Chemistry
zarkam21:

5 months ago
zarkam21:

5 months ago
SmokeyBrown:

I concur, mate

5 months ago
Vocaloid:

hm, I don't think so, 1.87 mol/1 L NaCl is not a valid conversion factor

5 months ago
zarkam21:

I'm confused as to what the conversion might be

5 months ago
Vocaloid:

before the 1.87/1 L NaCl you have Liters in the numerator, you can't just switch them to the denominator

5 months ago
SmokeyBrown:

Nah luv, he's just converting mL to Liters, then doing Mols/Liters to get the molarity. S'all good

5 months ago
Vocaloid:

I'd just convert 981mL to L via 981 mL * (10^(-3)) / 1 mL as you did then divide 1.87/ the result

5 months ago
Vocaloid:

*she

5 months ago
zarkam21:

I'm a girl :S

5 months ago
SmokeyBrown:

crikey

5 months ago
Vocaloid:

1.87 mol / (981 mL * (10^(-3)) / 1 mL) should do it

5 months ago
zarkam21:

1.906

5 months ago
zarkam21:

1.91

5 months ago
Vocaloid:

that's what i got too, just remember units are M

5 months ago
zarkam21:

for the bottom problem would it just be 1.89 / 2.70

5 months ago
zarkam21:

or would I take the molar mass of HCI

5 months ago
Vocaloid:

molarity = moles solute/ L solvent multiplying both sides by L solvent gives us molarity * L solvent = moles solute so you'd multiply, not divide, to get moles HCl

5 months ago
zarkam21:

5.103

5 months ago
Vocaloid:

good (5.10 moles since 3 sig figs)

5 months ago
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