MATH TUTORING NEEDED
Do you have a question? e.e
not really its more i have a algerbra DBA and i need to get the hang of the order of operations and other things so i can do well cause i SUCKKKKKKK at algerbra
ill go to the review test and put the questions i got wrong here so we can show me how to do dem
Ooooooooo The teacher probably has a study guide on her/his homepage. c: On the modules' study guide, it will show most questions the teacher will ask. cx
thx elsha ill look at it but i still would like a little practice and help here
Hehe, das all I know. e.e
he just had vocab review so i need help here e.e
@SmokeyBrown
Errything should be mentioned in the lesson. BREH My Algebra teacher only asked me about vocabulary. cx But there was one question that wasn't vocabulary... e.e Eh, I dunno. Hai derr, Smokey. :D
hewwo owo
elsha i clearly know there is stuff in the lesson it doesnt change i need help Understading it and being able to do it e.e
Hi smokey can you help me out like give me some questions i can do my best to answer
Things im not good at that i need help with is f(g(x))
Hey sure thing. When you're doing f(g(x)) problems, you wanna take the 'x' in the 'f(x)' equation and replace it with the entirety of the 'g(x)' equation. So, like, if f(x)= x^2 and g(x) = x + 1, f(g(x)) = (g(x)^2), or (x+1)^2
ok
that makes it look less confusing could you give me a question and ill answer it
Yeah sure thing, try this one \[f(x)=\frac{ 2 }{ x }\] \[g(x)=4x ^{2}\] \[f(g(x))=?\]
\[f(g(x))=\frac{ 2 }{ 4x^2}\]
?
Yeah, exactly. You can also simplify a bit more, since the numerator and denominator have a common factor of 2
._.
how do i do dat
im not good at fractions xD
Oh, see, 2/4 is equal to 1/2 when simplified, so 2/4x^2 would be equal to 1/2x^2
ohh ok
give me another question i wanna try it andsee if im getting better
Sure thing, try this one \[f(x)=\sqrt{x}\] \[g(x)=9x ^{2}\] \[f(g(x))=?\]
._.
\[f(g(x))=\sqrt{9x^2}\]
?
am i right
Yeah, you got it. You can still simplify the expression a bit. Keep in mind that the part inside the square root is a perfect square.
\[g=\frac{ 3 }{ f }\]
Like this ^
I'm not really sure what you mean by that?
i tried to simplifying it more like you said
and im alittle confused i put this in a calculator \[f(x)=\frac{ 2 }{ x } , g(x)=4x^2 \] and it equaled \[f(4x^2)=\frac{ 1 }{ 2x^2}\] Is that still correct
Oh, yeah, that's definitely correct, since 2/4 is equal to 1/2, right?
yes
Yeah definitely. Remember, how 2/4 is equal to 1/2?
yes
Yeah, so 2/4x^2 = 2/4 * 1/x^2 = 1/2 * 1/x^2 =1/2x^2
ohhh ok what about the f(4x^2) = is that the same thing as f(g(x))=
Yeah, that's right. Since g(x)=4x^2, you can replace g(x) with 4x^2
ok
ok i need help with this its a question from the review i did but didnt get it right and i need help so i can understand it and get it right next time
^the question ill put what it says here The number of fish (f) in a fish tank increases when the number of algae blooms (a) decreases. Write the correct equation for this scenario, and solve for the number of fish when there are 4 algae blooms.
Ok, I see. So, f = 1a makes sense, when a=10 and f=10 But then, another data point says that when a=25, f=4 So, from this, we know that f can't be equal to a all the time. Does the other option make sense? f = 100/a
wait so f=1a but A=10 and f=10 so it would look like 10=110? then there is a=25 f=4 so it would look like 4=125?
Oh I think 1a means 1*a, or just 'a', for simplicity's sake.
so 10=10 and 4=25
Right, but only the first of those makes sense. 4 can't be equal to 25, see. Now, if we try the other option, f=100/a 10 = 100/10, which is true 25 = 100/4, which is true So that equation represents the pattern we see better
*gasp* WAIT DOES THAT MEAN THE ANSWER IS f= 100 over a = f = 25
Oops, I meant 4=100/25, but you understand
Yeah, that's right. If you use that equation, then f would be 25 when a is 4, for just the reason you just described
ok i pretty much got the answer bc i knew it was 100 over a and then f=25 so it wouldnt be D were f= 400 Ok im understanding more now
can you give me another question
Yeah sure thing uhhhh Hey, here's a guide with a bunch of practice problems at the bottom. You can practice with that. http://www.mesacc.edu/~scotz47781/mat120/notes/composition/composite_functions_intro.pdf
^ Wisdom
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