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Mathematics 18 Online
jasonmitchell:

Which goes with the question ?

dude:

Complete, the question lol

jasonmitchell:

1 attachment
jasonmitchell:

@dude @563blackghost

Shadow:

\[m = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }\]

Shadow:

Find the slope of each line. It is a parallelogram if the two pairs of sides are perpendicular to each other, since this would create two parallel pairs

dude:

ASBa6h1ES0_Cz6iayepmuQ.png

Shadow:

Nice illustration dude.

Shadow:

I’m on mobile so I had to go on a desktop browser to get the slope formula inserted from my QC notebook. Cause I’m not typing that out in the equation tool xD

dude:

Thank you, and that is smart xD

jasonmitchell:

ok so AB is -1/6 BC is 1 CD is 3/2 AD is -2/5 am i correc ?

jasonmitchell:

correct ?

dude:

AB is not -1/6

dude:

The line is moving up so the slope must definitely be positive

jasonmitchell:

it should be 1

dude:

Right

jasonmitchell:

AB is 1 BC is _______

dude:

Any idea?

jasonmitchell:

3/2

dude:

Not quite, this slope must be 0 as it does down slighlty

jasonmitchell:

-2/5

jasonmitchell:

@563blackghost

563blackghost:

So you identify the slopes by the formula: \(\bf{slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}}\) Following with this you identify the slope of BC. The points connecting BC`B(-1,2)` and `C(5,1)`So plug this into your formula. \(\Large\bf{AB~slope=\frac{1-2}{5+1}}\) What does that equal?

563blackghost:

welp BC slope not AB slope

jasonmitchell:

1.6

563blackghost:

1.6 or 1/6?

jasonmitchell:

1/6

563blackghost:

okie, well the numerator will actually be -1 because `1-2=-1` So your slope for BC: \(\large\bf{BC=-\frac{1}{6}}\)

563blackghost:

For CD you put 3/2 which is incorrect. Try plugging CD into the slope formula. You have points `(5,1)` and `(1,-3)`. So how would you put that into the slope formula?

jasonmitchell:

5-1/1+-3

jasonmitchell:

1.75

jasonmitchell:

am i right ?

563blackghost:

mm not quite. \(\Large\bf{\frac{-3-1}{1-5}}\)

jasonmitchell:

-9

563blackghost:

um what is -3 -1?

jasonmitchell:

-4

563blackghost:

and 1 - 5?

jasonmitchell:

-4

563blackghost:

correct. so the slope of CD is \(\large\bf{CD=1}\)

jasonmitchell:

AB = 1 BC = -1/6 CD = 1

563blackghost:

You said `AD=-2/5` which is correct. so you have. AB = 1 BC = -1/6 CD = 1 AD = -2/5 are any of these equal to each other?

jasonmitchell:

yes

563blackghost:

which ones?

jasonmitchell:

AB and CD

563blackghost:

Correct. So that means since they have the same slope `(being 1)` they are parallel. So `Quadrilateral ABCD` has `one pair of opposite sides that are parallel`.

jasonmitchell:

alright correct

563blackghost:

here is a visual https://www.desmos.com/calculator/1obhesyiqe

563blackghost:

nice cx

jasonmitchell:

Quadrilateral ABCD is a parallelogram because only one pair of opposite sides is parallel

563blackghost:

it is not, a parallelogram has 2 pairs of parallels.

563blackghost:

so Quadrilateral ABCD IS NOT a parallelogram because it has ONLY ONE PAIR OF OPPOSITE SIDES.

jasonmitchell:

that are parallels

563blackghost:

|dw:1538505994827:dw| see a parallelogram has two pairs of parallels, we only identified that the quadrilateral that you have has only ONE pair. So it would be. Quadrilateral ABCD `is not` a parallelogram because `only one pair of opposite sides is parallel`.

jasonmitchell:

ok gotcha right there, it makes sense that a parallelogram only has two pairs of parallels

563blackghost:

great you got it cx

jasonmitchell:

thank you 563 for your help i really do appreciate it but if i message you would you please respond to me i think because i didn't fanned you that's why you haven't received any messages from me

563blackghost:

oh i dun really pay attention to the msgs sorry >.< i will next time doe.

jasonmitchell:

ok oh i forgot last couple of questions i need help but first i'll start a new question

563blackghost:

okie

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