Question

http://prntscr.com/kxpi95

Answer 1

Find \(v_1,v_2,v_3,i_1,_i_2,i_3\)

Answer 2

I created a study guide on this topic here: https://questioncove.com/study#/updates/5ae2c54632f943353231de00

\ Current is equal to voltage over the resistance. Note that in series circuits, the current is constant. In parallel circuits, the voltage is constant.

Answer 3

I created a study guide on this topic here: https://questioncove.com/study#/updates/5ae2c54632f943353231de00

\[I_{1} = \frac{ V_{1}}{ R_{1}}\]

Current is equal to voltage over the resistance.

Note that in series circuits, the current is constant. In parallel circuits, the voltage is constant.

Answer 4

Bro,the guide was good
But this also involves kirchoff's law

Answer 5

You need to know how to do that, first; and get the idea behind it

Answer 6

Then....

.... use Conservation of Charge - call it KCL if you like, at the 3-way junction at the top to get:

- \( i_1 = i_2 + i_3\)


Then apply Ohm's Law across the resistors to get these 3 eqns:

- \(10 - v_2 = 2 i_1\)

- \(v_2 + 6 = 4 i_3\)

- \(v_2 = 8 i_2\)


That's 4 eqns, 4 unknowns. You presumably know it from there.

Assuming no silly typo's, solves for me as: \(i_1 = 3, i_2 = 1/2, i_3 = 5/2, v_2 = 4\)

The drawing is the important bit, potentials are relative. Pick a zero/ earth and work everything from there

Answer 7

\(v_1, v_2\) follow from a bit more Ohm's Law

Answer 8

typo: \(v_1, v_3\)

Answer 9

Ah,I get it now. <3
Thank you @sillybilly123 and also @Shadow

Answer 10

awesome :)