Square P, square Q, and square S are drawn
well going off of the pythagorean theorem c^2 = a^2 + b^2 where c is the biggest side try applying this logic to sides Q, P and S where Q is the biggest side
B
hm not quite Q^2 = P^2 + S^2 so Q^2 is the sum, not half the sum making A the better choice
good
A is correct ?
yes
D
hm not quite if you put the triangles together you get 2 squares, right? so in total we have 2 + 4 = 6 squares with side length 5.9, what would be the total area?
B
area of a square = side length^2 right? so 6 squares of side length 5.9 = 6 * 5.9^2 = ? be careful w/ order of operations
C
209
good
volume of cone = pi * r^2 * h so plugging things in gives us 16875pi = pi * r^2 * 25 solve for r
25m^2
hm check again pi cancels out on both sides right? so 16875 = r^2 * 25 you can divide both sides by 25 to get 16875/25 = r^2 then simply take the square root of both sides to solve
D.
16875/25 = r^2 675 = r^2 r = sqrt(675)
B
good
a^2 + b^2 = c^2 where a and b are the legs, and c is the hypotenuse therefore 12^2 + b^2 = 37^2 solve for b
35, -35
good since we are talking about the side lengths of a triangle we would only consider the positive value 35 to be the solution
f
forget the F
the three angles make up a perpendicular angle right? so x + 2x + 42 = 90 first, solve for x
16
good now, it wants the angle <QTR which equals 2x so 2x = 2 * 16 = 32 = your solution
d
hm not quite it says he wants to prove that "the exterior angle is equal to the sum of the two remote interior angles", right? in this case exterior angle = x and two remote interior angles = p and q so he must somehow prove that x = p + q
B
hm not quite let's try looking at choice A he starts with the original two statements he makes (p + q + r = 180 and x + r = 180 and uses them to prove that x = p + q, right? so choice A is the most logical solution here
if we try drawing a right triangle between points G and H such that GH is the hypotenuse we get |dw:1534207440977:dw|
using the pythagorean theorem 5^2 + 10^2 = GH^2 solve for GH round to the nearest tenth
5.0
D
hm not quite remember order of operations, exponents before addition so 5^2 + 10^2 = GH^2 becomes 25 + 100 = GH^2 125 = GH^2 so GH = ?
hm not D either, check your calculations again
Fg = 125/h^2
GH
let's replace GH with a generic variable x x^2 = 125 x = ?
5√5
C
good, C
the third side of any triangle must be larger than the sum of the two other sides so the third side must be larger than (9+37) and there's only one choice that satisfies this requirement
C
hm not quite 9 + 37 = 46 so the answer must be larger than 46
D. 54
good
we can set up a proportion where 2 inches/7 feet = 3 inches/x feet and 2 inches/7 feet = (2 + 1/2)/y feet solve for x and y
B
good
well we have two points (0,5) and (-4,0) try to apply the slope formula on these two points (y2-y1)/(x2-x1) where x1 = 0 x2 = -4 y1 = 5 y2 = 0 (taken from the coordinates of the two points)
A.
hold on
i think A
i think that's correct
hm not quite, you might have switched the numerator and denominator using the slope formula gives us (5-0)/(0 - (-4)) which simplifies to 5/4 not 4/5 so B is the better solution
any ideas? as a hint you are ~not~ given any information about the sides so you can only use the angle measurements as part of the proof
C
B and D are out of the picture
good, C
wait
actually I believe B might be a better choice you have two pairs of angles (<L + <J) and (<R + <P) that are said to be congruent which implies the third must also be congruent making the two triangles similar C is insufficient b/c knowing the angles sum to 180 doesn't necessarily prove similarity
weird question
this next question is kind of a pain in the butt but you have to draw lines from the origin to each point and calculate the length using the pythagorean theorem
as a hint let's start w/ point D and work our way backwards if you draw a line from pt D to the origin you get |dw:1534209192806:dw|
so if we have a right triangle with legs 3 and 2, and hypotenuse equal to the distance between D and the origin we have D^2 = 3^2 + 2^2 solve for D leave your solution in radical form
sqr13
good and that matches the original question so D is the best solution
this is kind of a pain but you have to split the shape into its three component rectangles
|dw:1534209523757:dw|
|dw:1534209566315:dw|
A is simple, it's a 12 * 4 rectangle which has area 48 sqr inch. since 12 * 4 = 48
for B, it has width 2 but we need to figure out the length by looking at the other sides of the shape |dw:1534209667884:dw|
if the total length is 12 and the length of that side on the right is 5 thus x + 5 = 12 what must x, the side length of B, be?
7
good so B is a 5 * 2 = 10 sqr inch rectangle lastly rectangle C the bottom side is 12 as indicated by the drawing but we don't know what the width is yet
|dw:1534209808400:dw|
the total width of the entire shape is 10 the two segments on the right side are 4 and 2 so 4 + 2 + y = 10 solve for y, the width of rectangle C
4
good so the last rectangle is a 4 * 12 rectangle, or 48 inch sq adding up all the area gives us 48 + 48 + 14 = 110 sqr inches however it wants the area of the real garden not the drawing so we must use the conversion factor they give us if 1 inch = 3 feet then 1 inch^2 = 3^2 feet, or 9 feet ^2 so total area = 110 * 9 = 990 ft^2 = choice C
so as stated before, any side of a triangle must be greater than the sum of the other two sides so for example, we can try choice A to see if it works 9 < 9 + 9 in all cases, so A is eliminated try testing this logic for choices BCand D
*just had to correct a small typo
C
hm not quite 9 + 12 > 15 9 + 15 > 12 12 + 15 > 9 so c is a valid triangle try choice D 9 + 12 > 25 is this a true statement?
