Question

hey

Answer 1

@Vocaloid are you busy?

Answer 2

@Hero r u busy

Answer 3

@nuts hi please help us

Answer 4

@nuts @Hero hey guys please can u help

Answer 5

@ThisGirlPretty do u know math

Answer 6

Hey guys, and welcome to QuestionCove. What's up?

Answer 7

@sammixboo can you help us with math

Answer 8

Depends on the math! I can try. What's the question?

Answer 9

@sammixboo are u still online

Answer 10

@sammixboo I'm just waiting for @willa

Answer 11

@Vocaloid heyyyyy OMG

Answer 12

Can @willa post the question here..?

Answer 13

@Vocaloid are u online

Answer 14

please go easy on the tags, ok? what is the question?

Answer 15

@Vocaloid oh sorry

Answer 16

@vocaloid What is the sum of the probabilities in any probability distribution? is in infinite

Answer 17

let's use a simple example, flipping a coin. what's the sum of probabilities for all outcomes?

Answer 18

two

Answer 19

a coin has two sides, heads and tails

what is the probability of getting heads?

Answer 20

1/2

Answer 21

good, what about tails?

Answer 22

1/2

Answer 23

good, so the sum is 1/2 + 1/2 = 1 which is the case for any probability distribution

Answer 24

wait yeah it should be infinite

Answer 25

A store had a scratch-and-win promotion in which 1000 cards indicated 10% off, 50 cards indicated 15% off, 10 cards indicated 20% off and 1 card indicated 40% off. What is the expected value for a given scratch-and-win card? is it about 10.4 off

Answer 26

nvm it is

Answer 27

Kajan repeatedly rolled a die and he was getting frustrated that he could not roll his favourite number, which is three. What is the probability that the first three occurred on the tenth roll?

Answer 28

nvm

Answer 29

I got it

Answer 30

sooo soorrrry

Answer 31

@Vocaloid The student council is selecting six teachers to judge a talent contest. There are eight men and nine women available to be chosen. What is the probability that three men and three women are selected?

Answer 32

combination formula

nCr

considering the women alone we have 9 potential women and 3 women needed for the selection giving us 9C3

same logic with the men gives us 8C3

so 9C3 * 8C3

Answer 33

* meant to say 1 / (9C3 * 8C3) whoops

Answer 34

its the first one right I'm calculating it or trying to atleast

Answer 35

hm? why 6 in the numerator?

should just be 1 / (9C3 * 8C3), use wolframalpha.com or a graphing calculator

Answer 36

try to remember the combination formula

nCr = \[\frac{ n! }{ r!(n-r)!}\]

apply this logic to 9C3 and 8C3

Answer 37

what does n mean again

Answer 38

the total population being selected from. for the women, for example, we have 8 women and we select 3 so for 8C3, n = 8

Answer 39

how do u use the website u gave me

Answer 40

the binomial distribution involves counting successes in a specific number of trials; the hypergeometric distribution involves waiting time until success

Answer 41

is that the key difference @Vocaloid

Answer 42

plug in 1 / (9C3 * 8C3).

Answer 43

@Vocaloid um i think the answer is

Answer 44

I meant that

Answer 45

you can't just add the n and r values

just try plugging in n = 8 and r = 3 into the combination formula to get the value of 8C3.

Answer 46

A bag contains 8 red, 7 green, 5 black and 10 yellow jelly beans. Six jelly beans are selected at random without replacement.

What is the probability that all six jelly beans are red? its

Answer 47

@Vocaloid yeah the answer is 56

Answer 48

C(n,r)=C(8,3)
C
(
n
,
r
)
=
C
(
8
,
3
)
=8!(3!(8−3)!)
=
8
!
(
3
!
(
8
−
3
)
!
)
= 56

Answer 49

good now try finding 9C3

Answer 50

84

Answer 51

I only have three options tho @Vocaloid

Answer 52

4***

Answer 53

hm. then (8C3 * 9C3)/(17C6) is the best solution th en

Answer 54

jellybean problem is correct

Answer 55

binomial vs hypergeometric, both involve repeating trials until a certain desired outcome is achieved, but with binomial distribution the probability of each success/failure remains the same while in hypergeometric the probability changes based on previous outcomes

Answer 56

the binomial distribution involves independent trials; the hypergeometric distribution involves dependent trials

the binomial distribution involves dependent trials; the hypergeometric distribution involves independent trials

the binomial distribution involves counting successes in a specific number of trials; the hypergeometric distribution involves waiting time until success

the hypergeometric distribution involves counting successes in a specific number of trials; the binomial distribution involves waiting time until success

Answer 57

I think its the last one

Answer 58

"while in hypergeometric the probability changes based on previous outcomes"

this points to the idea that the trials in hypergeometric situations are dependent

Answer 59

can u explain more

Answer 60

hey can someone help me with this questino?
A brown-eyed father and a green-eyed mother have a 25% chance of having a green-eyed child. What is the probability that, in a family of four children, three of them have green eyes?

Answer 61

let's go back to the basic definition of independent vs dependent

Answer 62

also can we not interrupt other people's questions, thanks ~

Answer 63

sorry:o

Answer 64

anyway, independent events means that the outcome of one trial doesn't influence the others, right?

and for dependent events, the outcomes do influence the outcomes of other trials, right?

applying this logic to binomial distributions and hypergeometric distributions,

binomial distributions involve a series of trials that are independent b/c the probabilities of success/failure are not influenced by the other trials
hypergeometric distributions involve a series of trials that are dependent b/c the probabilities are influenced by the other trials

that being said which choice is the best option?

Answer 65

ohhh so hype always depends on the bio

Answer 66

okay got it

Answer 67

also u can help penny she seems in distress

Answer 68

:) i just have this one question left if your done helping jamie vocaloid can you please help

Answer 69

which choice do you think it might be?

Answer 70

What is the sum of the probabilities in any probability distribution? is it 2

Answer 71

because it must be equal or infinite

Answer 72

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
good, so the sum is 1/2 + 1/2 = 1 which is the case for any probability distribution
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 73

Thanks vocaloid for all the help we really appreciate it, sorry for the load of questions we brought to you....you were a great help to us!!<3

Answer 74

*miku voice*
Thank youuuuuuuuuu>.<