Question 2: CHECK MEH WORK
Q2: rewrite in simplest radical form 1 over -3 over x6 Show each step of your process
1 over -3 over x6 fraction rule 1 over 3 -over 6x Fraction rule 1 -over 3 over 6x = -6x over 3 = -2x
@dude
cant figure out how to use the equation thing so
|dw:1536179807741:dw|
i did my best drawing it to make it easier to understand but im bad at drawing e.e
\[1/(-3)/(x^6) = \] do you think it in this form ?
what?
no the question shows it in this form |dw:1536180113909:dw|
i suck at functions so a double function im like RIP e.e
use the rule of fractions 1 b --- = --- do you know it why ? a a --- b
im so confused by "do you know it why"
when you dicide two fractions so you can multiply the first fraction with secons inversed
divide two fractions
do you know this rule of fractions ?
urmmmmmmmmmmmm no?
i dont think i do cause this is all confusing
not is really - this is easy just use this what i ve wrote above
but i thought i already did
my original comment i took the negative and moved it to a different spot
|dw:1536180695932:dw|
\[\frac{ -a }{ b }\] \[\frac{ a }{ b }-\]
\[\frac{ \frac{ 1 }{ -3 } }{ x6 }\] to \[\frac{ \frac{ 1 }{ 3 } }{ 6x }-\] to \[\frac{ \frac{ 1 }3{ -} }{ 6x }\] to \[\frac{ -6x }{ 3}\]
to -2x
YESH FINALLY FIGURED OUT THAT EQUATION THINGY
@dude am i correct
try rewriting every fractions simplified in this form how i ve wrote to you above
1
do you can rewriting the second and the 3rd fractions so simplified like first ?
first fraction is (-x^6)/3
Your confusing me with the whole "do you can rewriting"
Ok \[\frac{x^6 }{ -3 }\]
@ThisGirlPretty please help understanding the way
the second fraction how will be simplified ?
.....
I think he's asking do you think you can convert the second and third fractions into simplest form like the first one
the second will be : 1/(-3/(6^x)) = (6^x)/(-3) = (-6^x)/3
Im SO CONFUSED there is only 1 fraction \[\frac{ \frac{ 1 }{ -3 } }{ x6 }\] i dont get were this third and second fraction are coming from
there are 3 fractions first divide second divide 3rd
were?
I think he's talking about the 3 fractions in the problem(post)
in the post thats my answer not the question the question is this^^^
omg. this is allllll different how you wrote firstly
No the question says "check my work" so i put my work \(\color{#0cbb34}{\text{Originally Posted by}}\) @AnimeGhoul8863 1 over -3 over x6 fraction rule 1 over 3 -over 6x Fraction rule 1 -over 3 over 6x = -6x over 3 = -2x \(\color{#0cbb34}{\text{End of Quote}}\)
x^(-3/6) = ?
i drew it so people would understand what it looks like
do you know this x^(-1) = ?
\[\frac{ 1 }{ x }\]
exactly - so us this rule of negativ exponent in case of your exercise
exercise?
problem
do you know how is the exponential form of squarroote ?
ok. sqrt x = x^(1/2) cuberoote x = x^(1/3)
do you see the index of radical allways is the denominator of exponent
@ThisGirlPretty do you understand it now ? please
Yes I do
sqrt x = x^(1/2)
where 2 is the index of radical
cuberoot x = x^(1/3) ok ?
ok?
these all you just need using in case of your above wrote problem
ok im sorry Jhonyy but im to confused im gonna ask someone to come and help
@563blackghost
ok sorry this is easy just us these rules
\(\color{#0cbb34}{\text{Originally Posted by}}\) @AnimeGhoul8863 \[\frac{ \frac{ 1 }{ -3 } }{ x6 }\] to \[\frac{ \frac{ 1 }{ 3 } }{ 6x }-\] to \[\frac{ \frac{ 1 }3{ -} }{ 6x }\] to \[\frac{ -6x }{ 3}\] -2x \(\color{#0cbb34}{\text{End of Quote}}\) I just need someone to check this is it correct
from x^6 how you get 6x ?
ohhh i see it now what you ve confused (-3/6) is the exponent of x
typo \(\color{#0cbb34}{\text{Originally Posted by}}\) @AnimeGhoul8863 \(\color{#0cbb34}{\text{Originally Posted by}}\) @AnimeGhoul8863 \[\frac{ \frac{ 1 }{ -3 } }{ x^6 }\] to \[\frac{ \frac{ 1 }{ 3 } }{ x^6 }-\] to \[\frac{ \frac{ 1 }3{ -} }{ x^6 }\] to \[\frac{ x^6 }3{ -}\] \(\color{#0cbb34}{\text{End of Quote}}\) I just need someone to check this is it correct \(\color{#0cbb34}{\text{End of Quote}}\)
that looks right
is that all i have to do to get the question right?
