Are my answers correct?
@Vocaloid
good attempt but not quite x = 1 is a valid solution because it makes the equation true (try plugging it in to check) x = 3 is the extraneous one (it makes the equation untrue)
So extraneous means incorrect?
sort of sometimes when you solve an equation you end up with a "solution" that seems to be true algebraically, but when you go back and plug it in, it ends up not working (in this case, because of the absolute value sign)
that's called an extraneous solution. a valid solution, by comparison, works when you go back and plug it in
oh ok i see
Can you help me with more?
sure
okay thanks
very close 3x + 5 must equal positive (x-1) or -(x-1) the second equation, after distributing, is -x + 1 not -x - 1
oh i see, so it would be B? ending with -x+1
yes
okay
good
good
good
good
good
yup good
not sure how to do this one
2/3 and 2/3 are very easy to add together to get 4/3, since they have the same denominator so you have (4/3)x = 7/8 you can divide both sides by (4/3) to isolate x
now, if you can't remember the rules for dividing fractions, to divide (7/8)/(4/3), we flip the numerator and denominator on the second fraction, and change the division sign to a multiplication sign so it is equivalent to (7/8) * (3/4)
b?
or keep it to d?
(7/8) * (3/4) gives you 21/32 when you multiply across the denom and numerator this cannot be simplified so B is the best solution
oh ok
can u help me go through this
oh lordy well first we take 3(2m-9+6m) and combine the m's together. 2m + 6m = 8m. 3(8m-9) we can also do this on the right side 3m + 29 -7m since 3-7 = -4 we get -4m + 29
so now we have 3(8m-9) = -4m + 29 distribute the 3 to get 24m - 27 = -4m + 29 then combining like terms and solving for m should be straightforward from there
uhh i got a...
hm. not quite. if you understand up to this point 24m - 27 = -4m + 29 adding 4m to both sides gives us 28m - 27 = 29 and adding 27 to both sides gives us 28m = 27 + 29 = 56 so m = 2
oh yikes.. im rly bad at math
Thanks for helping... Im done for now
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