i need some questions checked
@Vocaloid
check your calculations again volume of a cylinder = pi * r^2 * h
90.25 for the radius
1.27 for the height
the radius is just 9.5 not 90.25
643.3?
wait a sec
it's asking for the surface area not volume (since the penny is only coated w/ copper) so the formula ends up being SA = 2*pi*r*h + 2*pi*r^2 plug in r and h
uh, can you plug those in real quick?
i gotta run a quick errand
r is 9.5 as stated before h is 1.27 SA = 2*pi*r*h + 2*pi*r^2 = 2*pi*1.27*9.5 + 2*pi*9.5^2
642.8
be careful with order of operations start by calculating 2*pi*9.5^2 and 2*pi*1.27*9.5 separately then add them together
plug 2*pi*9.5^2 into a calculator and write the result down plug 2*pi*1.27*9.5 into a calculator and write the result down then add them together
567 and 75.8
ugh apparently I had the wrong thing typed in anyway 2*pi*9.5^2 + 2*pi*1.27*9.5 becomes 642.86 which rounds up to 642.9 = your sol'n
SA = 2*pi*r*h + 2*pi*r^2 again plug in r and h
477.5
good
true?
|dw:1530839227692:dw| this one is actually false, lateral area excludes the top/bottom bases
so use the same equation for this, right?
it's asking for lateral area not surface area so simply find the perimeter of the octagon and then multiply by the height
an octagon has eight equal sides so its perimeter is 8 * side length.
65.7
6.5 is the height and 7.4 is the side length
if 7.4 is the side length what is the perimeter?
6.5
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mercury an octagon has eight equal sides so its perimeter is 8 * side length. \(\color{#0cbb34}{\text{End of Quote}}\)
the side length as we established is 7.4 therefore perimeter = 8*7.4 all that's left is to multiply by the height 6.5.
384.8
good so that's your solution
D?
good
true?
good
check your calculations again let's start with the two triangle sides. height 3, base 4, what's the combined area of both triangles?
remember the formula for the area of a triangle is (1/2)bh.
6
good but we want to know the area of both triangles so double that to get 12 now let's look at the three remaining faces you have a rectangle with side lengths 5 and 13 a rectangle with side lengths 4 and 13 and a rectangle with side lengths 3 and 13 calculate the sum of these areas
i got it now
still working i keep getting something that's not one of the choices
alright finally figured out where i was going wrong you need to calculate the height of the triangle on the dotted line so its a right triangle with hypotenuse 10 and leg 12/2 calculate the other leg
i'm getting confused now...
|dw:1530843652728:dw|
|dw:1530843684338:dw|
check the circled triangle notice how you have a right triangle with leg 6 and hypotenuse 10 calculate the length of the other leg.
like, 4?
use the Pythagorean theorem
136
leg^2 + leg^2 = hypotenuse^2 plug in the hypotenuse, leg, and solve for the other leg
leg = 6 hypotenuse = 10 6^2 + leg^2 = 10^2 solve for leg.
8
good so 8 gives us the height of the triangle we already know the base is 12 so area = (1/2)bh = (1/2)8*12 we have two triangles so just double that to get 8*12 = 96, then we keep going w/ the other sides
we have one big side on the front that's 12 * 12 and two smaller rectangular sides that are 10 * 12 each so 12 * 12 + 2(10*12) + 96 from before = 480 = your solution
hm not quite let's check your calculations again let's start w/ the walls of the building two walls that are 8*6 and two walls that are 6*6 gives us 2(8*6) + 2(6*6)
then, we add the top which is another 8*6 side we subtract the area where the smokestack and ceiling touch so - (0.5)^2 * pi from that finally we add the painted area of the smokestack which is just 2*pi*r*h = 2*pi*0.5*3
putting it all together 2(8*6) + 2(6*6) + 8*6- (0.5)^2 * pi + 2*pi*0.5*3 = ?
for the sake of time after you plug this into a calculator it's 224.6 = your solution.
sorry, i'm not really working at full capacity today...
@Mercury
close but not quite the amt. of material to make a box is equal to its surface area a cube has 6 sides so 6 * area of each side
so it was just 60?
