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Mathematics 18 Online
princeevee:

i need some questions checked

princeevee:

@Vocaloid

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Mercury:

check your calculations again volume of a cylinder = pi * r^2 * h

princeevee:

90.25 for the radius

princeevee:

1.27 for the height

Mercury:

the radius is just 9.5 not 90.25

princeevee:

643.3?

Mercury:

wait a sec

Mercury:

it's asking for the surface area not volume (since the penny is only coated w/ copper) so the formula ends up being SA = 2*pi*r*h + 2*pi*r^2 plug in r and h

princeevee:

uh, can you plug those in real quick?

princeevee:

i gotta run a quick errand

Mercury:

r is 9.5 as stated before h is 1.27 SA = 2*pi*r*h + 2*pi*r^2 = 2*pi*1.27*9.5 + 2*pi*9.5^2

princeevee:

642.8

Mercury:

be careful with order of operations start by calculating 2*pi*9.5^2 and 2*pi*1.27*9.5 separately then add them together

Mercury:

plug 2*pi*9.5^2 into a calculator and write the result down plug 2*pi*1.27*9.5 into a calculator and write the result down then add them together

princeevee:

567 and 75.8

Mercury:

ugh apparently I had the wrong thing typed in anyway 2*pi*9.5^2 + 2*pi*1.27*9.5 becomes 642.86 which rounds up to 642.9 = your sol'n

princeevee:

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Mercury:

SA = 2*pi*r*h + 2*pi*r^2 again plug in r and h

princeevee:

477.5

Mercury:

good

princeevee:

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princeevee:

true?

Mercury:

|dw:1530839227692:dw| this one is actually false, lateral area excludes the top/bottom bases

princeevee:

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princeevee:

so use the same equation for this, right?

Mercury:

it's asking for lateral area not surface area so simply find the perimeter of the octagon and then multiply by the height

Mercury:

an octagon has eight equal sides so its perimeter is 8 * side length.

princeevee:

65.7

Mercury:

6.5 is the height and 7.4 is the side length

Mercury:

if 7.4 is the side length what is the perimeter?

princeevee:

6.5

Mercury:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mercury an octagon has eight equal sides so its perimeter is 8 * side length. \(\color{#0cbb34}{\text{End of Quote}}\)

Mercury:

the side length as we established is 7.4 therefore perimeter = 8*7.4 all that's left is to multiply by the height 6.5.

princeevee:

384.8

Mercury:

good so that's your solution

princeevee:

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princeevee:

D?

Mercury:

good

princeevee:

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princeevee:

true?

Mercury:

good

princeevee:

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Mercury:

check your calculations again let's start with the two triangle sides. height 3, base 4, what's the combined area of both triangles?

Mercury:

remember the formula for the area of a triangle is (1/2)bh.

princeevee:

6

Mercury:

good but we want to know the area of both triangles so double that to get 12 now let's look at the three remaining faces you have a rectangle with side lengths 5 and 13 a rectangle with side lengths 4 and 13 and a rectangle with side lengths 3 and 13 calculate the sum of these areas

princeevee:

i got it now

princeevee:

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Mercury:

still working i keep getting something that's not one of the choices

Mercury:

alright finally figured out where i was going wrong you need to calculate the height of the triangle on the dotted line so its a right triangle with hypotenuse 10 and leg 12/2 calculate the other leg

princeevee:

i'm getting confused now...

Mercury:

|dw:1530843652728:dw|

Mercury:

|dw:1530843684338:dw|

Mercury:

check the circled triangle notice how you have a right triangle with leg 6 and hypotenuse 10 calculate the length of the other leg.

princeevee:

like, 4?

Mercury:

use the Pythagorean theorem

princeevee:

136

Mercury:

leg^2 + leg^2 = hypotenuse^2 plug in the hypotenuse, leg, and solve for the other leg

Mercury:

leg = 6 hypotenuse = 10 6^2 + leg^2 = 10^2 solve for leg.

princeevee:

8

Mercury:

good so 8 gives us the height of the triangle we already know the base is 12 so area = (1/2)bh = (1/2)8*12 we have two triangles so just double that to get 8*12 = 96, then we keep going w/ the other sides

Mercury:

we have one big side on the front that's 12 * 12 and two smaller rectangular sides that are 10 * 12 each so 12 * 12 + 2(10*12) + 96 from before = 480 = your solution

princeevee:

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Mercury:

hm not quite let's check your calculations again let's start w/ the walls of the building two walls that are 8*6 and two walls that are 6*6 gives us 2(8*6) + 2(6*6)

Mercury:

then, we add the top which is another 8*6 side we subtract the area where the smokestack and ceiling touch so - (0.5)^2 * pi from that finally we add the painted area of the smokestack which is just 2*pi*r*h = 2*pi*0.5*3

Mercury:

putting it all together 2(8*6) + 2(6*6) + 8*6- (0.5)^2 * pi + 2*pi*0.5*3 = ?

Mercury:

for the sake of time after you plug this into a calculator it's 224.6 = your solution.

princeevee:

sorry, i'm not really working at full capacity today...

princeevee:

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princeevee:

@Mercury

Mercury:

close but not quite the amt. of material to make a box is equal to its surface area a cube has 6 sides so 6 * area of each side

princeevee:

so it was just 60?

