More help
@dude
PEMDAS
Parenthesis, Exponents, Multiplication and Division left to right, Addition and Subtraction left to right
Please Excuse My Dear Aunt Sally
Right

So start with parenthesis
4 * 6 = 24
Yes
Essentially exponents (not scientific notation) works like this 3^2 = 3 * 3 3 times 3 for a total of two times 3^3 = 3 * 3 * 3 3^4 = 3 * 3 * 3 * 3 Do you see how it works?
Yeah but the negatives are like 3^-1
Now when you have the negative number in the exponent (that's what that tiny number on top is called) you have to do a flip 2^(-1) -1 is the exponent 2 is the base 2^-1 = 1/(2^1) 2^(-2) = 1/(2^2)
Use latex
So basically what you do when you have a negative is that you make it a fraction with 1 on top and put the thing on the bottom with a positive exponent
I would but I'm too lazy to do it
What's latex?
\(\LaTeX\)
\(\Large \sf \color{red}{a}^{\color{blue}{b}}\) a is the base b is the exponent
Okay
\(\Large \sf a^{-b} = \frac{1}{a^b}\)
\(\color{#0cbb34}{\text{Originally Posted by}}\) @TheSmartOne Now when you have the negative number in the exponent (that's what that tiny number on top is called) you have to do a flip \(2^{-1}\) -1 is the exponent 2 is the base \(2^{-1} = \frac{1}{2^1}\) \(2^{-2} = \frac{1}{2^2}\) \(\color{#0cbb34}{\text{End of Quote}}\)
OHHHH
Do you see how the negative goes away and that piece goes in the denominator
Yeah
Yeah
Then you're all set
\[3^{-1} = \frac{ 1 }{ 3^{1} }?\]
bingo
So just put that in the box?
Well multiply all the stuff and follow pemdas and simplify it down
\[0.999999999999\]
Right?
Uhhhhhh don't convert the fractions in to a decimal Just leave them as a fraction and you'll get a nice number that's correct but for now just round that number to the nearest whole number to get the correct answer 0.999999 isn't really correct but bc you made it into a decimal you got that nice long repeating decimal
So what is it?
think of wha he said west
Are you kidding me
For now, just round \( 0.\overline{999}\) to the nearest whole number
No asking for answers ( ͡° ͜ʖ ͡°)
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