@563blackghost please she confused the exponent of x
You applied the fraction rule correctly both times. You used: \(\large\bf{\frac{a}{-b} = -\frac{a}{b}}\) and \(\large\bf{\frac{1}{\frac{b}{c}}=\frac{c}{b}}\)
x^(-3/6) = 1/6index radical ofx^3
so its not x^6?
but x^-3/6?
yes and so this mean that 6 id the index of radical
\[x^\frac{ -3 }{ 6 }\]
mhm
@563blackghost do you understand me now ?
yea
\[\frac{ \frac{ 1 }{ -3 } }{ x^6 }\] to \[\frac{ \frac{ 1 }{ 3 } }{ x^6 }-\] to \[\frac{ \frac{ 1 }3{ -} }{ x^6 }\] to \[\frac{ x^6 }3{ -}\] to \[x^\frac{ -3 }{ 6 }\]
So it would look like this ^
1/x^(-3/6) = ?
huh?
this is the original problem
\[\frac{ 1 }{ x^\frac{ -3 }{ 6 } }\]
so this is the original equation?
You first start with \(\large\bf{\frac{1}{x^{\frac{-3}{6}}}}\) This is your question. You start your problem here.
first you need simplifie x^(-3/6) = ?
WHAT?!?!?!?! i answered the question just to create the question you guys just made me 10000000000% confused
-3/6 is the power of x
*shoots self in head*
You first start with: \(\Large\bf{\frac{1}{x^{\frac{-3}{6}}}}\) This is your question. You start your problem here. ~~~ Now you need to simplify the given fraction. \(\bf\large{\frac{-3}{6} ~simplifies~ \rightarrow - \frac{1}{2}}\) So you go from: \(\Large\bf{\frac{1}{x^{\frac{-3}{6}}} \rightarrow \frac{1}{x^-{\frac{1}{2}}}}\)
how you get 1/3 from there ?
where the -1/2 mean the exponent of x
ok Ghosteh so once we have \[\frac{ 1 }{ x \frac{1 }{ 2 } }\]
we simplify again
make sure it includes the -
i tried but it wouldnt add to it this equation thing is hard to work with
so if were converting it to Radical form it would be \[\frac{ \frac{ 1 }{ 1 } }{ \sqrt{x} }\]??????
yes you do. You apply another fraction rule. \(\large\bf{\frac{1}{\frac{b}{c}}=\frac{c}{b}}\) \(\Large\bf{\frac{1}{x^{\frac{1}{2}}} \rightarrow \frac{x^{\frac{1}{2}}}{1} \rightarrow \color{red}{x^{\frac{1}{2}}}}\)
Ok so the answer is x^1/2
radical form? I thought we were just simplifying. If radical form then its acutally: \(\Large\bf{a^{\frac{x}{n} = \sqrt[n]{a^{x}}}}\) You first need to change your exponent fraction into positive. \(\large\bf{a^{-b} = \frac{1}{a^{b}}}\) \(\Large\bf{\frac{1}{x^-{\frac{3}{6}}} \rightarrow \frac{1}{\frac{1}{x^{\frac{3}{6}}}}}\) Then apply the formula. \(\Large\bf{ \frac{1}{\frac{1}{x^{\frac{3}{6}}}} \rightarrow \color{red}{ \frac{1}{\frac{1}{\sqrt[6]{x^{3}}}}}}\)
^the question
I know. I just typed out the explanation for the answer.
ok so add the radical form or no
I thought we were just simplifying not changing to radical form. Ye the explanation above is converting it to radical form.
i think its just simplifying
So simplifying and radical form?
e.e
simplify
Remember how I said the answer is \(\Large\bf{x^{\frac{1}{2}}}\)?
i gtg thx for the help Ghost and Jhony
np.
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