Question

thanks

Answer 1

4. the first number is your quantum number (4), and the second number is determined by the letter d

in general s = 0, p = 1, d = 2, f = 3 for your angular quantum number

Answer 2

5. the first two quantum numbers are determined using the earlier process

for the third quantum number it can be anywhere between -l to +l (those are lowercase L's). in this particular example, l = 0 so there's only one possibility for the third quantum number (0)

Answer 3

6

Answer 4

7. in general the number of electrons per principal quantum number (n) is 2n^2

8. I believe this would be the same logic as #6

Answer 5

if anything's confusing I'll try to clarify

I'm a little busy but we have some resident chem experts floating around

Answer 6

Actually yes. If you're not busy, can you clarify the whole thing a little more :) I started started learning this stuff this lesson so its very confusing to me still.

For 4. Am I supposed to be determining the energy level and sublevels. Im not sure.

For 6. im still confused is there a longer chart?

Im not really sure... im really just confused about all of the questions.

Answer 7

"4d" the first number gives you the principal quantum number (4) and the orbital (d) gives you the second quantum number (d-subshell gets l = 2)

so the first two quantum numbers are 4, and 2

Answer 8

it's just asking for the first two quantum numbers

Answer 9

Oh okay... I see because in the example question and answer at the top it gave the energy level and sublevel in the answer

Answer 10

n = 4 and l = 2 to follow their example

Answer 11

For 5. Would it be 2, 0, ?

Answer 12

it's asking for the first three numbers

so n = 2, l = 0, and because l = 0, ml can only be 0

Answer 13

2,0,0

Answer 14

Oh okay that makes sense.
For 6 how am I supposed to use the chart?

Answer 15

"in general s = 0, p = 1, d = 2, f = 3 for your angular quantum number"

you are given l = 3 so that's a f orbital ---> 14 electrons

Answer 16

Oh I see. Can you also clarify 7 and 8?

Answer 17

for 7 the number of electrons per energy level n is 2n^2

you are given n = 4

therefore electrons ---> 2n^2 ---> 2*4^2 ---> 32

Answer 18

8: from 6 we determined that any sub-level l = 3 contains 14 electrons

so n = 4, l = 3 ---> 14 electrons

Answer 19

Thats what I thought for 7 but was unsure if it was right. Thank you so much for all of your help! I really appreciate it! :)