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Mathematics 16 Online
BRAINIAC:

Number Theory problem!

BRAINIAC:

Find the last 3 non-zero digits of 2015! .

jhonyy9:

this mean 2015 factorial ? so yes like an idea than you multiply 5 by 5 how many get ? hope little help you

BRAINIAC:

Nice idea! So this will help me to find the numbers of trailing zeros in 2015! which is equal to the exponent of 5 in its factorization which is: \([\frac{2015}{5}]+[\frac{2015}{5^2}]+[\frac{2015}{5^3}]+...=403+80+16+3=502\) Am I rite?

Zarkon:

No

BRAINIAC:

T_T Zarkon,can u show me how u do it?

Zarkon:

I don't know of a quick way to do this. You need to eliminate all powers of 5 in 2015! and a corresponding number of 2's. You could write a computer code to do it.

jhonyy9:

@BRANIAC DO YOU SEE indifferent how many time you multiply 5 by 5 allways will get the last number 5 - hope little help

imqwerty:

Competitive coding?

BRAINIAC:

Alright,zarkon. I found a calculator that can calculate big values,lol. Yes,I do,jhonny9. It seems that everytime you keep on multiply 5 by 5,u will always get the last number 5. Nope,imqwerty. Mathematics. ^

Zarkon:

you don't need to compute large values if you program it correctly

BRAINIAC:

I found another solution..hold on,I will post those workings here ^

BRAINIAC:

http://prntscr.com/k8o7j3

BRAINIAC:

http://prntscr.com/k7zied

BRAINIAC:

http://prntscr.com/k8o88y

BRAINIAC:

http://prntscr.com/k87r9a

BRAINIAC:

http://prntscr.com/k8o8kz http://prntscr.com/k881wb ----> second comment in the above link

BRAINIAC:

http://prntscr.com/k8o8yq

BRAINIAC:

http://prntscr.com/k8o972

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