Question

http://prntscr.com/kuj1sk halp plz

Answer 1

Do you have an idea or are just completely lost?

Answer 2

lost as a blind person in the woods

Answer 3

You want to factor out \(18x^2-32\)

Answer 4

okayy... uhm i can do that probably ig

Answer 5

Do you wan me to show you how to factor it?

Answer 6

yes pls lol

Answer 7

The question shows that 2 has been factored out so just factor out the 2 from \(18x^2-32\)

=\(2(9x^2-16)\)
Once you have this, just factor out \(9x^2-16\)
both have multiples, 9 has 3 and 16 has 4, because the 16 is negative you need a (x+ number) and (x - number)

So \(2(3x+4)(3x-4)\)

Answer 8

uhhh wth how

Answer 9

ok wait i get it

Answer 10

so the missing thing is 4, and i would have never got that, and THANK YOU

Answer 11

Yes, and ofcs

Answer 12

You could've also reverse solved this

Answer 13

@dude can i derrange ?

Answer 14

what formule need using ? probably may help

Answer 15

different of squares

Answer 16

Yeah its a difference of squares, I forgot that term LOL

Answer 17

pardon for my interfer

Answer 18

Neh its okay, thanks for reminding me xD

Answer 19

:|

Answer 20

anytime - np

Answer 21

lol whut

Answer 22

\(9x^2-16\) is a difference of squares, basically both have a multiple that (squared) would equal the number

\(3^2=9\) and
\(4^2=16\)

Because 16 is being subtracted its a difference (-) of squares

Answer 23

oh ok, gotcha

Answer 24

thx again

Answer 25

ofcs