covalent compound CCl4?

5 months agoCarbon tetrachloride?

5 months agoyup

5 months agocompound N2O5?

5 months agoDInitride pentoxide??

5 months agogood

5 months agoincorrect? :S

5 months agooh sorry, when you have two nonmetals, for the first element gets its full name spelled out, not the -ide suffix dinitrogen, not dinitride :S

5 months agoand the second?

5 months agokeeps the -ide suffix, so pentoxide

5 months agoWhat is the name for the compound N2O4?

5 months agoDinitrogen tetraoxide??

5 months agoalmost, tetra + oxide ---> tetroxide (it drops the a)

5 months agoformula P2S5.

5 months agoPentaphosphorus disulfide

5 months agoalmost, just switch the prefixes (2 phosphorus atoms, 5 sulfur atoms)

5 months agobut dont you have to switch

5 months agolike would phosphorus have 5

5 months agohm? Pentaphosphorus disulfide would be P5S2 not P2S5

5 months agoyeah but to make it neutral dont you swtich

5 months agoyou're thinking of charges, the compound is already neutral so don't worry about charges here

5 months agooh okay

5 months agoA flask contains 0.500 mol of liquid bromine, Br2. Determine the number of bromine molecules present in the flask.

5 months ago2.41 x 10^24

5 months agohm not quite 0.500 mol of Br2 molecules --> each molecule has 2 Br atoms, so ---> 1 mol of Br atoms --> avogadro's number of br atoms

5 months ago79.91*6.022 x 10^23

5 months ago79.91? no, it's just avogadro's number, the molar mass of the element is irrelevant here

5 months ago6.022 x 10^23

5 months agough wait it asks for bromine molecules not bromine atoms >_> so just half of avogadro's number i gotta read these more carefully

5 months ago1.2044 x 10^24

5 months ago(6.022 x 10^23)/2 = 3.011×10^23

5 months agowait whee are you getting two from

5 months ago0.500 mol of Br2 molecules, or in other words, half a mole half a mole = avogadro's number/2

5 months agothe 2 signifies the half?

5 months agoyes. dividing something by 2 is equivalent to taking half.

5 months agoThe fuel used in many disposable lighters is liquid butane, C4H10. How many carbon atoms are in 2.00 g of butane?

5 months agoLast one

5 months agothen im gonna go to sleep;.getting tired

5 months agofirst step: g of butane to moles butane --> divide 2.00/molar mass of butane second step: moles of butane to moles of carbon. 1 molecule of C4H10 has 4 carbon atoms according to its formula so multiply step 1 result by 4 third step: moles of carbon to atoms of carbon, so multiply the previous result by 6.022e23

5 months agoto save some time: molar mass of butane = 58.12 so (2.00/58.12) * 4 * 6.022e23

5 months ago8.29 x 10^22

5 months agogood

5 months agoCalculate the mass of 1.00×1024 (a septillion) molecules of water

5 months agoThis is the last one

5 months ago10^24

5 months agobut it would just be 1.00 x 10^ 24 times molar mass?

5 months agoyou need to convert the quantity to moles first

5 months agoavagadros?

5 months agoatoms ---> moles divide by avogadro's

5 months agoye divide by avocado's

5 months ago|dw:1539584128678:dw|

5 months ago1.66

5 months ago1.66 what?

5 months agoum moles

5 months agoyup. so now multiply by molar mass to get grams

5 months agowiat times 1.00 x 10^24?

5 months agonah, you just calculated 1.66 moles so multiply that by the molar mass to get g

5 months agomolar mass so ?

5 months agothe same number given?

5 months agothe compound given in the question is water, so you need to multiply 1.66 moles * the molar mass of water.

5 months ago29.9

5 months agoyeah that's what i got too

5 months agois sig figs right

5 months agoyeah they gave you 3 sig figs so the result also has 3 sig figs

5 months ago