Question

Answer check

Answer 1

I concur, mate

Answer 2

hm, I don't think so, 1.87 mol/1 L NaCl is not a valid conversion factor

Answer 3

I'm confused as to what the conversion might be

Answer 4

before the 1.87/1 L NaCl you have Liters in the numerator, you can't just switch them to the denominator

Answer 5

Nah luv, he's just converting mL to Liters, then doing Mols/Liters to get the molarity. S'all good

Answer 6

I'd just convert 981mL to L via 981 mL * (10^(-3)) / 1 mL as you did

then divide 1.87/ the result

Answer 7

*she

Answer 8

I'm a girl :S

Answer 9

crikey

Answer 10

1.87 mol / (981 mL * (10^(-3)) / 1 mL) should do it

Answer 11

1.906

Answer 12

1.91

Answer 13

that's what i got too, just remember units are M

Answer 14

for the bottom problem would it just be 1.89 / 2.70

Answer 15

or would I take the molar mass of HCI

Answer 16

molarity = moles solute/ L solvent

multiplying both sides by L solvent gives us

molarity * L solvent = moles solute

so you'd multiply, not divide, to get moles HCl

Answer 17

5.103

Answer 18

good (5.10 moles since 3 sig figs)