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Mathematics 19 Online
envision:

A quiz consists of 3 true-or-false questions and 2 multiple choice questions. The multiple choice questions have 3 options each. How many ways can a student complete the quiz? a) 18 b) 48 c) 54 d) 72

envision:

@Vocaloid

Vocaloid:

"3 true-or-false questions" each T or F only has 2 possibilities for three questions we multiply 2 by itself 3 times so 2*2*2 "2 multiple choice questions with three options each" so multiply 3 by itself two times 3 *3

Vocaloid:

putting it all together = 2*2*2*3*3 = ?

envision:

Oh sorry, I didn't see that you were asking me a question. I was on another tab. So okay... the answer would be 72 then?

Vocaloid:

yeah

envision:

A secret code consists of 2 digits, followed by 2 letters, followed by 1 of the following symbols: @, #, %, and &. Digits and letters cannot repeat. How many secret codes are possible? a) 234,000 b) 243,360 c) 260,000 d) 270,400

Vocaloid:

2 digits: 9 * 9 since there are 9 digits 2 letters: 26 * 26 since there are 26 letters in the alphabet 1 of 4 possible symbols, so * 4 therefore 9 * 9 * 26 * 26 * 4 *

Vocaloid:

hm lemme double check something

envision:

alright

Vocaloid:

oh, there are 10 digits not 9 whoops

Vocaloid:

therefore 10 * 10 * 26 * 26 * 4

envision:

Okay so that would be 270,400

envision:

right?

Vocaloid:

yes

envision:

How many distinct arrangements can you make using the letters in the word EXPERIMENT? a) 604,800 b) 725,760 c) 1,209,600 d) 3,628,800

Vocaloid:

there are 9 total letters with three repeated E's so 9!/3! note: this is 9 factorial over 3 factorial, not 9/3

envision:

wait okay so it's a) 604,800

Vocaloid:

yes

envision:

How many ways can a dance instructor send 4 of her 11 students to a summer dance program? a) 7920 b) 1980 c) 720 d) 330

Vocaloid:

|dw:1538685541385:dw| n is the total set (11 students) and r is the set being chosen (4 students) plugging them in gives us 11! / (4!(11-4)!)

envision:

Eh I'm not really sure for this one. So, I'm just gonna take an educated guess. 1980?

Vocaloid:

I've given you the formula and the substitution, you just need to plug 11! / (4!(11-4)!) into a calculator.

envision:

That came out to be 13 when I used a calculator e.e

Vocaloid:

you can make it easier by simplifying first|dw:1538686137986:dw|

Vocaloid:

|dw:1538686178916:dw|

Vocaloid:

so in the end that's (11*10*9*8)/(4*3*2*1) see what that gives you

envision:

330

Vocaloid:

yup that's what i got too

envision:

I have 3 more questions left. Will you be able to help with the rest?

Vocaloid:

i'll give it my best try

envision:

There are 5 keys on a keychain. One of the keys starts a car. If a key is randomly chosen, what is the probability that it starts the car? a) 5% b) 15% c) 20% d) 25%

Vocaloid:

1 good key/5 total keys 1/5 = what as a percent?

envision:

20%

Vocaloid:

awesome so 20% = your sol'n

envision:

sol'n?

Vocaloid:

solution

Vocaloid:

20%, not 25%

Vocaloid:

have to be careful with the wording on this one "probability that a randomly chosen female runs sprints" so we want (females who run sprints)/(total females) any ideas what that might be, based on the numbers in the table?

envision:

http://prntscr.com/l2aic2

Vocaloid:

so, looking at the table how many females run sprints? and how many total females are there?

envision:

12 females run sprints and there are 31 females in total.

Vocaloid:

well done so 12/31 = ?

envision:

So that would be, 0.39?

Vocaloid:

yup

envision:

Okay I'm gonna post the last question

envision:

The probability of choosing a winning card from a stack of cards is 2.9%. What is the probability of choosing a losing card? a) 99.71% b) 97.1% c) 92.9% d) 87.1%

kendra4640:

b right?

Vocaloid:

assuming there are only two types of cards (winning and losing) winning + losing = 1 so 100% - 2.9% will give you the losing probability

envision:

so 0.971

kendra4640:

your pretty smart vocaloid but I think I was right on that one

Vocaloid:

good, which is also 97.1%

kendra4640:

great job envision:)

envision:

Thank you so much for helping, Vocaloid! Your explanations are very helpful!

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