hm, I don't think so, 1.87 mol/1 L NaCl is not a valid conversion factor
zarkam21:
I'm confused as to what the conversion might be
Vocaloid:
before the 1.87/1 L NaCl you have Liters in the numerator, you can't just switch them to the denominator
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SmokeyBrown:
Nah luv, he's just converting mL to Liters, then doing Mols/Liters to get the molarity. S'all good
Vocaloid:
I'd just convert 981mL to L via 981 mL * (10^(-3)) / 1 mL as you did
then divide 1.87/ the result
Vocaloid:
*she
zarkam21:
I'm a girl :S
SmokeyBrown:
crikey
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Vocaloid:
1.87 mol / (981 mL * (10^(-3)) / 1 mL) should do it
zarkam21:
1.906
zarkam21:
1.91
Vocaloid:
that's what i got too, just remember units are M
zarkam21:
for the bottom problem would it just be 1.89 / 2.70
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zarkam21:
or would I take the molar mass of HCI
Vocaloid:
molarity = moles solute/ L solvent
multiplying both sides by L solvent gives us
molarity * L solvent = moles solute
so you'd multiply, not divide, to get moles HCl