6*10*10 = 600 not 60
sorry
let me ask someone b/c i'm not quite sure i understand what they're looking for
ok
alright i got it |dw:1530847398992:dw|
let's start w/ the semicircle circumference is 2pi*r as usual we only have half the circle so (1/2) * 2pi*r or just pi*r, or 2pi multiplying this by the thickness of the arch (1ft) just gives us 2pi * 1 for the semicircular part
wait, is r 4 or 7?
|dw:1530847535136:dw|
notice how the top part of the arch has diameter 4 as shown in the original picture so the radius is 1/2 the diameter, or 2
moving on to the rectangular parts, we saw that the top part of the arch is 2 ft and the total height of the arch is 7 feet so the part of the arch without the circular dome part is 5 feet tall the two wooden parts on the left and right side of the arch are 1 foot wide so area of each rectangular piece on the side is 1 * 5 = 5 since there are two of them, we double to get 10
adding everything together: 10 from the rectangular pieces + 2pi from the arch part gives us about ~16.3 feet when you chuck this into a calculator so 16.3 is the best choice out of all of them
if you're having some trouble understanding try to visualize the arch first as a 2dimensional figure like this|dw:1530848110438:dw|
since 4 is essentially the diameter of the semicircle, divide 4/2 to get the radius 2
|dw:1530848196881:dw|
(sorry for the crappy diagram but) since we have a semicircle, we can draw any line segment from the center to the edge to get another segment with length 2
|dw:1530848265063:dw|
now, we know the circular part + rectangular part combined have a height of 7 feet subtracting the 2 feet from the "dome" circular part, we get 5 as the height of the rectangular part
|dw:1530848338835:dw|
then we switch back to a 3-d view of the image |dw:1530848419103:dw|
sorry if this is kind of overwhelming
it's perfectly fine.
@Mercury so the equation is to just multiply pi with the diameter or something?
hm perhaps I could explain it another way imagine if we took the arch and "unrolled" it into a giant rectangle
|dw:1530848932879:dw|
|dw:1530848956437:dw| where the entire length of the arch becomes the length of this rectangle and the width of the arch becomes the width of this new rectangle
we already know how wide the arch is (1 foot), but we need to do a bit of work to find the length we can see that the arch has a rectangular part underneath the semicircle. so we just need to find the circumference of the semicircle + the lengths of the sides to find the length of the long rectangle when the arch is "unrolled"
|dw:1530849080418:dw|
using these calculations, we can see that the arch (from a 2d perspective) is composed of: 1) a rectangle with length 5 and 2) a semicircle with radius 2
we have two rectangular sides (5 each, so 5+5 = 10) and a semicircle which we can find the circumference by taking (1/2)*2*pi*r or just pi*r the entire diameter of the circular part is 4 (see the original diagram) so the radius is just 2 therefore the circumference is pi*r = 2*pi
so adding up all these lengths together: 5 + 5 + 2*pi === > the length of the entire arch when "unrolled" 1 is the width and as usual, area of a rectangle is L*W so (5+5+2pi)*1 ==> area of the entire arch when unrolled, and thus the solution
alright
16.3
good
good
hm not quite we want the lateral surface area so pi*r^2 * h plug in r and h and pi
D
good
hm not quite pi*r^2 * h check your calculations again
pi*2^2*11
B
|dw:1530850554653:dw| the 4 lateral faces are the triangles which ~do~ meet at the vertex (apex) so the original statement is true
|dw:1530850957549:dw|
if we try shading in this right triangle over here:|dw:1530851006546:dw|
we can see we have a right triangle with legs 15 and 20 (since the bottom leg is half the length of one side) use the pythagorean theorem to find the hypotenuse first
625
almost, remember the pythagorean theorem gives you the square of a side so we take the sqrt of 625 to get 25 as the hypotenuse with that being said we go back to the original pyramid:
|dw:1530851276994:dw|
now we can see each side of the triangle has height 25 and base 40 calculate the area of one triangle (using area = 1/2 * b * h) and multiply by 4 to get the lateral area
so 25?
no, 15
(1/2)bh * 4 = (1/2)(25)(40) * 4
75
right?
@Mercury
@sammixboo
Yo my wifi randomly cut out last night sorry about that :/
@vocaloid @Mercury that's alright, should we continue now though?
Join our real-time social learning platform and learn together with your friends!