Question

Math

Answer 1

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ik there are no real roots but i don't understand how to get to that point

Answer 2

a) fundamental theorem of algebra says that the number of total roots is equal to the highest degree

so since the highest degree is 2 total roots

b) use the quadratic equation



plugging in a = 2, b = 4, c = 7 will give you the two irrational roots

Answer 3

so -1+1 and -1-1 ?

Answer 4

[ -4 +/- sqrt(4^2 - 4*2*7) ] / 2*2

= [-4 +/- sqrt(-40)]/4

= -1 +/- sqrt(-40)/4

= -1 +/- 2i*sqrt(10)/4

= -1 +/- i*sqrt(10)/2

Answer 5

therefore, plugging in a, b, and c into the quadratic equation gives you 2 roots

-1 + (sqrt(10)/2)i
and
-1 - (sqrt(10)/2)i

Answer 6

i really cant see if you put in the equations or not

Answer 7

x = [ -b +/- sqrt(b^2 - 4*a*c) ] / (2a)

I plugged in a = 2, b = 4, c = 7

and got

-1 + (sqrt(10)/2)i
and
-1 - (sqrt(10)/2)i

after simplifying.

Answer 8

thank you very much !