–3x+4
This is an expression. Do you have a question relating to this expression?
Graph y=–3x+4 .
Do you know that slope intercept form is?
Not really
It looks like this: \[y = mx + b\] Where m is the slope and b is the y intercept
So if the slope is 1, then the rise is 1 and the run is 1, and if the intercept is 5, then the line would intersect the y axis at 5.
Because 1 = 1/1
Youre better than my math teacher
If the slope were 2, the rise would be 2 and the run would be 1, since 2 = 2/1. A negative example: -1 The slope would rise (go down) by 1, then run by 1.
Since -1 = -1/1
But the slope is 3 right?
Negative three
So what would be the y?
the y intercept?
Yeah
y = mx + b b is the y intercept
So what is the y intercept for this line?
4?
Correct
So where would your line intersect the y axis at?
By the way, intersect means to cross. And the y axis is the vertical one (up and down), x axis is left to right (horizontal).
Okay so it would be (-3,4)?
What is that coordinate supposed to be?
What do you mean?
-3 is the x and 4 is the y
Because the y intercept is 2, so it intercepts the y axis at 2, then it rises (goes down, since it is negative) by 2 then runs by 1, since -2 = -2/1 Slope is rise/run
Okay so the rise is 3 correct?
What sign does the 3 have?
Sorry -3
So what would be the rise, would it go up or down
Down because it is negative
By how many units does it go down?
3
Then how many units does it run by?
4?
Remember the slope is rise over run. What is another way to write -3?
I gave examples of it above.
3//1?
Correct, but remember the negative sign. So what would be the run?
-3/1
Slope is rise/run, so what would be the run?
4?
I'm confused a balls
If the rise is -3, then what must the run be?
Look at what you just wrote
-3/1
Okay
\[Slope = m = \frac{ Rise }{ Run } = -3 = \frac{ -3 }{ 1 }\]
Maybe that will help give you some perspective.
I'm stupid the run would be 1 correct?
Correct
And the y intercept is 4, so that is where you would start drawing the line.
Rise is 3 run is 1
Yes, just remember the negative sign
Socorro would be(-3,1) and (4,1)?
You would be surprised how often this can impact your calculations in many other levels of math. Best to make a practice of it here in algebra.
Okay thank you good sir
How did you get those points?
*coordinates
So justx(-3,1)
http://prntscr.com/kzkcq3 That is where your (-3,1) and (4,1) are. If you were to draw a line through those points, the slope would be 0 since it is not rising.
I think I got it now
(-3,1) and (4,0) right?
hmm
It sounds like you are guessing, since you haven't explained how you are getting these numbers.
I'm kind of guessing but I'm also trying to do it correct
Let me show you a step by step of how you would graph something simple.
Brb
Back
Let me know if you can see those screenshots
yeah i can see them
Okay thank you
Once you have two points, you can draw a line. The y intercept is always the first point, and easy one. In this example it is at (0,1). Then we draw the second point from the slope, which is a rise of 2 up and a run of 1 to the right. We get our second point at (1,3)
Join our real-time social learning platform and learn together with your friends!