Question

1. Refer to Expression 1 and Expression 2.
Expression 1

Expression 2

(a) What is the value of Expression 1?
(b) Insert parentheses in Expression 2 so that it has a value of 19. Then show why your expression has a value of 19.

Answer 1

Equation 1: \[6\times7-3^{2}\times9+4^{3}\]

Answer 2

Equation 2: \[5+4\times2+6-2\times2-1\]

Answer 3

@dude

Answer 4

6*7-3^2*9+4^3=
42-3^2*9+4^3
42-9*9+64
25>>>i hope its right

5+4×2+6−2×2−1=14

Answer 5

Did you read the question?

Answer 6

(b) Insert parentheses in Expression 2 so that it has a value of 19. Then show why your expression has a value of 19.

Answer 7

*face palm*

Answer 8

Lol

Answer 9

I put the parenthesis around 5+4 and got 19 but my teacher marked it incorrect because I didn't show why... >:(

Answer 10

(5+(4*2)+6)-(2*2)-1

Answer 11

) at the end of the 2

Answer 12

Zoey use \(\LaTeX\) ;p

\(6\times 7-3^2\times 9+4^3=\\
6\times 7-9\times 9+64\\
42-81+64\\
25\)

Answer 13

yea dude i dont know how but imma go see

Answer 14

Okay so Equation 1 equals 25. What about the second part of the question?

Answer 15

i gtg eat

Answer 16

(b) Insert parentheses in Expression 2 so that it has a value of 19. Then show why your expression has a value of 19.

Answer 17

For the parenthesis between 5 and 4 you were right
(Originally you had to solve using PEMDAS)
To explain that:
\((5+4)×2+6−2×2−1\)
Once you have parenthesis you have to solve 5+4 first (PEMDAS)
\(9\times 2+6-2\times 2-1\)
Then Multiply (PEMDAS)
\(18+6-4-1\)
Simplify
\(=19\)

Answer 18

Thank you sir