A quiz consists of 3 true-or-false questions and 2 multiple choice questions. The multiple choice questions have 3 options each. How many ways can a student complete the quiz? a) 18 b) 48 c) 54 d) 72
@Vocaloid
"3 true-or-false questions" each T or F only has 2 possibilities for three questions we multiply 2 by itself 3 times so 2*2*2 "2 multiple choice questions with three options each" so multiply 3 by itself two times 3 *3
putting it all together = 2*2*2*3*3 = ?
Oh sorry, I didn't see that you were asking me a question. I was on another tab. So okay... the answer would be 72 then?
yeah
A secret code consists of 2 digits, followed by 2 letters, followed by 1 of the following symbols: @, #, %, and &. Digits and letters cannot repeat. How many secret codes are possible? a) 234,000 b) 243,360 c) 260,000 d) 270,400
2 digits: 9 * 9 since there are 9 digits 2 letters: 26 * 26 since there are 26 letters in the alphabet 1 of 4 possible symbols, so * 4 therefore 9 * 9 * 26 * 26 * 4 *
hm lemme double check something
alright
oh, there are 10 digits not 9 whoops
therefore 10 * 10 * 26 * 26 * 4
Okay so that would be 270,400
right?
yes
How many distinct arrangements can you make using the letters in the word EXPERIMENT? a) 604,800 b) 725,760 c) 1,209,600 d) 3,628,800
there are 9 total letters with three repeated E's so 9!/3! note: this is 9 factorial over 3 factorial, not 9/3
wait okay so it's a) 604,800
yes
How many ways can a dance instructor send 4 of her 11 students to a summer dance program? a) 7920 b) 1980 c) 720 d) 330
|dw:1538685541385:dw| n is the total set (11 students) and r is the set being chosen (4 students) plugging them in gives us 11! / (4!(11-4)!)
Eh I'm not really sure for this one. So, I'm just gonna take an educated guess. 1980?
I've given you the formula and the substitution, you just need to plug 11! / (4!(11-4)!) into a calculator.
That came out to be 13 when I used a calculator e.e
you can make it easier by simplifying first|dw:1538686137986:dw|
|dw:1538686178916:dw|
so in the end that's (11*10*9*8)/(4*3*2*1) see what that gives you
330
yup that's what i got too
I have 3 more questions left. Will you be able to help with the rest?
i'll give it my best try
There are 5 keys on a keychain. One of the keys starts a car. If a key is randomly chosen, what is the probability that it starts the car? a) 5% b) 15% c) 20% d) 25%
1 good key/5 total keys 1/5 = what as a percent?
20%
awesome so 20% = your sol'n
sol'n?
solution
20%, not 25%
have to be careful with the wording on this one "probability that a randomly chosen female runs sprints" so we want (females who run sprints)/(total females) any ideas what that might be, based on the numbers in the table?
so, looking at the table how many females run sprints? and how many total females are there?
12 females run sprints and there are 31 females in total.
well done so 12/31 = ?
So that would be, 0.39?
yup
Okay I'm gonna post the last question
The probability of choosing a winning card from a stack of cards is 2.9%. What is the probability of choosing a losing card? a) 99.71% b) 97.1% c) 92.9% d) 87.1%
b right?
assuming there are only two types of cards (winning and losing) winning + losing = 1 so 100% - 2.9% will give you the losing probability
so 0.971
your pretty smart vocaloid but I think I was right on that one
good, which is also 97.1%
great job envision:)
Thank you so much for helping, Vocaloid! Your explanations are very helpful!
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