourty gondolas"
so (4/40) * 360 degrees = ?
7 years ago
princeevee:
36
7 years ago
Mercury:
good so 36 = your sol'n
7 years ago
princeevee:
7 years ago
Mercury:
not quite
he ran 152 degrees so the fraction is (152/360)
multiply that fraction by the circumference 2pi*r
7 years ago
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Mercury:
(152/360) * 2 * 3.14 * 1.2 = ?
7 years ago
Mercury:
still there? you just need to chuck (152/360) * 2 * 3.14 * 1.2 = ? into a calculator
7 years ago
princeevee:
sorry, had to do a bit of chores
7 years ago
princeevee:
3.18
7 years ago
princeevee:
@Mercury
7 years ago
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Mercury:
good (rounds up to 3.2)
7 years ago
princeevee:
7 years ago
Mercury:
not quite
notice how SKF includes the 56 angle + half the circle
so 180 + 56
7 years ago
princeevee:
7 years ago
Mercury:
good
7 years ago
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princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
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Mercury:
"five teams of four" so 20 students out of 24
(20/24) * 360 = ?
7 years ago
princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
Mercury:
notice how RQS includes everything except the 30 degree angle
7 years ago
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Mercury:
"everything except the 30 degree angle"
so take the whole circle 360 and subtract 30 degrees.
7 years ago
princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
i'm gonna head off for the night, you will be here tomorrow, right?
7 years ago
Mercury:
I'm doing volunteer work all day but maybe in the evening
7 years ago
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princeevee:
i might be able to do some more, if that's okay
7 years ago
princeevee:
@Mercury
7 years ago
Mercury:
sure
7 years ago
princeevee:
7 years ago
Mercury:
notice how angle ADC is the inscribed arc of <B so it's double <B
7 years ago
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princeevee:
7 years ago
Mercury:
each side of the octagon is 45
the number of sides between TQV is 5
so 5 * 45
7 years ago
princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
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Mercury:
close but not quite, the angle is half the arc not double
7 years ago
princeevee:
60?
7 years ago
Mercury:
the angle is half the arc
the arc is 60
so the angle is 30
7 years ago
princeevee:
7 years ago
Mercury:
yikes
what's the question it's not showing up for me
7 years ago
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princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
Mercury:
if you notice <JHI includes everything except the arc JI
so it's 360 - 124
7 years ago
princeevee:
7 years ago
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Mercury:
both angles Q and R intersect the same arc PS so 5x = 28.5 solve for x
7 years ago
princeevee:
2.3?
7 years ago
Mercury:
check your calculations again
if 5x = 28.5 simply divide both sides by 5 to get x
7 years ago
princeevee:
5.7
7 years ago
Mercury:
good so 5.7 = your sol'n
7 years ago
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princeevee:
7 years ago
Mercury:
statement 1 is true (remember that an angle on the edge of a circle is 1/2 its arc)
7 years ago
Mercury:
try checking the other statements
7 years ago
princeevee:
C?
7 years ago
Mercury:
statement 3 is true for the same reason statement 1 is (angle on the edge of circle is 1/2 its arc)
notice how statement 4 is talking about arcs on opposite sides of the circle so the 1/2 rule does not apply making statement 4 the incorrect statement and thus the solution
7 years ago
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princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
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Mercury:
hm. still working on it.
7 years ago
Mercury:
ok got it 140K is correct
7 years ago
princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
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Mercury:
|dw:1530777860150:dw|
concentric means they have to have the same center which is not the case in your problem
between "nonintersecting" and "tangent" which one do you think is the better descriptor? keep in mind the red dots where the circles touch
7 years ago
princeevee:
tangent
7 years ago
Mercury:
good so tangent = your sol'n
7 years ago
princeevee:
7 years ago
Mercury:
huh
generally the tangent does not include the radius except for the tangent point
so generally speaking i would say no
|dw:1530778461837:dw|
7 years ago
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princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
Mercury:
good
7 years ago
princeevee:
7 years ago
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Mercury:
good
7 years ago
princeevee:
alright, i think it's time for both of us to sleep
7 years ago