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Mathematics 9 Online
Vocaloid:

graphing question on behalf of @Nicole

Vocaloid:

|dw:1542678316170:dw|

Vocaloid:

graphing is the easy part, we just have to move all the points up 1 and right 3 |dw:1542678333750:dw|

Vocaloid:

re-writing the function is a bit more difficult translating up and down: you just have to add/ subtract the desired amount from the whole equation, so translating up 1 is just adding 1 to the entire equation y = 3 * 2^x + 1 (the 1 is not part of the exponent) to translate to the right, we subtract 3 from x (not from the whole function, just x) so y = 3 *2^(x-3) + 1

Vocaloid:

|dw:1542678500991:dw|

Nicole:

so the new function is y = 3 *2^(x-3) + 1

Vocaloid:

yes

Nicole:

http://prntscr.com/lkhh7m

Vocaloid:

similar process as before 1) translate down 5 units --> subtract 5 from the entire function 2) left two units --> add 2 to x only can you try applying this to y = (0.5)^x ?

Nicole:

so i just need to add 2 to x to find the new funtion?: y = (0.5)^x

Vocaloid:

gotta remember both steps 1. subtract 5 from the whole function 2. add 2 to the x part only

Nicole:

y = (0.5)^x-5

Nicole:

im confused a bit loll

Vocaloid:

you're almost there if we want to just add 2 to the x part we put x in parentheses and add 2 so y = (0.5)^(x+2)-5 should account for both transformations

Nicole:

got it, and how would the graph look?

Vocaloid:

well we kinda just do what the words say "translate down 5 and left 2" so we just take all the points and move them down 5 and left 2 |dw:1542679014807:dw|

Vocaloid:

|dw:1542679022842:dw|

Vocaloid:

you just wanna identify any obvious points on the original graph (like 0,1 in the previous example), move down 5, 2 left, and draw the new point

Nicole:

http://prntscr.com/lkhjpq

Vocaloid:

dilation by 2: multiply the entire function by 2 (so basically just write 2* in front) a reflection across the x-axis --> add a negative sign in front of the equation so what do you think might be the final result from this?

Nicole:

wdym "a reflection across the x-axis" like where would that be in the function?

Vocaloid:

if you look at the original problem it calls for "a reflection about the x-axis" which basically means the function gets "flipped" using the x-axis as a mirror (I can try drawing it)

Vocaloid:

|dw:1542679417405:dw|

Vocaloid:

to accomplish this we just need to multiply the entire function by -1 y = (1/4)^x becomes y = -(1/4)^x

Vocaloid:

then the second part, dilating by 2, we just multiply the entire function by 2 so the end result is y = -2(1/4)^x

Vocaloid:

now, to draw this, we want to 1) draw the mirror image of the original function across the x-axis and 2) dilate by 2 (make the curved part a bit steeper)

Vocaloid:

|dw:1542679623387:dw|

Vocaloid:

|dw:1542679629523:dw|

Nicole:

Oh okay that looks accurate enough http://prntscr.com/lkhlxe one more after this^

Vocaloid:

so to reflect across the y-axis we multiply x (just the x part) by -1 dilation of 1/2 --> multiply the entire function by 1/2 so applying these two operations to y = 4^x what do you think we get?

Nicole:

y = 4^x*(-1)

Vocaloid:

1. multiply the x by -1 ---> y = 4^(-x) 2. multiply the entire function by 1/2 ---> y = (1/2) * 4^(-x) --> end result

Nicole:

ohh ok

Vocaloid:

so if you just want to perform an operation on x it's a good idea to separate x into parentheses to keep it separate from the whole function

Vocaloid:

anyway to graph this just flip the function across the y-axis, then to dilate by 1/2 we make it less steep

Vocaloid:

|dw:1542680064365:dw|

Vocaloid:

|dw:1542680069852:dw|

Vocaloid:

still there?

Nicole:

yes sorry im here

Nicole:

but got that part

Nicole:

last one: http://prntscr.com/lkhqih

Vocaloid:

ah well in that case you just have to pick two things to do to the graph so, like, you can translate up 3 and reflect across the x-axis (just an example), remember how to do that?

Nicole:

can you tell me one more time?

Vocaloid:

|dw:1542681027206:dw| would recommend studying this chart on your own time but translating up 3 ---> add 3 to the entire function reflect across x-axis --> multiply the entire function by -1

Nicole:

Ugh this is confusing lmao

Nicole:

im sorry im literally just not in the mood for math but im trying to understand it loll

Vocaloid:

> if we want to reflect across the x-axis, multiply the function by -1 so y = 2 * 3^x ---> becomes y = -2 * 3^x > if we want to translate a function up 3 units we add 3 to the function so y = -2 * 3^x ---> becomes y = -2 * 3^x + 3 as the end result of applying both transformations

Vocaloid:

then to graph you would just reflect the function across the x-axis (pretend the x-axis is a mirror and draw what the mirror image would be) then move all the points on the graph 3 units up

Vocaloid:

|dw:1542681333852:dw|

Vocaloid:

|dw:1542681339667:dw|

Nicole:

Got it, how about a and b?

Vocaloid:

the rules for these transformations have to be studied/memorized a) is asking for the function we created y = -2 * 3^x + 3 b) is asking to graph the function we created (see the purple line)

Nicole:

okay thank you voca! illmake sure to study them

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