graphing question on behalf of @Nicole
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graphing is the easy part, we just have to move all the points up 1 and right 3 |dw:1542678333750:dw|
re-writing the function is a bit more difficult translating up and down: you just have to add/ subtract the desired amount from the whole equation, so translating up 1 is just adding 1 to the entire equation y = 3 * 2^x + 1 (the 1 is not part of the exponent) to translate to the right, we subtract 3 from x (not from the whole function, just x) so y = 3 *2^(x-3) + 1
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so the new function is y = 3 *2^(x-3) + 1
yes
similar process as before 1) translate down 5 units --> subtract 5 from the entire function 2) left two units --> add 2 to x only can you try applying this to y = (0.5)^x ?
so i just need to add 2 to x to find the new funtion?: y = (0.5)^x
gotta remember both steps 1. subtract 5 from the whole function 2. add 2 to the x part only
y = (0.5)^x-5
im confused a bit loll
you're almost there if we want to just add 2 to the x part we put x in parentheses and add 2 so y = (0.5)^(x+2)-5 should account for both transformations
got it, and how would the graph look?
well we kinda just do what the words say "translate down 5 and left 2" so we just take all the points and move them down 5 and left 2 |dw:1542679014807:dw|
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you just wanna identify any obvious points on the original graph (like 0,1 in the previous example), move down 5, 2 left, and draw the new point
dilation by 2: multiply the entire function by 2 (so basically just write 2* in front) a reflection across the x-axis --> add a negative sign in front of the equation so what do you think might be the final result from this?
wdym "a reflection across the x-axis" like where would that be in the function?
if you look at the original problem it calls for "a reflection about the x-axis" which basically means the function gets "flipped" using the x-axis as a mirror (I can try drawing it)
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to accomplish this we just need to multiply the entire function by -1 y = (1/4)^x becomes y = -(1/4)^x
then the second part, dilating by 2, we just multiply the entire function by 2 so the end result is y = -2(1/4)^x
now, to draw this, we want to 1) draw the mirror image of the original function across the x-axis and 2) dilate by 2 (make the curved part a bit steeper)
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so to reflect across the y-axis we multiply x (just the x part) by -1 dilation of 1/2 --> multiply the entire function by 1/2 so applying these two operations to y = 4^x what do you think we get?
y = 4^x*(-1)
1. multiply the x by -1 ---> y = 4^(-x) 2. multiply the entire function by 1/2 ---> y = (1/2) * 4^(-x) --> end result
ohh ok
so if you just want to perform an operation on x it's a good idea to separate x into parentheses to keep it separate from the whole function
anyway to graph this just flip the function across the y-axis, then to dilate by 1/2 we make it less steep
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still there?
yes sorry im here
but got that part
ah well in that case you just have to pick two things to do to the graph so, like, you can translate up 3 and reflect across the x-axis (just an example), remember how to do that?
can you tell me one more time?
|dw:1542681027206:dw| would recommend studying this chart on your own time but translating up 3 ---> add 3 to the entire function reflect across x-axis --> multiply the entire function by -1
Ugh this is confusing lmao
im sorry im literally just not in the mood for math but im trying to understand it loll
> if we want to reflect across the x-axis, multiply the function by -1 so y = 2 * 3^x ---> becomes y = -2 * 3^x > if we want to translate a function up 3 units we add 3 to the function so y = -2 * 3^x ---> becomes y = -2 * 3^x + 3 as the end result of applying both transformations
then to graph you would just reflect the function across the x-axis (pretend the x-axis is a mirror and draw what the mirror image would be) then move all the points on the graph 3 units up
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Got it, how about a and b?
the rules for these transformations have to be studied/memorized a) is asking for the function we created y = -2 * 3^x + 3 b) is asking to graph the function we created (see the purple line)
okay thank you voca! illmake sure to study them
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