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Find \(v_1,v_2,v_3,i_1,_i_2,i_3\)
I created a study guide on this topic here: https://questioncove.com/study#/updates/5ae2c54632f943353231de00 \ Current is equal to voltage over the resistance. Note that in series circuits, the current is constant. In parallel circuits, the voltage is constant.
I created a study guide on this topic here: https://questioncove.com/study#/updates/5ae2c54632f943353231de00 \[I_{1} = \frac{ V_{1}}{ R_{1}}\] Current is equal to voltage over the resistance. Note that in series circuits, the current is constant. In parallel circuits, the voltage is constant.
Bro,the guide was good But this also involves kirchoff's law
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You need to know how to do that, first; and get the idea behind it
Then.... .... use Conservation of Charge - call it KCL if you like, at the 3-way junction at the top to get: - \( i_1 = i_2 + i_3\) Then apply Ohm's Law across the resistors to get these 3 eqns: - \(10 - v_2 = 2 i_1\) - \(v_2 + 6 = 4 i_3\) - \(v_2 = 8 i_2\) That's 4 eqns, 4 unknowns. You presumably know it from there. Assuming no silly typo's, solves for me as: \(i_1 = 3, i_2 = 1/2, i_3 = 5/2, v_2 = 4\) The drawing is the important bit, potentials are relative. Pick a zero/ earth and work everything from there
\(v_1, v_2\) follow from a bit more Ohm's Law
typo: \(v_1, v_3\)
Ah,I get it now. <3 Thank you @sillybilly123 and also @Shadow
awesome :)
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