How much does one sucrose molecule weigh in grams?
342.3
hm, that would be an entire mole of sucrose, so to find 1 molecule you'd just divide that by avogadro's remember that a molecule is very very small
1.76 x 10^21
342.3/(6.022*10^23) = ?
5.68 x 10^-22
good
Find the number of ibuprofen molecules in a tablet containing 200.0 mg of ibuprofen (C13H18O2).
would I find the molar mass first of each element
yeah, you'd add up 13(molar mass of carbon) + 18(molar mass of hydrogen) + 2(molar mass of oxygen) to find the molar mass of the whole compound then it's 200.0 mg/1000 to convert this to grams; then divide by the molar mass from the first step to get moles, then multiply by avogadro's to get molecules
7.834 x 10^26
what did you get for the molar mass of ibuprofen
260.1898
wait no
the molar mass of ibuprofen should be closer to 206 not 260
yeah i rechecked my calculation I am getting 206.2852 now
13(12.0107) + 18(1.00794) + 2(15.9994) = 206.28082g
yeah that's fine, it's within rounding error
after that it's just ( (200mg/1000) / 206.2852 ) * 6.022e23
5.839 x 10^20
good that should be your solution
What is the mass of a sample of water containing 3.55×10^22 molecules of H2O?
this would be the opposite right take the molar mass of h20 and multiply by the given
think about the units of molar mass g/mol; this doesn't have molecules in it since we have molecules we have to convert 3.55×10^22 molecules to moles first, then multiply by the molar mass of water
2.13781 x 10^46
3.55×10^22 / (6.022e23) * 18.02 = ?
remember, molecules to moles --> divide by molar mass
|dw:1539661417976:dw|
1.06
good that's what i got too
yeah that's what i got too
What is the mass percentage of each element in the compound Al2O3?
Did you get 9% for Al if I did this right
hm, I feel like it should be more than that molar mass of aluminum = 26.981538g molar mass of oxygen = 15.9994g total mass: 2(Al) + 3(O) = 2(26.981538g) + 3(15.9994g) just the aluminum: 2(26.981538g) so aluminium only/total mass * 100 should give the percentage
36
and then for O it would be
:
hm, I got something a bit different
32 for oxygen
2(26.981538) / [2(26.981538) + 3(15.9994)] = 52.9% composition of aluminum then for oxygen it's just 100% - 52.9% since we only have two components, aluminum and oxygen
Oh I see.
so it would be 52.9 , 47.1
yes, 52.9 for Al and 47.1 for O
This is what I got. When going from grams to moles, it has nothing to do with avogadros # does it
not quite have you tried calculating the molar mass of CaCO3?
Yes I got 100.091
and then divided the total by the number of grams given in the problem
good, so you'd divide 25.45g/100.091g to get to moles, then you'd multiply by 3 since each molecule of CaCO3 has 3 mol oxygen
but I got 48 in the beginning for the molar mass. Would I still multiply by 3?
48? no the molar mass is 100.091
no I mean when calculating the molar mass of the entire thing I already incorporated oxygen as being 3. In other words 16 * 3 . so why do I need to multiply by 3 again
you have to incorporate oxygen into the molar mass to get 100.091 after you have moles, you have to multiply by 3 because it's asking for the number of moles of oxygen
it's a completely separate calculation
oh okay I get it so I have to multiply by 3 in the beginning regardless because of the total molar mass but because its asking for oxygen I have to multiply by 3 again
yes
.7628
good that's it
well you have 100g of the entire compound, and it says its composed of 40.0% carbon, 6.70% hydrogen, 53.5% oxygen, right? so how many grams of carbon hydrogen and oxygen do you have
still there? since the percentages are out of 100 it's just 40.0g carbon, 6.7g hydrogen, 53.5g oxygen
then you'd convert these masses to moles
40/100=.4 6.7/100=.067 53.5/100=.535
hm, that's not how you convert grams to moles, remember g --> moles, divide by molar mass
but would I do 100 divded by molar mass or like the other number for the elements like for carbon 40/molar mass
we started with 100g of a compound with composition 40.0% carbon, 6.70% hydrogen, 53.5% oxygen naturally, if we want to know the masses of carbons, hydrogens, and oxygen, we would do 100g * 40.0% = 40g of carbon; same reasoning gives us 6.7g hydrogen and 53.5g oxygen
now, we want to convert 40g of carbon to moles by dividing by the molar mass of carbon, 6.7g hydrogen to moles by dividing by the molar mass of hydrogen and 53.5g oxygen to moles by dividing by the molar mass of oxygen
40/12.011=3.33 6.7/1.0079=6.65 53.5/16=3.34
awesome, this gives us the molar ratio between the compounds, but since we want whole numbers, we divide all three quantities by the smallest quantity of the three so in simpler words, since the smallest number out of those three is 3.33, divide all three quantities by 3.33
3.33/3.33 = 1 6.65/3.33 = about 2 3.34/3.33 = about 1 so the molar ratio is CH2O = your empirical formula = your sol'n
anyway I haven't eaten all day so i'm gonna grab a quick bite, be back in an hour ish if you're still up for more hw
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