Question

A normal distribution has mean 200 and standard deviation 50. Find the area under the normal curve from the mean to 224

Answer 1

I think its kind of different though

Answer 2

Do I do the same with this one
?

Answer 3

Yes, find the z-score of 224

the z-score from a mean is automatically 0 standard deviations or (0.500 this is what we will subtract from)

Find the z-score of 224

Answer 4

so 224-0.500/200?

Answer 5

I am completely wrong right

Answer 6

No no

\(z=\large\frac{x-\mu}{\sigma}\)

\(\mu\)=mean
\(\sigma\) = Standard deviation
x = your value (In this case, its 16 and 60)

Mind the 0.500 for this moment

Answer 7

oh so I subtract 224 from 60

Answer 8

realized I copy pasted

Answer 9

yea I was getting confused lol

Answer 10

\(\large \frac{224-200}{50}\)

Answer 11

so I subtract 224 from 200?

Answer 12

Right

Answer 13

oh I see

Answer 14

so 1.2 for the first and what do I subtract the second number with?

Answer 15

1.2?

224-200 is 24

\(\frac {24}{50}=\)

Answer 16

oh i mean 0.48

Answer 17

Right, now using the table find the decimal value

Answer 18

.6844?

Answer 19

Right

I previously said that the mean has a z-score of 0 which based on the table is 0.5000
So we subtract

\(0.6844-0.5000\)

And that should be your answer

Answer 20

so How did u turn 50 into 0.5000

Answer 21

\(\color{#0cbb34}{\text{Originally Posted by}}\) @dude
No no

\(z=\large\frac{x-\mu}{\sigma}\)

\(\mu\)=mean
\(\sigma\) = Standard deviation
x = your value (In this case, its 16 and 60)

Mind the 0.500 for this moment
\(\color{#0cbb34}{\text{End of Quote}}\)
didn't happen

read it again :)

Answer 22

Lol thanks I get it now

Answer 23

@dude thanks so much for your time :)