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Chemistry 74 Online
zarkam21:

Answer check please

zarkam21:

zarkam21:

@Vocaloid

Vocaloid:

yeah that's what i got too

zarkam21:

Vocaloid:

couple of things since nf = 2 and ni = 9 E = 2.183e-18 * (1/2^2-1/9^2)

Vocaloid:

also this only gives you energy in joules (I think?) per atom, you need to divide by 1000 to get kJ and multiply by avogadro's number

zarkam21:

I got -5.180x10^-19

zarkam21:

Oh okay so this is in joules so to get it in KJ I would just do the conversion so ?KJ=-5.180x10^-19 * (1KJ/1000J) = -5.18x10^-22KJ

Vocaloid:

getting there then since this is only one electron, we need to multiply by avogadro's number to get the desired quantity, kJ/mol

zarkam21:

oh okay, so on top of this I have to multiply by 6.022x10^23

zarkam21:

ANd I have to do this because this is the mol quantity?

Vocaloid:

yes

zarkam21:

-311.9396 KJ/mol

Vocaloid:

good but only three sig figs so -312 kJ/mol still not 100% sure on the sign convention but try -312 for now

zarkam21:

I have the .091 part but is that all of it or do I have to do something more

Vocaloid:

what

zarkam21:

Vocaloid:

|dw:1537831727187:dw|

Vocaloid:

since we want wavelength we can just use the original rydberg equation 1/x = (1.096776e7)(1/3^2 - 1/7^2)

zarkam21:

998270 m

Vocaloid:

almost, just need to invert the quantity at the end 1/998270 m

zarkam21:

1.00x10^-6 m

Vocaloid:

good

ILoveXXXTENTACION:

that looks like a hard expression, what grade is that?

zarkam21:

How do I know n=4 from the electron spectrum

zarkam21:

ILoveXXXTENTACION:

r u talking to me?

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