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Biology 22 Online
bill533:

Part 1: Incomplete Dominance—Predicting Flower Color in Snapdragons Snapdragons are popular garden plants that produce brightly colored flowers. When a plant that is homozygous for white flowers is crossed with a plant that is homozygous for red flowers, all offspring are pink. Snapdragons are an example of a plant that exhibits an inheritance pattern called incomplete dominance. 1. Determine the genotype of each parent plant and write them below. Use W to indicate the allele for white flowers and R to indicate the allele for red flowers. Answer: Genotype of homozygous parent plant with white flowers: Genotype of homozygous parent plant with red flowers:

bill533:

@SmokeyBrown

SmokeyBrown:

So, homozygous means that both alleles that influence a trait are the same. So, a homozygous white plant would have a WW genotype, and a homozygous red plant would have a RR genotype

bill533:

that's for number 1 right

SmokeyBrown:

Yup

bill533:

ok for number 2

bill533:

Genotype of homozygous parent plant with white flowers: Genotype of homozygous parent plant with red flowers:

SmokeyBrown:

That's the same one

bill533:

oh that answer for all three of those questions ?

bill533:

2. Next, think about the gametes each parent plant will produce. List the alleles in each gamete. Answer: Parent plant with white flowers: Gamete 1: Gamete 2: Gamete 3: Gamete 4: Parent plant with red flowers: Gamete 1: Gamete 2: Gamete 3: Gamete 4:

SmokeyBrown:

Hm, since the parents only have one type of allele, the red plant would only produce gametes with R alleles and the white plant would only produce gametes with W alleles, right?

bill533:

right all are W's

bill533:

The two parent plants are the P generation, or parent generaton. Create a Punnett square to show their offspring, the F1 generation.

SmokeyBrown:

So, you'd draw the punnett square with the red parent contributing R and R, and the white parent contributing W and W

bill533:

the punnett square looks like this https://middleschoolscienceblog.files.wordpress.com/2015/02/spongbob-genetics-public1.jpg?w=636 R R and W W i'm trying to figure how to draw it like

SmokeyBrown:

You can have RR along the top and WW along the side. Then, fill in the squares with the combination of R and W that are next to that square

bill533:

on the left side: RW, Rw on the right side: Rw, rw right ?

bill533:

is it like this

bill533:

What pattern do you notice in the genotypes of the F1 generation snapdragons?

SmokeyBrown:

Yeah, that's right. Do you notice any pattern in the genes inside the square?

bill533:

yes and it's red

bill533:

it's the colors of the snapdragons

SmokeyBrown:

Oh, sorry, all of the genotypes should be RW The snapdragons have "incomplete dominance", so instead of one allele dominating the other, if there is a combination of different alleles, RW, they combine. That's why all the offspring are pink

bill533:

oh that's right

bill533:

What are the phenotypes of the F1 generation snapdragons ?

bill533:

All F1 plants are RW, a combination of red and white.

bill533:

correct all is RW ?

SmokeyBrown:

Yeah that's right

bill533:

Part 2: Incomplete Dominance—Predicting Flower Color in F2 Generation Snapdragons Now, set up a cross of the offspring of the F1 generation and predict the traits of the F2 generation. 1. What are the genotypes of the F1 parent plants?. Answer: Type your answer here. • Genotype of F1 parent plant 1: • Genotype of F1 parent plant 2:

bill533:

Ww right ?

SmokeyBrown:

Well, we're still looking at the F1 generation, so they would all be RW

bill533:

Next, think about the gametes each parent plant will produce. List the alleles in each gamete. F1 parent plant 1: • Gamete 1: • Gamete 2: • Gamete 3: • Gamete 4: F1 parent plant 2: • Gamete 1: • Gamete 2: • Gamete 3: • Gamete 4: Answer:

SmokeyBrown:

I think, for each plant, they'd produce 2 R and 2 W

bill533:

Create a Punnett square showing a cross between the two F1 parent plants. Their offspring are the F2 generation.

SmokeyBrown:

It would be the same as before, except instead of RR and WW, the alleles on the outside would be RW and RW

bill533:

What are the genotypes of the F2 generation?

SmokeyBrown:

Not quite, that's the punnett square for the original parents. Like I said, the square for the F1 generation has RW on the top and RW on the side, instead of RR on the top and WW on the side

bill533:

what about in the inside

SmokeyBrown:

You fill in the inside of the square with whatever allele intersects with it

bill533:

oh i got it RW in the inside

bill533:

What are the genotypes of the F2 generation?

SmokeyBrown:

Ok, so the punnett square has 4 squares inside it. Each smaller square takes an allele from above and an allele from the left. The combination of those two alleles is what goes inside the box.

