Question

Mg(NO3)2?

Answer 1

Magnesium Nitrate?

Answer 2

Mg=Magnesium
NO3=nitrate

You're correct (:

Answer 3

BUt its NO NItrogen and Oxygen?

Answer 4

The NO3 is a polyatomic ion.
Why do we know that?
Because every compound has to be equal charges, and Nitrogen charge is -3 while Oxygen is -6, and that doesn't work because the charges aren't equal.

Answer 5

OH okay so NO3 is nitrate then

Answer 6

Yes, so you were correct!

Answer 7

NH4ClO3

Answer 8

Ugh I really wanna figure this out on my own

Answer 9

BUt this would be a polyatomic too?

Answer 10

Try it out! You were already right the first time for the first problem

Answer 11

Do you have to memorize the polyatomic ions, or no?

Answer 12

no

Answer 13

I mean I don't think kso

Answer 14

Alright, then use this picture for your help.

Answer 15

What chemistry are you in? Most of the times, regular high school chemistry doesn't force you to remember them.

Answer 16

Im in college chem

Answer 17

Using that polyatomics chart and what you know, try to form a formula.

Answer 18

general chemistry

Answer 19

Prepare to memorize it, just a side note. I'm in college level chemistry in high school, and they made me remember them.

Answer 20

Okay thanks for the chart i really appreciate it

Answer 21

and I got umm ammonium chlorate?

Answer 22

Of course, that chart is your drugs to passing chemistry

Answer 23

And yes, you are right

Answer 24

PbO would just be Lead oxide?

Answer 25

Partially right :P
You see in the chart that Lead has multiple charges, right?

Answer 26

NO :/

Answer 27

Oh, it doesn't say! I'm sorry.

Answer 28

if you have like a chemistry go-to folder, add that polyatomic list and this one.

Answer 29

Now, looking at that chart you can see that Lead has multiple charges, am I correct>

Answer 30

Yup I see it

Answer 31

It has charge 2 and 4. Since it is common sence (as oxygen charge is -2 and lead must be 2 because the ratio is 1:1) that the lead is charge 2, we still have to show that Lead has the charge of two in this compound because it could be four.

Answer 32

Kind of confusing, I know. But to show that Lead has the charge of plus 2, you can add a parenthesis after Lead and add the roman numeral of how many charges they have.

Answer 33

So the actual answer would be Lead (ll) Oxide
You were almost right ;P

Answer 34

its easier if you just draw it

Answer 35

Give the systematic name for the compound Mg(NO3)2.

Answer 36

Magnesium Nitrate?

Answer 37

for this one

Answer 38

Yep!

Answer 39

Fe2(SO4)3.

Answer 40

I know the first one is Iron (ii) but not sure if it is sulfate or sulfide

Answer 41

No, the iron has either a charge 2 or 3, and in this case, it is a 3 because

Answer 42

Does that make sence?

Answer 43

A little

Answer 44

So it would be Iron (III) Sulfate?

Answer 45

Since the charge of one sulfate ion is -2, and there are three of them, the overall charge is -6. The other element always has to have the same opposite charge, so Fe2 must be 6. There are two, and so we divide it by two, and so the charge of one iron is 3.
So the formula is Iron (lll) sulfate

Answer 46

OH i get it

Answer 47

barium oxide.

Answer 48

would be BaO

Answer 49

?

Answer 50

yes, thats correct

Answer 51

lead(II) phosphate is Pb^+2 P

Answer 52

Not quite.
Remember the polyatomic ions, phosphate is PO4

Answer 53

oh right so Pb^+2 PO4

Answer 54

Lead is Pb, and charge is either 2 or 3.
Phosphate is PO4, and charge is -3.
To balance, we have to find a common multiplier for 2 and 3, which is 6.

Answer 55

Lead must be charge three because phosphate is 2.

Answer 56

Oh it always has to be in its balanced form

Answer 57

Yes

Answer 58

Pb^+3 PO2

Answer 59

:)

Answer 60

The formula for phosphate is PO4

Answer 61

SO is it 3Pb 4PO4

Answer 62

it would be Pb3(PO4)2
You were very close.

Answer 63

The charges have to be equal, Pb charge is 2, multiply by 3=6
Phosphate charge is -3, multiply by 2=-6
They are both equal.

Answer 64

is the 3 an expoonent?

Answer 65

No, there would be no exponents

Answer 66

\[Pb _{3}(PO _{4})_{2}\]