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Mathematics 14 Online
AnimeGhoul8863:

Question 2: CHECK MEH WORK

AnimeGhoul8863:

Q2: rewrite in simplest radical form 1 over -3 over x6 Show each step of your process

AnimeGhoul8863:

1 over -3 over x6 fraction rule 1 over 3 -over 6x Fraction rule 1 -over 3 over 6x = -6x over 3 = -2x

AnimeGhoul8863:

@dude

AnimeGhoul8863:

cant figure out how to use the equation thing so

AnimeGhoul8863:

|dw:1536179807741:dw|

AnimeGhoul8863:

i did my best drawing it to make it easier to understand but im bad at drawing e.e

jhonyy9:

\[1/(-3)/(x^6) = \] do you think it in this form ?

AnimeGhoul8863:

what?

AnimeGhoul8863:

no the question shows it in this form |dw:1536180113909:dw|

AnimeGhoul8863:

i suck at functions so a double function im like RIP e.e

jhonyy9:

use the rule of fractions 1 b --- = --- do you know it why ? a a --- b

AnimeGhoul8863:

im so confused by "do you know it why"

jhonyy9:

when you dicide two fractions so you can multiply the first fraction with secons inversed

jhonyy9:

divide two fractions

jhonyy9:

do you know this rule of fractions ?

AnimeGhoul8863:

urmmmmmmmmmmmm no?

AnimeGhoul8863:

i dont think i do cause this is all confusing

jhonyy9:

not is really - this is easy just use this what i ve wrote above

AnimeGhoul8863:

but i thought i already did

AnimeGhoul8863:

my original comment i took the negative and moved it to a different spot

jhonyy9:

|dw:1536180695932:dw|

AnimeGhoul8863:

\[\frac{ -a }{ b }\] \[\frac{ a }{ b }-\]

AnimeGhoul8863:

\[\frac{ \frac{ 1 }{ -3 } }{ x6 }\] to \[\frac{ \frac{ 1 }{ 3 } }{ 6x }-\] to \[\frac{ \frac{ 1 }3{ -} }{ 6x }\] to \[\frac{ -6x }{ 3}\]

AnimeGhoul8863:

to -2x

AnimeGhoul8863:

YESH FINALLY FIGURED OUT THAT EQUATION THINGY

AnimeGhoul8863:

@dude am i correct

jhonyy9:

try rewriting every fractions simplified in this form how i ve wrote to you above

AnimeGhoul8863:

1

jhonyy9:

do you can rewriting the second and the 3rd fractions so simplified like first ?

jhonyy9:

first fraction is (-x^6)/3

AnimeGhoul8863:

Your confusing me with the whole "do you can rewriting"

AnimeGhoul8863:

Ok \[\frac{x^6 }{ -3 }\]

jhonyy9:

@ThisGirlPretty please help understanding the way

jhonyy9:

the second fraction how will be simplified ?

AnimeGhoul8863:

.....

ThisGirlPretty:

I think he's asking do you think you can convert the second and third fractions into simplest form like the first one

jhonyy9:

the second will be : 1/(-3/(6^x)) = (6^x)/(-3) = (-6^x)/3

AnimeGhoul8863:

Im SO CONFUSED there is only 1 fraction \[\frac{ \frac{ 1 }{ -3 } }{ x6 }\] i dont get were this third and second fraction are coming from

jhonyy9:

there are 3 fractions first divide second divide 3rd

AnimeGhoul8863:

were?

ThisGirlPretty:

I think he's talking about the 3 fractions in the problem(post)

AnimeGhoul8863:

AnimeGhoul8863:

in the post thats my answer not the question the question is this^^^

jhonyy9:

omg. this is allllll different how you wrote firstly

AnimeGhoul8863:

No the question says "check my work" so i put my work \(\color{#0cbb34}{\text{Originally Posted by}}\) @AnimeGhoul8863 1 over -3 over x6 fraction rule 1 over 3 -over 6x Fraction rule 1 -over 3 over 6x = -6x over 3 = -2x \(\color{#0cbb34}{\text{End of Quote}}\)

jhonyy9:

x^(-3/6) = ?

AnimeGhoul8863:

i drew it so people would understand what it looks like

jhonyy9:

do you know this x^(-1) = ?

AnimeGhoul8863:

\[\frac{ 1 }{ x }\]

jhonyy9:

exactly - so us this rule of negativ exponent in case of your exercise

AnimeGhoul8863:

exercise?

jhonyy9:

problem

jhonyy9:

do you know how is the exponential form of squarroote ?

jhonyy9:

ok. sqrt x = x^(1/2) cuberoote x = x^(1/3)

jhonyy9:

do you see the index of radical allways is the denominator of exponent

jhonyy9:

@ThisGirlPretty do you understand it now ? please

ThisGirlPretty:

Yes I do

jhonyy9:

sqrt x = x^(1/2)

jhonyy9:

where 2 is the index of radical

jhonyy9:

cuberoot x = x^(1/3) ok ?