SmokeyBrown:

|dw:1540826695103:dw| Now, how would you fill in the boxes of this punnet square?

bill533:

RW

SmokeyBrown:

So, all four boxes would have a different combination of R and W, depending on which is on top and which one is on the side

bill533:

RR Rr rr

SmokeyBrown:

Not quite, no. I'll draw it out for you

SmokeyBrown:

|dw:1540827061441:dw|

bill533:

ok gotcha

bill533:

What are the genotypes of the F2 generation?

bill533:

?

bill533:

WW, WR, RR FOR THE genotypes ?

SmokeyBrown:

Yeah, that's right

bill533:

Calculate the percentages of the phenotypes of the F2 generation.

SmokeyBrown:

So, one of them is RR, one is WW, and two are RW. What would the percentages be?

bill533:

White-WW-1/4 Pink-WR- 2/4 Red-RR- 1/4

bill533:

is that right somehow

SmokeyBrown:

Oh, yeah, that's right. You just have to convert them to percentages

bill533:

White-WW-14% Pink-WR- 24% Red-RR- 14% correct ?

SmokeyBrown:

Not quite. 1/4 would be equal to 25%, and 2/4 would be 1/2 or 50%

bill533:

that's right

bill533:

What are the phenotypes of the offspring from this cross?

SmokeyBrown:

So you already kind of answered this. You know that WW is white, RR is red and RW is pink

bill533:

Imagine that you are studying two parents who are considering having children. One parent is has the genotype IAi and the other has the genotype IBi. Create a Punnett square to calculate the possible genotypes of their children. Answer? Part 3 Punnett? Part 3: Multiple Alleles—Predicting Blood Types of Offspring As you read in the online lab, human blood type is determined by multiple alleles that show a type of inheritance called codominance. Recall that the alleles that determine blood type are IA, IB, and i. IA and IB are both dominant over i, while neither IA nor IB is dominant when they combine. Use this table to help you determine the genotypes associated with each blood type. Blood Type Allele Possible Genotype(s) Possible Allele(s) A IA AA or AO IAIA or IAi B IB BB or BO IBIB or IBi AB IAIB AB IAIB O i OO ii

SmokeyBrown:

I think that is correct

bill533:

Look at the table at the beginning of Part 3. What are the possible phenotypes (blood types) of the children ?

bill533:

1/4 chance of each AB, A, B, and O correct ?

SmokeyBrown:

Yes, I think that's right

bill533:

Part 4: Sex-Linked Inheritance—Predicting Color Blindness in Offspring Recall that females have two X chromosomes: one from the mother and one from the father. Males have one X chromosome and one Y chromosome; the X chromosome comes from the mother, and the Y chromosome comes from the father. Traits associated with genes located on the sex chromosomes are called sex-linked traits. Individuals with the sex-linked condition called red-green color blindness do not perceive the colors red and green. Red-green color blindness is caused by the recessive allele b and is carried on the X chromosome. The dominant allele for normal color vision is B. When an X chromosome contains the dominant allele, the allele is written as . When an X chromosome contains the recessive allele, the allele is written as X^b. 1. What is the genotype of a male with red-green color blindness? Answer:

bill533:

XY, X chromosome

SmokeyBrown:

Yeah, the X chromosome would have the b allele, for the recessive colorblindness trait

bill533:

or X n Y

bill533:

is that one right

SmokeyBrown:

Well, going by the notation that he question uses, I think it'd be X^bY

bill533:

2. What is the genotype of a female who is not color-blind but is a carrier of red-green color blindness? Answer:

SmokeyBrown:

For that one, one of the X chromosomes has the colorblind gene, but the other X chromosome does not

bill533:

XBXb for the female

bill533:

or b

SmokeyBrown:

Yeah XBXb should be right

bill533:

Even though red-green color blindness is a recessive trait, can a female have red-green color blindness? Explain.

SmokeyBrown:

I would say yes. If the genotype is XbXb, then the female would have color blindness

bill533:

A man who is color-blind marries a woman who is not color-blind and is not a carrier of the allele for color blindness. Create a Punnett square to predict the possible genotypes of their children. Part 4 Punnet Square

SmokeyBrown:

Well, the man would have a XbY, and the woman would have XBXB. So, you can use that to construct your punnett square

SmokeyBrown:

Kind of, except the man should have XbY, not XBY. The woman should have XBXB, not XbXb

bill533:

Will all of the female children be carriers of the color-blind allele, or will none be carriers? Explain. Answer:

bill533:

??

SmokeyBrown:

Oh, they'd all be carriers. The only possible combination would be XBXb

bill533:

Will all of the male children be color-blind, or will none be color-blind? Explain Answer:

bill533:

?

SmokeyBrown:

None of the male children would be colorblind, since the only possible combination would be XBY

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