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Mathematics 17 Online
kaylak:

calc help @vocaloid

kaylak:

5 questions give me a sec to upload them

kaylak:

well 6

kaylak:

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kaylak:

false?

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kaylak:

find the derivative and plug in 3?

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Vocaloid:

Acceleration is the second derivative so you would plug in t = 3 to the second derivative

kaylak:

maybe not because the derivative is 6t-5 and that would be 13 and that's not an answer

kaylak:

ah okay

Vocaloid:

Velocity is the first derivative of distance so for that parabola velocity question you would just see if the slope across that interval is neg. or not

kaylak:

I get 6 so multiply 3 and get 18?

Vocaloid:

First derivative = 6t - 5 Second derivative = 6 There’s no t anymore so just 6

kaylak:

okay and the velocity question true then?

Vocaloid:

Yes

kaylak:

is the limit question correct

kaylak:

These last 3 and I'm done

Vocaloid:

Yes

Vocaloid:

For the ladder one you have to take the implicit derivative of the Pythagorean theorem wrt t

Vocaloid:

Same thing with the volume sphere problem, differentiate both sides wrt t

kaylak:

I'm thinking a but maybe it's d hold on

kaylak:

6 is false because the function is not continuous

kaylak:

the ladder is a?

kaylak:

5 I feel like I have in my notes somewhere let me see

Vocaloid:

x^2 + y^2 = 6^2 derivative wrt 2x(dx/dt) + 2y(dy/ty) = 0 at 45 degrees each side is 6/sqrt(2) you are given dx/dt = 0.5 so 0.5*2*6/sqrt(2) + [2*6/sqrt(2)](dy/dt) = 0 solving for dy/dt should give you the speed of the top of the ladder falling down

kaylak:

b for 5 ?

Vocaloid:

agree w/ your solutions for 5+6 still working on the solution for 4

Vocaloid:

solving for 0.5*2*6/sqrt(2) + [2*6/sqrt(2)](dy/dt) = 0 gives dy/dt = -0.5 m/s (or 0.5 m/s downward)

kaylak:

so d?

Vocaloid:

yes

kaylak:

so all the other questions are correct?

Vocaloid:

yes

kaylak:

100% ty happy Thanksgiving!

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