Question

Check

Answer 1

still not super confident about these, but since the only want 2s/2p electrons, you'd start with N having 5 valence electrons, then doubling to get 10, then removing 1 electron since we have a -1 charge

so I believe you would just fill with the first 9 electrons

Answer 2

yeah that's my best attempt

Answer 3

0?

Answer 4

yeah that's what i got too

Answer 5

C

Answer 6

not quite; antibonding orbitals are higher in energy (notice how they're higher on the MO diagram)

this is a memorization thing but they come from destructive interference of AO's

Answer 7

haven't done the diagrams but I believe that would be correct