Which series of transformations on figure 1 can be used to show that the figures are congruent ?
What is figure 1?
@Vocaloid
if this is like a graded test I'm not sure I can answer this and abide by the rules of the site
oh no it's look like that
that's how our assignments look like that
crop image
i can't that's only picture i have
well in any case you would just go through the answer choices one by one and see which transformation produces the image
B.
that's a good guess but a clockwise rotation would make the image look like this|dw:1534200831177:dw|
thoughts on C or D?
C cause it's makes sense coming from your example
good, C
i think the answer is A,B or D
but i personally think it's B
i might be wrong
hm not quite since all the x-values are linear (increasing by the same amount/decreasing by the same amount each time) we only need to check the y-values so see which answer choice has the y-values change by the same amount each time (adding the same amount or subtracting the same amount)
A or C to me
hm not quite let's look at the y-values of A it goes from 2 to 1, so that's subtracting 1 it goes from 1 to 0, still good, subtracting 1 again but it goes from 0 to 1, that's adding, not subtracting, so it's not linear same reasoning with C have you tried looking at D yet?
D seems to appears for subtracting
well, since it goes from -5 to -7/2 that's adding 3/2 going from -7/2 to -2 that's also adding 3/2 same thing from -2 to -1/2 and -1/2 to 1 so since the same value is being added each time D is linear and thus the appropriate solution
this question i've had a problem cause it asks what are the areas of the squares now i could be but i'm suggesting that the answer is C
|dw:1534201490632:dw| sorry for the crappy diagram but let's pretend all the pink shapes are squares and the center is a right traingle
|dw:1534201538896:dw|
the side lengths of the three squares are thus, 16, 20, and 12 since area = side length^2 what will the three areas be?
B
good
I PICKED CAUSE I BELIEVE THIS IS THE CORRECT ANSWER
A
hm, not quite, let's try completing the square first step: we start with the x term (36x), take 36, divide by 2 to get 18, and square it to get 324 we can then take the original expression x^2 + 36x = 88 and re-write this as x^2 + 36x + 324 = 88
do you know how to then, factor the left side x^2 + 36x + 324?
** made a typo, should be x^2 + 36x + 324 = 88 + 324 since we need to add 324 to both sides
C
good
any ideas? as a hint they both have the same side lengths just in different orientations
A
good attempt but a reflection won't do it, it has to be a rotation judging by how they're positioned should it be a 90 degree or a 180 degree rotation?
90 degree
good so B is the best sol'n
|dw:1534202515252:dw| so if a^2 + b^2 = c^2 where a b and c are the lengths of the squares what do you think might be the best way to prove the theorem?
write down all givens and
well, if c^2 = a^2 + b^2 we are adding the areas of the two squares, right? so which answer choice best reflects this idea?
C
good
non-linear = not a perfectly straight line = which answer choice do you think it might be?
B
hm not quite if you look at A there's a decrease of 1 unit by 1 unit but then it decreases 1 unit for every 4 x-units so A is the one that's not a perfectly straight line, so A is the best solution in this case
i just figured out the answer is D
hm? I think the shapes are congruent, if you look at the dimensions they both have the same side lengths
which should narrow us down to A and C
so the answers is A
hm not quite, a 180 rotation would look like this|dw:1534203132142:dw| if you go through the transformations choice C would be the better option
for the pythagorean question, remember that the shapes must be three squares surrounding a right triangle
rectangles don't count
D
hm not quite, notice how D has a rectangle that is 4*5 see how choice B has a 3*3 square, a 4*4 square, and a 5*5 square? choice B is the only viable option in this question
any ideas? as a hint which one can you re-write in y = mx + b form?
A
good
I thought about C
good attempts but not quite let's start w/ what we have x^2 = 6x + 12 we can subtract 6x from both sides to get x^2 - 6x = 12 again, when completing the square, we take the x term (-6x), divide -6 by 2, square the result to get (-6/2) = -3 and (-3)^2 = 9 and add 9 to both sides x^2 - 6x + 9 = 12 + 9 can you try factoring the left side and see which answer choice best fits this equation?
how do you factor (x^2 - 6x + 9)? as a hint try picking two numbers that add up to -6 and multiply to get 9
x^2 - 6x + 9 factors into (x-3)^2 right? so (x-3)^2 = 12 + 9 = 21 making B the best choice
RIGHT
basically you just want to pick the choice where the two shapes aren't congruent since the original question states the two triangles are congruent and it wants the one that is impossible
that's easy D
good
for a nonlinear function look for a choice where x has an exponent other than 1
D
good
well as stated before the squares should have side lengths that are equal to the sides of the triangle that being said which choice makes the most sense? the side lengths of the triangle are 6, 8, and 10
B
good
well let's start by applying the distributive property to x(x-5) first, what do you get? remember that A(B-C) = A*B - A*C try applying this logic to x(x-5)
B or D
D
x(x-5) = x^2 - 5x giving us x^2 - 5x - 10 = 0 completing the square x^2 - 5x + 25/4 = 10 + 25/4 which does factor into D
well let's start by eliminating choices do you think 11x - y = 15 is linear or nonlinear?
linear
awesome so that immediately eliminates C and D between A and B which one do you believe is the more accurate/better reasoning?
B
awesome, so B is the best solution
well let's start by eliminating choices again are shapes F and G congruent?
NO
hm, are you sure? they're both circles w/ diameter 4 and both have a quarter cut out of them remember that rotations of the same shape are still considered congruent that being said what might the best choice be?
oh i'm sorry it is i didn't look right
A
good would you mind closing this question and opening a new one for your next questions? this thread has over 100 replies and its lagging a bit
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