Question

What is the area of a rectangle with vertices at (−3, −1) , (1, 3) , (3, 1) , and (−1, −3) ?

Enter your answer in the box. Do not round any side lengths.

_____ units²

Answer 1

@SmokeyBrown

Answer 2

It might help to draw this out on some graph paper, if you have any.
You're going to want to find the lengths of the rectangle's sides using the pythagorean theorem. Basically, you can draw right triangles between the points, and you'll know the lengths of the right triangle's short sides. Then use that to find the length of the long side, which belongs to the rectangle.

Answer 3

IT'S 16 ISN'T IT ?

Answer 4

correct ?

Answer 5

Yeah, that's what I got too.
The rectangle should be sqr(8) by sqr(32), so the area is sqrt(256), which is equal to 16

Answer 6

https://static.k12.com/nextgen_media/assets/8080621-NG_GMT_K_01_U04_Quiz_04.png

What is the perimeter of the rectangle shown on the coordinate plane, to the nearest tenth of a unit?

A. 12.7 units

B. 16.9 units

C. 24.0 units

D. 33.9 units

Answer 7

Let's see... sqrt(180) by sqrt(18), if I'm not mistaken.
So, 2(sqrt(180)+sqrt(18)), which is... Well, it's definitely more than 24, so I'd have to go with D, 33.9

Answer 8

What is the area of a triangle with vertices at (−2, 1) , (2, 1) , and ​ (3, 4) ​ ?

Enter your answer in the box.


_______ units²

Answer 9

So, we have a right triangle that looks something like this. We can separate it into three right triangles, which are easier to find the area of.

Answer 10

ok so the answer must be

Answer 11

Wait wait wait, I told you something wrong. That's not how you do it

Answer 12

it must be 1/2

Answer 13

Mm, I think it should be larger than that. I'm thinking there's some way to make right triangles out of this one, but I can't quite visualize it.
You'd probably fare better asking someone else on this one