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The cross-section design of the kerbing for a driverless-bus roadway is shown opposite. The metal strip is inlaid into the concrete and is used to control the direction and speed of the bus. Find the width of the metal strip. |dw:1537912751828:dw|
Not sure on how to solve this, would you need to use the Sine or Cosine Rule?
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You need to find BC first
Wait hold on
Never mind heehe. I'm dumb so don't rely on me (: @Shadow
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|dw:1537915432497:dw| wait how did you find it was 20
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Oh im dumb sorry
LUL
For the height I got 549.5
Nvm 187.93
Agh, im just stuck here
welp im trying dude >.>
Its okay x.x
welp i got some small number dats probableh wrong
what did you do to solve for it
pls tell meh dis is multiple choice cause dis would beh so much easier >.>
No, this is all short response x.x
well i got 84.97 its most likely wrong, i was following what mchen was saying...and applied some things...but im not confident in my answer...also i found your problem http://prntscr.com/kyqoal
Okay, my teacher gave us the answer (number but not the work, I need to find the work) What did you do, it is right http://prntscr.com/kyqom1
Oh wow o-o
Um well mah work is like super messy is that okie?
Its okay
Lets see I first filled in the gaps of the angles. Based on your drawing you see that the strip and A they are parallel to each other. If you apply the right angled you would get a perpendicular intersection. Soo... |dw:1537921734212:dw| So I filled in the angles in that area... |dw:1537921759828:dw| Following so far?
Yes
Okie gud :3 I then decided to find the height (200 is the hypotenuse)... |dw:1537921881684:dw| You have your angle 20 and your hypotenuse 200. So you follow by cosine to find b. \(\large\bf{cos(20)=\frac{b}{200} \approx 187.94}\) |dw:1537921942715:dw|
Yes, I got there
Now you in order to find the width you need to sort of split the triangles length... |dw:1537921992315:dw| So we need to find z. We need to fill in the missing angles on the length.|dw:1537922130514:dw| We then find z. \(\large\bf{\tan(38)=\frac{187.94}{z} \approx 240.55
\(\large\bf{\tan (38)=\frac{187.94}{z} \approx 240.55}\)
Gah! Thats where I screwed |dw:1537922265545:dw| I was not sure how to find them e.e
ye you just had to find the angles. just identify the top angles then simplify to find the lower ones cx
I was blind there, anyway,, continue
So we find z already. |dw:1537922355723:dw| just posting this up so i can work wid it
Now we need to find y. So we sum up the angles that create y. |dw:1537922422904:dw| So your angles is 60. Now follow with tangent. \(\large\bf{tan(60)=\frac{y}{187.94} \approx 325.52}\) So now to find x you simply subtract y by z. \(\large\bf{325.52-240.55 = 84.97}\)
my work btw
wow, thank you so much afvdssfb <3 A relief
no problem cx
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