Question

Given the function f(x)= 3+|x-2|, find the turning point.
What x value makes the absolute value equal to 0? Then, substitute that value in to find the ordered pair.

and

Given the function f(x)= 3+|x-2|, find f(-4).

Answer 1

@Falconmaster @dude @Shadow

Answer 2

` find the turning point. *`?
What is *

Answer 3

Oh that's not needed sorry

Answer 4

https://www.desmos.com/calculator/2qcbp28wfx
Turning point in this case is just the vertex

Answer 5

For the second part
x-2=0
Solve for x

Answer 6

2?

Answer 7

Right so that is when the absolute value is 0

tranq you can input too if you think theres a better way to say it or to check

Answer 8

I think I got it....

The turning point is (3,3). The x to make the absolute value negative would be 2. The ordered pair would then be (0,3)

Answer 9

But I dunno the second one.

Answer 10

Check your turning point, refer to the graph

Answer 11

Idk dude

Answer 12

That's the answer?

Answer 13

lol, yes that is the turning point

Answer 14

Thanks dude, you da best x'D

Answer 15

We didnt finish part 2

Answer 16

`Given the function f(x)= 3+|x-2|, find f(-4).`

Answer 17

f(-4) just means y when x= -4
\(f(-4)= 3+|(-4)-2|\)
\(f(-4)= 3+|(-6|\)
\(f(-4)= 3+6\)
\(f(-4)=\) answer

Answer 18

"Thanks dude, you da best"

x'D

Answer 19

Cools :P