Mercury:

6*10*10 = 600 not 60

princeevee:

sorry

princeevee:

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Mercury:

let me ask someone b/c i'm not quite sure i understand what they're looking for

princeevee:

ok

Mercury:

alright i got it |dw:1530847398992:dw|

Mercury:

let's start w/ the semicircle circumference is 2pi*r as usual we only have half the circle so (1/2) * 2pi*r or just pi*r, or 2pi multiplying this by the thickness of the arch (1ft) just gives us 2pi * 1 for the semicircular part

princeevee:

wait, is r 4 or 7?

Mercury:

|dw:1530847535136:dw|

Mercury:

notice how the top part of the arch has diameter 4 as shown in the original picture so the radius is 1/2 the diameter, or 2

Mercury:

moving on to the rectangular parts, we saw that the top part of the arch is 2 ft and the total height of the arch is 7 feet so the part of the arch without the circular dome part is 5 feet tall the two wooden parts on the left and right side of the arch are 1 foot wide so area of each rectangular piece on the side is 1 * 5 = 5 since there are two of them, we double to get 10

Mercury:

adding everything together: 10 from the rectangular pieces + 2pi from the arch part gives us about ~16.3 feet when you chuck this into a calculator so 16.3 is the best choice out of all of them

Mercury:

if you're having some trouble understanding try to visualize the arch first as a 2dimensional figure like this|dw:1530848110438:dw|

Mercury:

since 4 is essentially the diameter of the semicircle, divide 4/2 to get the radius 2

Mercury:

|dw:1530848196881:dw|

Mercury:

(sorry for the crappy diagram but) since we have a semicircle, we can draw any line segment from the center to the edge to get another segment with length 2

Mercury:

|dw:1530848265063:dw|

Mercury:

now, we know the circular part + rectangular part combined have a height of 7 feet subtracting the 2 feet from the "dome" circular part, we get 5 as the height of the rectangular part

Mercury:

|dw:1530848338835:dw|

Mercury:

then we switch back to a 3-d view of the image |dw:1530848419103:dw|

Mercury:

sorry if this is kind of overwhelming

princeevee:

it's perfectly fine.

princeevee:

@Mercury so the equation is to just multiply pi with the diameter or something?

Mercury:

hm perhaps I could explain it another way imagine if we took the arch and "unrolled" it into a giant rectangle

Mercury:

|dw:1530848932879:dw|

Mercury:

|dw:1530848956437:dw| where the entire length of the arch becomes the length of this rectangle and the width of the arch becomes the width of this new rectangle

Mercury:

we already know how wide the arch is (1 foot), but we need to do a bit of work to find the length we can see that the arch has a rectangular part underneath the semicircle. so we just need to find the circumference of the semicircle + the lengths of the sides to find the length of the long rectangle when the arch is "unrolled"

Mercury:

|dw:1530849080418:dw|

Mercury:

using these calculations, we can see that the arch (from a 2d perspective) is composed of: 1) a rectangle with length 5 and 2) a semicircle with radius 2

Mercury:

we have two rectangular sides (5 each, so 5+5 = 10) and a semicircle which we can find the circumference by taking (1/2)*2*pi*r or just pi*r the entire diameter of the circular part is 4 (see the original diagram) so the radius is just 2 therefore the circumference is pi*r = 2*pi

Mercury:

so adding up all these lengths together: 5 + 5 + 2*pi === > the length of the entire arch when "unrolled" 1 is the width and as usual, area of a rectangle is L*W so (5+5+2pi)*1 ==> area of the entire arch when unrolled, and thus the solution

princeevee:

alright

princeevee:

16.3

Mercury:

good

princeevee:

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Mercury:

good

princeevee:

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Mercury:

hm not quite we want the lateral surface area so pi*r^2 * h plug in r and h and pi

princeevee:

D

Mercury:

good

princeevee:

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Mercury:

hm not quite pi*r^2 * h check your calculations again

princeevee:

pi*2^2*11

princeevee:

B

princeevee:

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Mercury:

|dw:1530850554653:dw| the 4 lateral faces are the triangles which ~do~ meet at the vertex (apex) so the original statement is true

princeevee:

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Mercury:

|dw:1530850957549:dw|

Mercury:

if we try shading in this right triangle over here:|dw:1530851006546:dw|

Mercury:

we can see we have a right triangle with legs 15 and 20 (since the bottom leg is half the length of one side) use the pythagorean theorem to find the hypotenuse first

princeevee:

625

Mercury:

almost, remember the pythagorean theorem gives you the square of a side so we take the sqrt of 625 to get 25 as the hypotenuse with that being said we go back to the original pyramid:

Mercury:

|dw:1530851276994:dw|

Mercury:

now we can see each side of the triangle has height 25 and base 40 calculate the area of one triangle (using area = 1/2 * b * h) and multiply by 4 to get the lateral area

princeevee:

so 25?

princeevee:

no, 15

Mercury:

(1/2)bh * 4 = (1/2)(25)(40) * 4

princeevee:

75

princeevee:

right?

princeevee:

@Mercury

princeevee:

@sammixboo

Vocaloid:

Yo my wifi randomly cut out last night sorry about that :/

princeevee:

@vocaloid @Mercury that's alright, should we continue now though?

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