Which goes with the question ?
Complete, the question lol
@dude @563blackghost
\[m = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }\]
Find the slope of each line. It is a parallelogram if the two pairs of sides are perpendicular to each other, since this would create two parallel pairs

Nice illustration dude.
I’m on mobile so I had to go on a desktop browser to get the slope formula inserted from my QC notebook. Cause I’m not typing that out in the equation tool xD
Thank you, and that is smart xD
ok so AB is -1/6 BC is 1 CD is 3/2 AD is -2/5 am i correc ?
correct ?
AB is not -1/6
The line is moving up so the slope must definitely be positive
it should be 1
Right
AB is 1 BC is _______
Any idea?
3/2
Not quite, this slope must be 0 as it does down slighlty
-2/5
@563blackghost
So you identify the slopes by the formula: \(\bf{slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}}\) Following with this you identify the slope of BC. The points connecting BC`B(-1,2)` and `C(5,1)`So plug this into your formula. \(\Large\bf{AB~slope=\frac{1-2}{5+1}}\) What does that equal?
welp BC slope not AB slope
1.6
1.6 or 1/6?
1/6
okie, well the numerator will actually be -1 because `1-2=-1` So your slope for BC: \(\large\bf{BC=-\frac{1}{6}}\)
For CD you put 3/2 which is incorrect. Try plugging CD into the slope formula. You have points `(5,1)` and `(1,-3)`. So how would you put that into the slope formula?
5-1/1+-3
1.75
am i right ?
mm not quite. \(\Large\bf{\frac{-3-1}{1-5}}\)
-9
um what is -3 -1?
-4
and 1 - 5?
-4
correct. so the slope of CD is \(\large\bf{CD=1}\)
AB = 1 BC = -1/6 CD = 1
You said `AD=-2/5` which is correct. so you have. AB = 1 BC = -1/6 CD = 1 AD = -2/5 are any of these equal to each other?
yes
which ones?
AB and CD
Correct. So that means since they have the same slope `(being 1)` they are parallel. So `Quadrilateral ABCD` has `one pair of opposite sides that are parallel`.
alright correct
nice cx
Quadrilateral ABCD is a parallelogram because only one pair of opposite sides is parallel
it is not, a parallelogram has 2 pairs of parallels.
so Quadrilateral ABCD IS NOT a parallelogram because it has ONLY ONE PAIR OF OPPOSITE SIDES.
that are parallels
|dw:1538505994827:dw| see a parallelogram has two pairs of parallels, we only identified that the quadrilateral that you have has only ONE pair. So it would be. Quadrilateral ABCD `is not` a parallelogram because `only one pair of opposite sides is parallel`.
ok gotcha right there, it makes sense that a parallelogram only has two pairs of parallels
great you got it cx
thank you 563 for your help i really do appreciate it but if i message you would you please respond to me i think because i didn't fanned you that's why you haven't received any messages from me
oh i dun really pay attention to the msgs sorry >.< i will next time doe.
ok oh i forgot last couple of questions i need help but first i'll start a new question
okie
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