no false
good so d is not a triangle making D the best solution
you must use the quadratic formula for this one for a generic equation ax^2 + bx + c = 0 the quadratic formula is given by |dw:1534210678262:dw| so for your equation 2x^2 + 13x - 1 = 0 identify your a, b, and c values and plug them into the formula ** be careful with positive/negative signs **
a = 2, b = 13, c = -1
good, then just plug them into the quadratic formula
D
good
well since it crosses (0,0) that means it must be y = mx with no b value which eliminates choices C and D to decide between A and B let's pick point (3,5) and plug them into y = mx 5 = m(3) m = ?
5/3
good so y = (5/3)x which is choice A
two intersecting lines create two pairs of equal angles therefore 8x - 4 = 110 solve for x
57/4
good but the answers are in decimals so 57/4 = 14.25 = your solution
|dw:1534211440516:dw| so we have a right triangle with legs 6 and 5 and hypotenuse LM so 6^2 + 5^2 = LM^2 solve for LM
61
close, that's LM^2 so LM is just sqrt(61) d
to find out how many cones he can make he will calculate volume of clay cube/volume of each cone tree volume of a cube is s^2 where s = the side length = 3 inch volume of a cone = (1/3) * pi * r^2 * h where h = height = 2 and radius = 0.75 inches (since the diameter is given as 1.5, divide by 2 to get 0.75 as the radius) with that being said calculate volume of clay cube/volume of each cone tree
ugh made a typo volume of a cube is s^3 not s^2
anyway we can break it down into steps if volume of a cube = s^3 and s = 3 inch then volume = ?
did you get a solution for part A yet?
3
3 is a bit too low volume of the cube is 3^3 = 27 inch^3 volume of the cone is (1/3) * pi * r^2 * h = (1/3) * pi * (0.75^2) * 2 so volume of cube/volume of cone = ?
1.17
27/((1/3) * pi * (0.75^2) * 2) = 22.9 when i chuck it into a calculator we round down to 22 since we only want to know how many complete trees he can make so for part A, 22 trees = your solution (make sure to show all your calculations)
sqr2
that's it for B
but could i rewrite for part A i'm a bit confused
the artist wants to know how many trees he can make with his cube to find that, he must divide volume of cube/volume of one tree so simply show the calculations for the volume of the cube and the volume of the tree
also we may need to re-do part B because it wants an actual equation. hm.
yeah sorry I kind of misunderstood what part b was asking whoops but in the meantime are you making any progress with part A?
@mikewwe13 still there?
Part A to find out how many cones he can make he will calculate volume of clay cube/volume of each cone tree volume of a cube is s^3 where s = the side length = 3 inch volume of a cone = (1/3) * pi * r^2 * h where h = height = 2 and radius = 0.75 inches (since the diameter is given as 1.5, divide by 2 to get 0.75 as the radius) with that being said calculate volume of clay cube/volume of each cone tree we round down to 22 since we only want to know how many complete trees he can make then, volume of the cube is 3^3 = 27 inch^3 volume of the cone is (1/3) * pi * r^2 * h = (1/3) * pi * (0.75^2) * 2 so volume of cube/volume of cone = 22 so that would be 22 trees Part B the artist wants to know how many trees he can make with his cube to find that, he must divide volume of cube/volume of one tree so simply show the calculations for the volume of the cube and the volume of the tree
am i correct ?
make sure the steps are logical and concise and you're not just copy-pasting things I've said (that can set off plagiarism detectors and that's no fun) you just need to show: 1) # of trees = volume of cube/volume of cone 2) the calculations for the cube volume 3) the calculations for the cone volume 4) the calculation for dividing cube volume/cone volume 5) rounding down to 22
also part B is asking something entirely different, erase what you have so far for part B
FOR A i'm good ?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid make sure the steps are logical and concise and you're not just copy-pasting things I've said (that can set off plagiarism detectors and that's no fun)
no into my own words
the content itself is fine
Part A First, to find out how many cones he can only make he will have to calculate the volume of clay cube/volume of each cone tree the volume of a cube is s^3 where s = the side length = 3 inch the volume of a cone = (1/3) * pi * r^2 * h where h = height = 2 and radius = 0.75 inches (since the diameter is given as 1.5, divide by 2 to get 0.75 as the radius) with that being said calculate volume of clay cube/volume of each cone tree we round down to 22 since we only want to know how many complete trees he can make then, volume of the cube is 3^3 = 27 inch^3 volume of the cone is (1/3) * pi * r^2 * h = (1/3) * pi * (0.75^2) * 2 so therefore the volume of cube/volume of cone = 22 so that would be 22 trees
that's in my words
they not gonna know anyway but i want to be fair
and you're right
good but you don't need this sentence "with that being said calculate volume of clay cube/volume of each cone tree" the sentence "we round down to 22 since we only want to know how many complete trees he can make" needs to be before "so therefore the volume of cube/volume of cone = 22"
otherwise its fine
i could leave that out
anyway for part B idek what they want but here's my best attempt x = the height of the tree since each piece of yarn goes from the top to the base volume of cone = (1/3) * pi * r^2 * x = (1/3) * pi * (0.75)^2 * 2 from the part A calculations solving for x gives x = 2 inch = the length of each piece
ok
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