covalent compound CCl4?
Carbon tetrachloride?
yup
compound N2O5?
DInitride pentoxide??
good
incorrect? :S
oh sorry, when you have two nonmetals, for the first element gets its full name spelled out, not the -ide suffix dinitrogen, not dinitride :S
and the second?
keeps the -ide suffix, so pentoxide
What is the name for the compound N2O4?
Dinitrogen tetraoxide??
almost, tetra + oxide ---> tetroxide (it drops the a)
formula P2S5.
Pentaphosphorus disulfide
almost, just switch the prefixes (2 phosphorus atoms, 5 sulfur atoms)
but dont you have to switch
like would phosphorus have 5
hm? Pentaphosphorus disulfide would be P5S2 not P2S5
yeah but to make it neutral dont you swtich
you're thinking of charges, the compound is already neutral so don't worry about charges here
oh okay
A flask contains 0.500 mol of liquid bromine, Br2. Determine the number of bromine molecules present in the flask.
2.41 x 10^24
hm not quite 0.500 mol of Br2 molecules --> each molecule has 2 Br atoms, so ---> 1 mol of Br atoms --> avogadro's number of br atoms
79.91*6.022 x 10^23
79.91? no, it's just avogadro's number, the molar mass of the element is irrelevant here
6.022 x 10^23
ugh wait it asks for bromine molecules not bromine atoms >_> so just half of avogadro's number i gotta read these more carefully
1.2044 x 10^24
(6.022 x 10^23)/2 = 3.011×10^23
wait whee are you getting two from
0.500 mol of Br2 molecules, or in other words, half a mole half a mole = avogadro's number/2
the 2 signifies the half?
yes. dividing something by 2 is equivalent to taking half.
The fuel used in many disposable lighters is liquid butane, C4H10. How many carbon atoms are in 2.00 g of butane?
Last one
then im gonna go to sleep;.getting tired
first step: g of butane to moles butane --> divide 2.00/molar mass of butane second step: moles of butane to moles of carbon. 1 molecule of C4H10 has 4 carbon atoms according to its formula so multiply step 1 result by 4 third step: moles of carbon to atoms of carbon, so multiply the previous result by 6.022e23
to save some time: molar mass of butane = 58.12 so (2.00/58.12) * 4 * 6.022e23
8.29 x 10^22
good
Calculate the mass of 1.00×1024 (a septillion) molecules of water
This is the last one
10^24
but it would just be 1.00 x 10^ 24 times molar mass?
you need to convert the quantity to moles first
avagadros?
atoms ---> moles divide by avogadro's
ye divide by avocado's
|dw:1539584128678:dw|
1.66
1.66 what?
um moles
yup. so now multiply by molar mass to get grams
wiat times 1.00 x 10^24?
nah, you just calculated 1.66 moles so multiply that by the molar mass to get g
molar mass so ?
the same number given?
the compound given in the question is water, so you need to multiply 1.66 moles * the molar mass of water.
29.9
yeah that's what i got too
is sig figs right
yeah they gave you 3 sig figs so the result also has 3 sig figs
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