Number Theory problem!
Find the last 3 non-zero digits of 2015! .
this mean 2015 factorial ? so yes like an idea than you multiply 5 by 5 how many get ? hope little help you
Nice idea! So this will help me to find the numbers of trailing zeros in 2015! which is equal to the exponent of 5 in its factorization which is: \([\frac{2015}{5}]+[\frac{2015}{5^2}]+[\frac{2015}{5^3}]+...=403+80+16+3=502\) Am I rite?
No
T_T Zarkon,can u show me how u do it?
I don't know of a quick way to do this. You need to eliminate all powers of 5 in 2015! and a corresponding number of 2's. You could write a computer code to do it.
@BRANIAC DO YOU SEE indifferent how many time you multiply 5 by 5 allways will get the last number 5 - hope little help
Competitive coding?
Alright,zarkon. I found a calculator that can calculate big values,lol. Yes,I do,jhonny9. It seems that everytime you keep on multiply 5 by 5,u will always get the last number 5. Nope,imqwerty. Mathematics. ^
you don't need to compute large values if you program it correctly
I found another solution..hold on,I will post those workings here ^
http://prntscr.com/k8o8kz http://prntscr.com/k881wb ----> second comment in the above link
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