Question

i need some answers checked

Answer 1

@Vocaloid last day, my friend, we have to work fast, if that's okay with you

Answer 2

@Mercury

Answer 3

good

Answer 4

good

Answer 5

other way around (x moves across 5 units, y down 4 units) so x + 5 y + 4 choice the first

Answer 6

it asks which one is ~not~ true so its the one where the letters on both sides aren't in the same order (choice 4)

Answer 7

good

Answer 8

good

Answer 9

good

Answer 10

good

Answer 11

good

Answer 12

question is not well written but I believe they want a 90 degree clockwise rotation which means you would multiply the y-coordinates by -1 not the x-coordinates (see option 3)

Answer 13

note: your problem asks for a 90 degree clockwise which is the same as 270 clockwise

so the third matrix on this picture (fourth choice on your problem)

Answer 14

close

the original coordinates are (2,1) and the rule for rotating 180 degrees is to multiply both coordinates by -1

so (-2,-1)

Answer 15

check again

you have a 2 x 3 matrix and a 3 x 2 matrix, so we take the outer numbers 2 and 2 to get 2 x 2

Answer 16

had to look this one up tbh but it's perpendicular bisectors

https://www.illustrativemathematics.org/content-standards/tasks/1913

Answer 17

not quite

you need to multiply the first entries of each matrix together
then the second entries of each matrix together, etc. and add up all 4 products
so

8(16) + 4(12) + 1(10) + 5(13) = > plug this into a calculator and you'll get your solution

Answer 18

good

Answer 19

hm not quite, the pentagon has at least 5, you can draw one through each point

the arrow can be split horizontally and vertically
the star can be split along all of its points

leaving us w/ the trapezoid as the one w/ only one line of symmetry

Answer 20

hm not quite, 12 would be the lines of symmetry but order of rotation is a bit different

it's how many times we can rotate the figure (within a 360 rotation) and still get the same figure

for a regular hexagon like the windmill it's 360/6 = 6

Answer 21

good

Answer 22

funnily enough a parallelogram actually has 0

but if we take a square we can fold it lengthwise, widthwise, and across 2 diagonals giving us a total of 4 making square the best solution

Answer 23

hm not quite, this is like the hexagon problem except it's a heptagon so 7 sides --> order of rotation 7

imagine it like a wheel where every vertex is a spoke, it can rotate from one vertex to the next w/o changing its appearance

Answer 24

good

Answer 25

good

Answer 26

alright i've never heard of this in my life so i'm gonna have to look this up

Answer 27

i think it's either 22 or 23

Answer 28

alright so since we only have border points here and no interior points we just count the number of points and divide by 2

but there's honestly an easier method, just count the # of squares and then add 2 to that since those two triangles add up to 2

Answer 29

so 24

Answer 30

I get 24, you can double check me just to be sure

Answer 31

alright cool

Answer 32

good

Answer 33

good

Answer 34

(n – 2)*180 / n

plug in n = 11 to get the solution

Answer 35

147.2

Answer 36

@Vocaloid

Answer 37

previous one is 147.3 with correct rounding

Answer 38

for this one, a tangent is a line that touches the circle on the outer edge only

which can only be option 3

Answer 39

good guess but it only says the width doubles, not the length

so new width = 8

new area = 8 * 6 = 48

Answer 40

good

Answer 41

pay attention to the scale, we want the circle that touches (0,4) so it's the third one

Answer 42

<XYZ is on the edge so false

Answer 43

good

Answer 44

hm not quite, we have two angles given (90 and 32) and we know the sum is 180

so 180 - 90 - 32 = > the missing angle B

Answer 45

good

Answer 46

lateral area doesn't include the top and bottom faces
so false

Answer 47

(sorry, i'm trying to work a bit faster, because i only have an hour left,

Answer 48

for PQ it's half the given angle (218/2 = 109)

Answer 49

not 114

Answer 50

tan(27 degrees) rounds up to 0.510

Answer 51

sin is opposite/hypotenuse

for angle A that's h/c
therefore

sin(A) = h/c

h = csin(A)

Answer 52

for the parallelogram 2x + 5 = 13

solving for x gives

2x = 8, x= 4

Answer 53

good

Answer 54

we did this one earlier

21^2 = x^2 + (39/2)^2 gives us NK = 7.8

Answer 55

constellation one is good

Answer 56

sorry, i must've forgot, a bit of fog-o-war effect

Answer 57

some of this stuff i'm actually using a bit of memory to do, but i just want to check nonetheless.

Answer 58

not sure about the tesselation one tbh (let's just go with your answer)

Answer 59

angle of elevation one is good

Answer 60

good for both

Answer 61

for the dishwasher: prism, multiply the dimensions 2*2.5*3 = 15 not 37

Answer 62

for BZ the horizontal line is the horizontal distance -5 - (-9) is 4 not 5

Answer 63

last one is good

Answer 64

for the pyramid, lateral area is 4 * the area of a triangle or 4*(1/2)bh

so 4(1/2)(115)(90)

Answer 65

alright.

Answer 66

plotting the points on quadrilateral ABCD gives us a rectangle (using desmos)

parallelogram is a more inclusive term so parallelogram = your solution

Answer 67

third one is good then, right?

Answer 68

for the hexagon question the radius is one half the longest segment

so 9.8/2 = 4.9 not 3.55

Answer 69

good

Answer 70

the last one here i think is right.

Answer 71

wait no, it's A

Answer 72

for the sector ABC question

we know that a full circle is 360 degrees

so x + 2x + 3x + 60 = 360,
solving for x gives us x = 50

the radius of the circle is 5
so ABC = (50/360)*pi*5^2

Answer 73

for the cross section one, we got pentagon when we did this earlier as the solution

Answer 74

right, i remember that now.

Answer 75

not 100% sure about the center of a circle question (let's go with your answer for now)

for the "one point perspective" there's one vanishing point not 0 (hence the name)

Answer 76

good on both

Answer 77

angle of depression not angle of elevation, so it's the angle from the persons eye downwards

so the first choice is a better representation of the scenario

Answer 78

for the height of the building

tan(angle) = opposite/adjacent

tan(49) = x/42

plugging this into a calc gives x = 48.3

Answer 79

the angle of depression is taken from the horizontal

so the second one is a better representation

Answer 80

for the second building question

tan(angle) = opposite/adjacent

using the first triangle we get

tan(26) = x/220

plugging this into a calculator gives us x = 107.3

then add on 5.7 onto that to get the sol'n

Answer 81

let's start w/ the rollercoaster one

tan(x) = opposite/adjacent = 48/65

therefore x = arctan(48/65) which gives you 36.44 when you chuck it into a calculator

Answer 82

for the parking garage problem

we have opposite and hypotenuse so we use sin

sin(x) = 10/80

take the arcsin of both sides

x = arcsin(10/80) = > chuck this into a calculator and round to the nearest whole #

Answer 83

0.125

Answer 84

the parking lot is 7, your calc was probably in the wrong mode

Answer 85

for the airplane one, we use cos since we have adj and hyp.

cos(22) = x/18

x = cos(22) * 18 which is about 16.7

Answer 86

for the mountain one

consider each triangle separately

you have tan(theta) = opposide/adjacent

so the first half is

tan(14) = x/200

so x = 200*tan(14)

the second half uses the same logic to calculate

so y = 200*tan(26)

combined: x + y = 200*tan(14) + 200*tan(26) = 147