Question

Let f(x) = 7x − 13. Find f−1(x).

13x − 7
7 over quantity of x plus 13
quantity of x plus 13 over 7
1 over quantity 7 x minus 13

Answer 1

So in this problem we're trying to find the inverse of the original function. This means, if we plug b into f(x) and get c, we should also get b when we plug c into f-1(x)

Answer 2

urmmmmm .................

Answer 3

Basically, every operation in the original function should be reversed, in order for this to be true

Answer 4

So, if you multiply x by 7 and subtract by 13 in the original...

Answer 5

you'd do the opposite of multiply and the opposite of subtract in the inverse

Answer 6

for instance, instead of subtracting 13 from x, you'd add 13 to x,
and instead of multiplying by 7, you'd divide by 7

Answer 7

i still confused

Answer 8

oh, did you mean this?\[f^{-1}(x)\]

Answer 9

Because if you have that, then you just flip the x and y values (and \(f(x)=y\), usually).
So then \(f(x)=7x-13=y\), and the inverse (the \(f^{-1}(x)\) part) would be:\[x=7y-13\]

Answer 10

i think the answer is a

Answer 11

its the only one that seems logical to me atleast

Answer 12

So you solve for y from the new equation (someone correct me if I interpreted the question wrong...)\[x=7y-13\]\[7y=x+13\]\[y=\frac{1}{7}x+\frac{13}{7}\]

Answer 13

the algebraic way to do it is to 'switch' y's for x's and vice versa. Then you solve for y again to get your inverse function