AnimeGhoul8863:

ok?

jhonyy9:

these all you just need using in case of your above wrote problem

AnimeGhoul8863:

ok im sorry Jhonyy but im to confused im gonna ask someone to come and help

AnimeGhoul8863:

@563blackghost

jhonyy9:

ok sorry this is easy just us these rules

AnimeGhoul8863:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AnimeGhoul8863 \[\frac{ \frac{ 1 }{ -3 } }{ x6 }\] to \[\frac{ \frac{ 1 }{ 3 } }{ 6x }-\] to \[\frac{ \frac{ 1 }3{ -} }{ 6x }\] to \[\frac{ -6x }{ 3}\] -2x \(\color{#0cbb34}{\text{End of Quote}}\) I just need someone to check this is it correct

jhonyy9:

from x^6 how you get 6x ?

jhonyy9:

ohhh i see it now what you ve confused (-3/6) is the exponent of x

AnimeGhoul8863:

typo \(\color{#0cbb34}{\text{Originally Posted by}}\) @AnimeGhoul8863 \(\color{#0cbb34}{\text{Originally Posted by}}\) @AnimeGhoul8863 \[\frac{ \frac{ 1 }{ -3 } }{ x^6 }\] to \[\frac{ \frac{ 1 }{ 3 } }{ x^6 }-\] to \[\frac{ \frac{ 1 }3{ -} }{ x^6 }\] to \[\frac{ x^6 }3{ -}\] \(\color{#0cbb34}{\text{End of Quote}}\) I just need someone to check this is it correct \(\color{#0cbb34}{\text{End of Quote}}\)

563blackghost:

that looks right

AnimeGhoul8863:

is that all i have to do to get the question right?

jhonyy9:

@563blackghost please she confused the exponent of x

563blackghost:

You applied the fraction rule correctly both times. You used: \(\large\bf{\frac{a}{-b} = -\frac{a}{b}}\) and \(\large\bf{\frac{1}{\frac{b}{c}}=\frac{c}{b}}\)

jhonyy9:

x^(-3/6) = 1/6index radical ofx^3

563blackghost:

so its not x^6?

563blackghost:

but x^-3/6?

jhonyy9:

yes and so this mean that 6 id the index of radical

AnimeGhoul8863:

\[x^\frac{ -3 }{ 6 }\]

563blackghost:

mhm

jhonyy9:

@563blackghost do you understand me now ?

563blackghost:

yea

AnimeGhoul8863:

\[\frac{ \frac{ 1 }{ -3 } }{ x^6 }\] to \[\frac{ \frac{ 1 }{ 3 } }{ x^6 }-\] to \[\frac{ \frac{ 1 }3{ -} }{ x^6 }\] to \[\frac{ x^6 }3{ -}\] to \[x^\frac{ -3 }{ 6 }\]

AnimeGhoul8863:

So it would look like this ^

jhonyy9:

1/x^(-3/6) = ?

AnimeGhoul8863:

huh?

jhonyy9:

this is the original problem

AnimeGhoul8863:

\[\frac{ 1 }{ x^\frac{ -3 }{ 6 } }\]

AnimeGhoul8863:

so this is the original equation?

563blackghost:

You first start with \(\large\bf{\frac{1}{x^{\frac{-3}{6}}}}\) This is your question. You start your problem here.

jhonyy9:

first you need simplifie x^(-3/6) = ?

AnimeGhoul8863:

WHAT?!?!?!?! i answered the question just to create the question you guys just made me 10000000000% confused

jhonyy9:

-3/6 is the power of x

AnimeGhoul8863:

*shoots self in head*

563blackghost:

You first start with: \(\Large\bf{\frac{1}{x^{\frac{-3}{6}}}}\) This is your question. You start your problem here. ~~~ Now you need to simplify the given fraction. \(\bf\large{\frac{-3}{6} ~simplifies~ \rightarrow - \frac{1}{2}}\) So you go from: \(\Large\bf{\frac{1}{x^{\frac{-3}{6}}} \rightarrow \frac{1}{x^-{\frac{1}{2}}}}\)

jhonyy9:

how you get 1/3 from there ?

jhonyy9:

where the -1/2 mean the exponent of x

AnimeGhoul8863:

ok Ghosteh so once we have \[\frac{ 1 }{ x \frac{1 }{ 2 } }\]

AnimeGhoul8863:

we simplify again

563blackghost:

make sure it includes the -

AnimeGhoul8863:

i tried but it wouldnt add to it this equation thing is hard to work with

AnimeGhoul8863:

so if were converting it to Radical form it would be \[\frac{ \frac{ 1 }{ 1 } }{ \sqrt{x} }\]??????

563blackghost:

yes you do. You apply another fraction rule. \(\large\bf{\frac{1}{\frac{b}{c}}=\frac{c}{b}}\) \(\Large\bf{\frac{1}{x^{\frac{1}{2}}} \rightarrow \frac{x^{\frac{1}{2}}}{1} \rightarrow \color{red}{x^{\frac{1}{2}}}}\)

AnimeGhoul8863:

Ok so the answer is x^1/2

563blackghost:

radical form? I thought we were just simplifying. If radical form then its acutally: \(\Large\bf{a^{\frac{x}{n} = \sqrt[n]{a^{x}}}}\) You first need to change your exponent fraction into positive. \(\large\bf{a^{-b} = \frac{1}{a^{b}}}\) \(\Large\bf{\frac{1}{x^-{\frac{3}{6}}} \rightarrow \frac{1}{\frac{1}{x^{\frac{3}{6}}}}}\) Then apply the formula. \(\Large\bf{ \frac{1}{\frac{1}{x^{\frac{3}{6}}}} \rightarrow \color{red}{ \frac{1}{\frac{1}{\sqrt[6]{x^{3}}}}}}\)

AnimeGhoul8863:

AnimeGhoul8863:

^the question

563blackghost:

I know. I just typed out the explanation for the answer.

AnimeGhoul8863:

ok so add the radical form or no

563blackghost:

I thought we were just simplifying not changing to radical form. Ye the explanation above is converting it to radical form.

AnimeGhoul8863:

i think its just simplifying

563blackghost:

So simplifying and radical form?

563blackghost:

e.e

AnimeGhoul8863:

simplify

563blackghost:

Remember how I said the answer is \(\Large\bf{x^{\frac{1}{2}}}\)?

AnimeGhoul8863:

i gtg thx for the help Ghost and Jhony

jhonyy9:

np.

sillybilly123:

Keeps Happenin'

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